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Android Nine Sudoku Programming code _android

This article describes the design code for the Nine program. A Related introduction (i) Effect display 1. The effect of the program just run: 2. Click on the page to select and slide the screen 3. Select the display after the password (b) Functional Introduction 1. After clicking on a circle, add a small circle in the center of the circle.2. The page slide appears with a following line.3. When you slide to another circle, a straight line is generated that connects.4. When the number

Analysis of Sudoku background image cutting with wide and high adaptive nine

A number of optimizations were made on the basis of the original Sudoku nine-and-eight background-map requests to reduce network costs. In fact, this is just some simple tips, in the cut diagram will be more stringent 1px asymmetry will be problematic, please pay attention to the following examples of cutting analysis. RAR:module.zip Production Instructions : Picture Cutting analysis The emphasis is on using a locally transparent background imag

Nine Sudoku controls based on. NET CompactFramework

On the internet often see someone asked Windows Mobile under the nine Sudoku control practices, I have also many times on the internet search, but found most of the C + + version, so germination of their own to write a thought, first on the picture. When selected. The effect of the selection is actually the alternating results of two pictures, because only for the 240x320 this style, so it may be written in many places, the following to some o

Sudoku Detectors: Imperial Engineering C + + jobs

(!Onceflag) { return false; } } } for(intj=0; j9; J + +) {vectorint>colnumbers; Extract_col (input,j,colnumbers); for(intm=1;mTen; m++) { BOOLonceflag=once (m,colnumbers); if(!Onceflag) { return false; } } } for(intp=0; p9; p=p+3) for(intq=0; q9; q=q+3) {vectorint>subsquarenumbers; Extract_subsquare (input,p,q,subsquarenumbers); for(intm=1;mTen; m++) { BOOLonceflag=once (m,subsqu

Android Mini-game----Sudoku (ii)

screen draw background Initgameview (canvas, paint); NBSP ; //Redraw Surfaceview fill new data Inflatenewnum (c Anvas,paint); }CATCH (Exception e) { e.printstacktrace (); N Bsp }finally{ if (canvas! = null) NBS P //End lock drawing and submit changes. surfaceholder.unlockcanvasandpost (canvas); //unlock canvas, update } } } nbsp; it is best to use synchronous locks, and to use try Catch finally for exception trapping. private void

Python implements a Sudoku algorithm instance

In this paper, we describe the method of Python's implementation of Sudoku algorithm. Share to everyone for your reference. Specific as follows: #-*-Coding:utf-8-*-"Created on 2012-10-5@author:administrator" from collections import Defaultdictimport Itertool SA = [[0, 7, 0, 0, 0, 0, 0, 0, 0], #0 [5, 0, 3, 0, 0, 6, 0, 0, 0], #1 [0, 6, 2, 0, 8, 0, 7, 0, 0], #2 # [0, 0, 0 , 3, 0, 2, 0, 5, 0], #3 [0, 0, 4, 0, 1, 0, 3, 0, 0], #4 [0, 2, 0, 9, 0, 5, 0, 0,

Solving sudoku in C Language

I usually like to play the sudoku game. I suddenly wanted to use a program to automatically solve the problem yesterday. The idea is to trace back and keep testing. The program code is as follows: 1 # include 23 /*4 {, 1 },5 {, 6 },6 {9, 0, 0 },7 {1, 2, 5, 0, 6, 0, 3, 4, 7 },8 {, 6, 0, 0, 9, 8, 5 },9 {, 9, 0, 2 },10 {, 0, 0, 4 },11 {, 9 },12 {6, 4, 0 }};13 */1415 int data [9] [9] = {16 {, 0 },17 {, 7 },18 {, 0 },19 {5, 0, 0, 0, 0, 0, 0 },20 {, 0 },21

Sudoku Design (2)

Today the idea is determined, roughly for the following structure:1. Define the data in the game and initialize the lattice data.2. Define touch events.In the view class, overwrite the Ontouchevent (Motionevent event) method.3, inherit the dialog class, customize a dialog.4, do the above preparation, we can re-view class, the game layout, and to operate.5. Call the MyView object in the main class.Estimated time: 5 days, each day to complete the encoding of a class.Today's content:The class of th

Sudoku ~~~~~~ Only remember the current eye pain

{ - to if(i==Bayi) + { -n=Bayi; the return; * } $ inty=i/9, x=i%9;Panax Notoginseng if(a[y][x]==0) - { the for(intI=1; i9; i++) + { A if(check (y,x,i)) the { +a[y][x]=i; -i++; $ DFS (); $i--; - if(n==Bayi) - { theI=Bayi; - Break;Wuyi } thea[y][x]=0; - } Wu if(

Sudoku Design (4)

canvas.drawrect (0, 0, getwidth (), getheight (), Paint );//define the Brush object and draw the grid line paint Darkpaint = new paint ();d Arkpaint.setcolor (Getresources (). GetColor (R.color.shudu_dark)); Paint Hilitepaint = new paint (); Hilitepaint.setcolor (Getresources (). GetColor (R.color.shudu_hilite)); Paint Lightpaint = new paint (); Lightpaint.setcolor (Getresources (). GetColor (R.color.shudu_light));//Draw nine lattice for (int i = 0 ; iCall the MyView object in the main class.Pa

poj2676 Sudoku (DFS)

