tandberg educational

Php implements simulated login to the Founder's educational administration system to capture course schedules This article mainly introduces how php can simulate login to the Founder's educational administration system to capture information about the course schedule. For more information, see Course lattice and super curriculum are two applications that must be familiar to college students. They can use th

Topic Link: Click to open the linkTest instructions: A n*m matrix, inside the lattice except ' Z ' is '. ', ask how many Z-shaped patterns.Idea: Because N and M are large, even n^3 complexity will time out. If according to the simplest method, we can deal with the prefix and, processing out a lattice left l[i][j], right r[i][j], oblique to the left Lr[i][j] attached z to where, so we use n^2 complexity to enumerate each lattice as the upper right corner of the Z-shape, Take min (L[i] [j], Lr[i][

Qiangzhi educational administration system kills Getshell (Elevation of Privilege server Intranet penetration) File: unzip GL \ jcxx \ savetofile. asp Use exp: Directly use exp.html to upload any file. The server has almost the sa permission, and the elevation of permission is complete. Configuration file: Conn \ connstring. asp Server Self-carried Serv-U Exec> Elevation of Privilege. As you can see, the servers are all horse cells, and there

; A if(G[u][i].second) +VIS[V] =true; the Dfs (v, u); - } $ } the the intMain () the { the intN, M, U, V, art, S, E, Heheda =1; -scanf"%d%d", n, m); in init (); the for(inti =0; I ) { thescanf" %d%d%d", u, v, art); About Add (U, V, art); the Add (V, U, art); the if(Art = =1) theHeheda =0; + } -scanf"%d%d", s, e); the if(Heheda) {Bayiprintf"no\n"); the return 0; the } -Tarjan (1, -1); -End_point =Block[e]; the for(intU =1; U ) { the

times polynomial n is x, where n is directly replaced by x, the result is the final results; because we know the number of the final polynomial (key)Implementation details: The internal factorial first preprocessing, but the inside is not a continuous factorial, need to use the multiplication inverse, that is, the Euler function deduction formula; As for the positive and negative of the denominator, it can be judged after the inverse (which is not proved)Time complexity: for n less than MAXN, i

DescriptionOne company's IT City decided to create a group of innovative developments consisting from 5 to 7 people and hire New employees for it. After placing a advertisment the company received N resumes. Now the HR department have to evaluate each possible group composition and select one of the them. Your Task is to count the number of variants of the group composition to evaluate.InputThe only line of the input contains one integer n (7≤ n ≤777)-the number of potential EMP Loyees that

DescriptionConsider the infinite sequence of integers: 1, 1, 2, 1, 2, 3, 1, 2, 3, 4, 1, 2, 3, 4, 5 .... The sequence is built in the following Way:at first the number 1 was written out and then the numbers from 1 to 2 , then the numbers from 1 to 3, then the numbers from 1 to 4 and so on . Note that the sequence contains numbers, not digits. For example number Ten first appears in the sequence in position (the elements is numerated from one). Find the number on the n-th position of the sequenc

A-infinite SequenceTest Instructions: There is one such infinite sequence number 1,1,2,1,2,3 ... (If the maximum number is n, then there are all 1 to N of the number from 1 to n );Train of thought: test instructions only gave 1 seconds, direct simulation definitely timeout, I use two points to find the Nether1#include 2 using namespacestd;3 Long LongFLong Longx)4 {5 return(1+X) *x/2;6 }7 Long LongSearchLong Longx)8 {9 intl,r,m;TenL=0; r=1e8; One while(lR) { AM= (L+R)/2; - if

Into the main interface, see so long menu, I felt a hint of malice, and then I want to use this system to query my public elective class, I put the menu to the end, found that I need to play five letters, I think it's OK, just follow the fight.So I clicked on the input field and was ready to start typing. But what?The menu unexpectedly jumps to the top, which makes me have to pull the long menu to the bottom again, and then remember the five letters. At the time, I didn't even think of it. These

]; inttot; voidinit () {memset (ch,0,sizeof(CH)); memset (SZ,0,sizeof(SZ)); Tot=2; } voidInsertintx) {intu=1; sz[u]++; for(intI= -; i>=0; i--) { intp = (x>>i) 1; if(!ch[u][p]) ch[u][p]=tot++; U=CH[U][P]; sz[u]++; } } int Get(intXinty) {intu=1; Long LongAns =0; for(intI= -; i>=0; i--) { intp = (x>>i) 1^1; intQ = (y>>i) 1; if(q==0) ans+=sz[ch[u][p]],u=ch[u][p^1]; Elseu=Ch[u][p]; if(u==1)returnans; } returnans+Sz[u]; }}t;intMain () {t.init (); i

