: first, only to find the feasible side, the second is to take the search process to the X -side point all down, in order to make subsequent changes1 #defineINF 0x3f3f3f3f2 intDfsintx)3 {4 inty,tmp;5VISX[X] =1;6 for(y =1; Y )7 {8 if(!Visy[y])9 {TenTMP = Lx[x] + ly[y]-W[x][y]; One if(TMP = =0) A { -Visy[y] =1; - if(linker[y]==-1||DFS (Linker[y])) the { -Linker[y] =x; - return 1; -
- - intGap = Ex_girl[girl] + ex_boy[boy]-Love[girl][boy]; in - if(Gap = =0) {//If the requirements are met toVis_boy[boy] =true; + if(Match[boy] = =-1|| DFS (Match[boy])) {//find a guy who doesn't have a match, or the boy's sister can find someone else . -Match[boy] =girl; the return true; * } $}Else {Panax NotoginsengSlack[boy] = min (Slack[boy], GAP);//s
Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--> /* PKU 2195 kmAlgorithmMinimum weighted binary matching */ # Include Stdio. h > # Include String . H > # Include Math. h > # Define Maxcompute 101 Int HX [Max], MX [Max], Hy [Max], my [Max]; Char Map [Max] [Max]; Int Usedx [Max], usedy [Max], Match [Max], W [Max] [Max], n, m; /// /Match [] stores the matching information of the right vertex. W [] [] stores the weight
This is a code big problem. First read the wrong test instructions, and then understand the direct look of the kind of adjacent, and then do not want to pass a long time!!!Separate the diagram of the different unicom, and then pre-preprocess the formation of the adjacent diagram after the state, and then according to 01 to determine which is the need to change the state, and then build a diagram, using the binary diagram km algorithm to match the optimal scheme. Then find each group of replaceme
chips to FPGA by the system clock.
Figure 1.3 FPGA data input model
The input delay is the delay time from the external device to the FPGA input port. This includes the latency from the clock source to the FPGA, the latency from the external device, the TCO of data transmission from the external device, and the cabling latency on the PCB. As shown in Figure 1.4, It is the timing of the external device and FPGA interface.
Figure 1.4 timing of external devices and FPGA Interfaces1. maximum inp
] expands, and edge (I, j) does not belong to an equal subgraph.
I is in the staggered tree, j is not in the staggered tree, and edge (I, j) may be added to an equal subgraph.
To ensure that a [I] + B [j]> = w (I, j) is always valid, and at least one edge is added to an equal subgraph, d = min {a [I] + B [j]-w (I, j)}, I is in the staggered tree, j is not in the staggered tree
Time Complexity:You need to find the O (n) Increment path. You need to modify the O (n) Increment path at most. During
:
@after @hipchat('token', 'room', 'Envoy', "{$task} ran in the {$env} environment.")@endafter4.2 Slack
In addition to HipChat, Envoy also supports sending notifications to Slack. @ Slack command receives a Slack hook URL, channel name, and the message you want to send to the channel:
@after @
reduced to AD and BC, must be intersect?It turns out that this proposition is not necessarily, but it can be found that when it can be reduced to AD and BC, AD and BC must be disjoint. Doing so will result in AD+BC > AC+BD.So as long as can reduce the side of the right and, must be able to ensure that disjoint. Then the final state becomes the edge right and the smallest state, which is the minimum match. Can be done using the KM algorithm.Appears to be a data problem and cannot be processed us
HDU_2426
This topic is a perfect match for the maximum right. we need to pay attention to two points: 1. Deal with the negative edge. 2. Note that N and M are not necessarily equal.
For the processing of the first point, I have seen two ways to deal with: ① all the sides are initialized to the negative side, so that as the N-M between all the edge is to exist to match, if the number of matches with the positive edge weight is N, there is a solution. Otherwise, no solution is available. ② The e
KM algorithm of nudity. O (n^4) template , in fact, in the augmented path is still redundant, you can use BFS optimization to O (n^3).1#include 2#include 3#include 4#include 5#include 6#include 7 using namespacestd;8 Const intmaxn= -+5;9 Const intinf=0x7fffffff;Ten intn,m; One intW[MAXN][MAXN]; A intX[MAXN],Y[MAXN]; - intVISX[MAXN],VISY[MAXN],SLACK[MAXN]; - intLK[MAXN]; the - intDfsintu) - { -visx[u]=1; + for(intI=1; i) - { + intwt=x
As mentioned above, high-precision timer is implemented through hrtimer. hrtimer uses a programmable timer to present it. It does not occupy CPU while waiting.
In the user State, when we call usleep, the thread will use hrtimer to wait for CPU usage during kernel state execution.
How to use it in kernel?
Let's take a look at the ep_poll function in eventpoll. C:
static int ep_poll(struct eventpoll *ep, struct epoll_event __user *events, int maxevents, long timeout){int res = 0, eavail, timed_
valid when building the message:
@after @hipchat (' token ', ' guest ', ' Envoy ', ' {$task} ran in the {$env} environment. ') @endafter
4.2 Slack
In addition to Hipchat, Envoy also supports sending notifications to Slack. The @slack instruction receives a slack hook URL, a channel name, and the message you want
Symphony orchestra mode, it's also a good model to compare with the theatrical model, but the symphony pattern always gives people a messy feeling, with a lot of guys and a whole range of things that might be too busy during the final delivery of the program, because we all might write different code, and then, There is no chat and walk during the performance, meaning that we do not communicate in the proc
play this song, but not that song. He has no basic skills. Therefore, every piece of music has to be practiced for a long time. For students with basic skillsWithin his level, you put the music on the piano frame and he can see it. In other words, it is called the ability to recognize music, which is actually a basic skill.
I am training in the direction of the philphia symphony orchestra. What is the philphia Sy
"Team and process". Development has been carried out by more than half,It is also interesting to come up with a reflection.First of all, we have their own division of labor, and rely on each other to work together to complete the task, so as a team, we are qualified, and then the software team Model,To reflect on it, we should belong to the amateur theater model (amateur Theater Team). For example, in this team-work project, we started with the topic of the subway,Then everyone chooses differen
The content source of this page is from Internet, which doesn't represent Alibaba Cloud's opinion;
products and services mentioned on that page don't have any relationship with Alibaba Cloud. If the
content of the page makes you feel confusing, please write us an email, we will handle the problem
within 5 days after receiving your email.
If you find any instances of plagiarism from the community, please send an email to:
info-contact@alibabacloud.com
and provide relevant evidence. A staff member will contact you within 5 working days.