} + } A return false; the } + intMain () { - intT, I, J; $ CharC; $scanf"%d", t); - while(t--){ - bk.clear (); thememset (Row_f,0,sizeof(Row_f)); -memset (Col_f,0,sizeof(Col_f));Wuyimemset (Block_f,0,sizeof(Block_f)); the for(i =0; I 9; ++i) { - for(j =0; J 9; ++j) { WuCIN >>C; -G[I][J] = C-'0'; About if(!G[i][j]) $ Bk.push_back (Blank (i, j)); - Else -Setnum (i, J, G[i][j],1); - } A } +

Bzoj 3109: [cqoi2013] New Sudoku

); theha[x][i]=0; -li[y][i]=0; Wuxi[(x1)/3*3+ (Y1)/3][i]=0; - } About } $ intMain () - { - for(intI=1; i9; i++) - { A for(intj=1;j9; j + +) + if(j%3) the { -scanf"%s", ch); $ if(ch[0]=='') thebh[i][j+1]=1; the Else thebh[i][j+1]=0; the } - if(i%3) in for(intj=1; j9; j + +) the { thescanf"%s", ch); About if(ch[0]=='^') thebl[i+1][j]=1; the Else t

Leetcode Valid Sudoku

translation数独板被部分填充,空格部分用‘.‘来填充。一个部分填充的数组是否有效只需要看其填充的部分即可。OriginalCodeThe word was inscribed for a while, wrong ... Because the input is too lazy to make, directly read someone else's writing ...classSolution { Public:inta[9];BOOLIsvalidsudoku ( vectorvectorchar>> Board) {memsetA0,sizeof(a)); for(intI=0, j=0, row=0, col=0;i9; ++j,j==9? ++i,j=0, row=col=0:0) {if(board[i][j]!='. ') {if((1 -) Row)return false;Elserow|=1 -;if((1 -) a[i/3*3+j/3])return false;Elsea[i/3*3+j/3]|=1 -;

POJ 2676/2918 Sudoku (DFS)

Idea: Record the number of each row in each column that has already appeared. Data is relatively weakIn addition POJ 3074 3076 must use pruning strategies. But to achieve more trouble, or after the DLX to do it againaccepted160k0ms#include POJ 2676/2918 Sudoku (DFS)

Dfs/poj 2676 Sudoku

,0,sizeof(used)); $ for(intI=1; i9; i++) - { - Charstr[Ten]; -scanf"%s", str); A for(intj=0;j9; j + +) + { thea[i][j+1]=str[j]-'0'; - if(a[i][j+1]!=0) $ { thev[i][j+1]=1; the intx=a[i][j+1]; therow[i][x]=1; thecol[j+1][x]=1; -used[(I-1)/3+1[(j+1-1)/3+1][x]=1; in } the } the } About /* the for (int i=1;i the { the for (int j=1;j + printf ("\ n"); -

A Sudoku Verifier

Publicclasssudokuverifier{privatebooleanis1to9row (int[][]a,int R) {int[]pos=newint[9];for (inti=0;iA Sudoku Verifier

POJ 2676 Sudoku

#include #include #include #include using namespace STD;intmp[Ten][Ten],row[Ten][Ten],col[Ten][Ten],grid[Ten][Ten];intGetintXintY) {if(x>=1x3) {if(y>=1y3)return 1;Else if(y>=4y6)return 4;Else return 7; }Else if(46) {if(y>=1y3)return 2;Else if(y>=4y6)return 5;Else return 8; }Else{if(y>=1y3)return 3;Else if(y>=4y6)return 6;Else return 9; }}intDfsintXintY) {if(x==Ten)return 1;intflag=0Iif(Mp[x][y]) {if(y==9) Flag=dfs (x+1,1);ElseFlag=dfs (x,y+1);if(flag)return 1;Else return 0; }Else{ for(i=1;

leetcode#37 Sudoku Solver

Original title AddressBacktracking, nothing to say.1 BOOLrow[9][9];2 BOOLcol[9][9];3 BOOLgrid[9][9];4 BOOLmark[9][9];5 6 BOOLSolve (vectorChar> > board,intRintc) {7 if(r = =9)8 return true;9 if(Mark[r][c])Ten returnSolve (board, R + (c +1) /9, (c +1) %9); One for(inti =0; I 9; i++) { A if(!row[r][i] !col[c][i] !grid[(R/3) *3+ C/3][i]) { -Row[r][i] = Col[c][i] = grid[(R/3) *3+ C/3][i] =true; -BOARD[R][C] = i +'1'; the if(Solve (board, R + (c +1) /9, (c +1) %9)) -

Android games-Sudoku (2)

Android games-Sudoku (2)> First, create a View class --> inherit SurfaceView and implement SurfaceHolder. callback interface --> SurfaceView. getHolder () obtains the SurfaceHolder object --> SurfaceHolder. addCallback (callback) adds a callback function --> SurfaceHolder. lockCanvas () Get the Canvas object and lock the Canvas --> Canvas painting --> SurfaceHolder. unlockCanvasAndPost (Canvas canvas) ends locking and submits changes to display the im

Poj 3076 Sudoku (dancing links)

Question: 16*16. Train of Thought Analysis: Needless to say, it is useless. This is to say that the dancing links line is based on Enter 1 in the first column of the first row. Enter 2 in the second column of the first row. ...... Enter 15 in column 15th of the first row. Enter 1 in the second column of the first row. ...... The second line .... Column textiles are Put 1 In the first row and 2 in the first row ,.. Put 16th rows in 16... Put 1 In the first column .. Put 2 In th

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