Preparation materials for the exam:1, i xxx original;2, the original diploma;3, the applicant for the level of the above also need to provide a starting degree certificate in the "Learning Letter Network" Query page copy of 1 or academic certification report original.Registration process:1, choose the major: According to the work background, interests, goals, the actual level of choice of the appropriate professional2, registration: On-Site Confirmation registration information3. Entrance Examin

changes.Sample Test (s) InputAabcOutputAbbaInputAabcdOutputAbcba1#include 2#include 3#include 4#include 5#include 6#include string>7#include 8#include 9#include Ten using namespacestd; OnetypedefLong Longll; Atypedef unsignedLong Longull; - Const intmaxn=2e5+5; - intcnt[ -]; the intMain () - { - CharS[MAXN]; - intflag=-1; +scanf"%s", s); -cnt[ -]=0; + intlen=strlen (s); A for(intI=0; i'a']++; at for(intI=0;i -; i++) - { - if(cnt[i]1) - for(intj= -;

It's my idea to see this question, but it's definitely about the average, but then I don't know what to do.After reading the great God's coefficient, the original discovery is so simple, but I do not know why must be mean and average plus 1, rather than mean and average minus 1;Okay, here's the code for the Great God:#include Codeforce---educational codeforces Round 3 Load balancing The Chase

calculate the number of days per year. If it is a multiple of 7 and the same flat leap is the result.1#include 2#include string>3#include 4#include 5#include 6#include 7 using namespacestd;8 intDay_weak (intYearintMonthintDay )9 {Ten if(month==1|| month==2) One { AMonth + = A; ---Year ; - } the intWeek =-1; -week= (day+2*month+3* (month+1)/5+year+year/4-year/ -+year/ -)%7+1; - returnWeek//Output-1 is error - } + intMain () - { + inta,b,c; A inti; atCin>>A; - for

DescriptionLittle Joty have got a task to do. She has a line of n tiles indexed from 1 to n. She has to paint them in a strange pattern. An unpainted tile should be painted Red if it's index is divisible by A and a unpainted tile should be paint Ed Blue if it ' s index is divisible byb. The tile with the number divisible by a and b can be either painted Red or Blue. After her painting was done, she'll get p Chocolates for each tile that's painted Red and q Ch Ocolates for each tile, which

DescriptionAfter a probationary period in the game development Company's IT City Petya is included in a group of the programmers th At develops a new turn-based strategy game resembling the well known "Heroes of Might Magic". A part of the game was turn-based fights of big squadrons of enemies on infinite fields where every cell was in form of a He Xagon.Some of magic Effects is able to affect several field cells at once, cells, is situated not farther than n cells away from the cell in

''; - } to //A , B is equal in length (L1 = L2) + for(inti =0; i ) { - if(*s1 //the value pointed to by the pointer the return ''; * } $ Else if(*s1 > *S2) {Panax Notoginseng return '>'; - } thes1++;//The pointer moves right one +s2++; A } the return '='; + } - $ $ intMain () - { - #ifndef Online_judge theFreopen ("In.txt","R", stdin); - #endif //Online_judgeWuyi the while(SCANF ("%s%s", A, b)! =EOF) { -pri

'; Exit ();} Construct data at login $data = array (' __viewstate ' = + $vs [1],//__viewstate ' TextBox1 ' = ' username ',//Modify the user here ' TeXtBox2 ' + ' password ',//and password ' RadioButtonList1 ' + ' student ',//and Identity type ' Button1 ' = ' login '); $html = $http->post (log In_url, $data);p reg_match ('/language=\ ' javascript\ ' >alert\ (\ ' (. +?) \ ' \);/', $html, $err);//Check for errors, display an error message if there is an error, and then exit if (count ($err) = =

#include #include#includestring.h>#include#definell Long Long#defineRep (i,j,k) for (Long long i=j;i#definePer (i,j,k) for (Long long i=j;i>=k;i--)using namespacestd;Const intN = 2e5+5; ll H[n];intMain () {Long Longn,k; while(~SCANF ("%lld%lld",n,k)) {memset (H,0,sizeof(h)); LL Maxx=0; ll X; LL Minn=2e5+5; for(intI=1; i) {scanf ("%lld",x); H[X]++; Minn=min (minn,x); Maxx=Max (maxx,x); } ll sum=0; Per (I,maxx-1, Minn) h[i]=h[i+1]+H[i]; intCnt=0;//cout//Rep (I,minn,maxx) {//printf ("%d", H[

The academic administration system of Zhengfang University is a course selection management system for students. Currently, many colleges and universities use this educational administration system. A high-risk vulnerability has recently been detected in the system. Attackers can exploit this vulnerability to easily obtain website webshell permissions. The following describes how to fix the vulnerability: Vulnerability Type: Upload Vulnerability Vul