straight ruler

A. Straight line point painting mode: That is, do not completely fill all the pixels to draw a straight line, but in the form of a point painting, spaced to draw a lineFirst enable PIP mode:Glenable (gl_line_stipple);Then customize to create your own PIP modeGllinestipple (gllint factor,glushort pattern);Where the first parameter factor is a multiplication factor, the second parameter pattern is a custom PI

This question was also asked by others. I have been thinking about it for some time and hope to get a better method. The problem is that there are some discrete points which are to be merged into a curve in the coordinate system. One of them looks like a straight line, now, the starting and ending coordinates of this line are required, and the equation of this line is obtained. for example: We can see with the naked eye that the labeled section

The importance of general equation in computer field commonly used linear equation has the general type Point oblique intercept type oblique intercept type two point type and so on. In addition to the general equation, they either cannot support straight lines in all cases (such as perpendicular or parallel to the axis), or they cannot support points in all cases (such as equal x coordinates or equal y coordinates). Therefore, the general equation is

Test instructions: give you a straight line and a number of circles, to find the length of the circle and the line is the proportion of the whole lineProblem-solving ideas: The ratio of the circle to the straight line is calculated by the method of determining the score point.First step: (Determine whether the projection is in the x-axis or y-axis)(1) When the line line.s (x, y), line.e (x, y) line.s.x and

C # version /***** Distance from a point to a straight line *** * The Linear Equations of points (x1, Y1) and points (X2, Y2) are: Kx-y + (x2y1-x1y2)/(x2-x1) = 0* Set the straight line slope to k = (y2-y1)/(x2-x1), c = (x2y1-x1y2)/(x2-x1)* The distance from point P (x0, y0) to the straight line AX + by + c = 0de is: D = | ax0 + by0 + c |/SQRT (A * A + B * B)* The

Given n straight lines, find out which lines can be seen from top down Bare questions in semi-planialization First, sort all straight lines by slope and import them to the stack in sequence. If the intersection of a straight line and stack top is on the left of the intersection of the stack top line and the next line on the stack top, the stack top is deleted. If

Problem description There are n straight lines on the plane, and there are no three-line common points. Ask how many different kinds of intersection points are there for these straight lines. For example, if n = 2, the number of possible intersections is 0 (parallel) or 1 (non-parallel ). Input The input data contains multiple test instances. Each test instance occupies one row and each row contains a posit

ensure that the details are not lost, the edge detected by the low threshold is more abundant, but many edges are not of our concern. Finally, a search algorithm is used to retain the overlapping lines between the low threshold and the high threshold, and delete other lines. In this article, we will not further describe the principle of the image processing algorithm. Next, we use the canny function in opencv to detect the image edge. 1 int main() 2 { 3 Mat I=imread("../cat.png"); 4

Label: style blog HTTP color Io OS AR for SP Question: There are N points on the plane. Find a straight line so that all points are on the same side of the straight line. And find the minimum value of the distance between these points and the straight line. Analysis: As long as the straight line does not pass through t

This article mainly introduces php's method of drawing a straight line, which involves the use of the imageline method in the GD Library. if you need it, refer to the example below to describe php's method of drawing a straight line. Share it with you for your reference. The specific implementation method is as follows: The code is as follows: // 1. create a canvas$ Im = imagecreatetruecolor (300,200);

http://poj.org/problem?id=3067Japan Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 23602 Accepted: 6369 DescriptionJapan plans to welcome the ACM ICPC World Finals and a lot of roads must is built for the venue. Japan is Tall island with N cities on the East coast and M cities on the West coast (M InputThe input file starts with t-the number of test cases. Each test case is starts with three numbers–n, M, K. Each of the

JS drawing idea through the brain, feel a little meaning, so practice a. JS drawing for a series of articles, this is the point, line and polygonFirst look at the sample: http://www.zhaojz.com.cn/demo/draw5.htmlOne, pointHere's the point we use the span tag to represent//strokes, parameters are a bit of size, color, point coordinates and labels; obviously the opts parameter is an objectfunctionDrawpoint (opts) {document.write (" Display:inline-block; Width: "+opts.pw+" PX;Height:"+opts.ph+" PX;B

Keywords: space geometryUse: There will always be a place to use it.Article type: C + + function display@Author: V_shawn@Date: 2016-11-19@Lab: [Email protected]For two straight lines within a space A, I assume they must not be parallel or intersect. If it is known that a on two points A1, A2,b on the two points B1, B2, then it is easy to get two straight lines of the equation.The function can then be called

Transferred from: http://jingyan.baidu.com/article/9113f81b0192e72b3214c709.html?st=2os=0bd_page_type=1net_ Type=1When we need to complete the decomposition of physical forces in the CAD, we need to draw axes and other lines with arrows, but the cad inside is not with the arrow straight line, the following will be described in detail how to skillfully complete the drawing of the straight arrow in the CAD.To

Title: Given n points on a 2D plane, find the maximum number of points that lie on the same straight line.Analysis: Fixed a point, traversing the remaining points, the period with a HashMap record two points slope and the number of slopes, the local maximum value, and then fixed another point, traversing the rest, ..., that is, two loops, the inner loop to find the local maximum value, the outer loop to update the global maximum value. Need to note: 1

7 relationship between the position of a straight line and a plane IResolution conditions for positional relationships: Set line L: With plane π: Ax + By + Cz + D = 0 Then, the intersection of L and π is unique A (+ X) + B (+ Y) + C (+ Z) = 0 The substring has the intersection of L and π L ∥ π L on π, there are an infinite number of t numbers in the "struct" to make A (+ tX) + B (+ tY) + C (+ tZ) + D = 0 Inference: L ∥ π, but L is not on π II

line increases (or decreases) by 1 pixel in the X direction, its Y direction can only increase (or decrease) 1 or 0, which depends on the distance between the actual line and the nearest grating mesh point. The maximum error of this distance is 0.5. With a perceptual knowledge, we can calculate the amount of changes in the Y direction in the world of mathematics. Bresenham's mathematical implementation: (in order to understand the following content, some basic mathematical concepts may be requi

For more information about the algorithm used to draw a straight line on a In-Place graph, see http://free.pages.at/easyfilter/bresenham.html. However, unlike creating a straight line on the in-place graph, you need to determine the grids through which a straight line goes. Assume that there are P0 and P1 points, and the position is as follows: We can easily o

From: http://blog.csdn.net/byxdaz/archive/2009/12/01/4912136.aspx Detection Line: cvhoughlines, cvhoughlines2 Check circle: cvhoughcircles Check rectangle: there is no corresponding function in opencv. The following code can detect the rectangle by first finding a straight line and then finding the four lines parallel to the vertical line. Check line code: /* This is a standalone program. Pass an image name as a first parameter of the program. Switc

Calculate the symmetric point M (x1, Y1) of the linear AX + bx + c = 0 by P (x0, y0). The following conditions are met: (1) The point of a line segment PM is on a straight line. (2) vertical between PM and straight line /* Vertices on straight lines */PointSymmetricalpoint(Point P, line L) {point S; double TMP = L. A * L. A + L. B * L. b; S. X = (L. B * L. B