tangent games

Test instructions: The room is a convex polygon, to lay in the inside two radius r of the round carpet, can overlap, now requires the laying of where, so that the carpet occupies the largest floor area.Solution: To make the circular carpet occupies the largest area, the round carpet must be tangent to the edge, so as to make as far as possible do not overlap. So we push all the edges inward R, so the polygon is formed, we know that the center of the t

I will give you a detailed analysis of the Illustrator software and share with you the tutorials on creating beautiful tangent circle marks.Tutorial sharing:The following is another simple analysis method:1. The radius of a small circle is half of the big circle.2. Use a linear tool to pull the length between two circles.3. Rotate a green line to determine the center4. Draw a circle and rotate it again.Ps: note that the stroke width may affect the acc

AOP- oriented tangent programming in the daily development, the business logic is defined under a special service package, and the implementation is defined in the impl package under the service package.Service Interfaces to Ixxxservice form, and service realization is xxxservice, this is the protocol designsteps:1.e:\users\workspaces\kmwalletapp\spring\aop\test\helloworldservice.java Inheritance (implements) XX Interface2.e:\users\workspaces\kmwall

Find public tangent The public tangent is a simple line tangent to the polygon at the same time, and both polygon are located on the same side of the line. In other words, a public tangent is a line that is tangent to both polygon. An example is shown in: Two non-Interse

First, let's take a look at the picture of the problemThe problem is that when you click on the input box, the input method will be cut to the red line position, the ideal state should be in the Green line positionSo, what is the cause of it?The problem is very simple, because the Drawableleft picture is higher than the text height of the input box, and the Input method pops up when the text height is calculated, not the height of the entire input box.So, it's going to be cut from the Green Line

The Fibonacci sequence can be generated in a good way with generators, directly on the code:# 1 Control Maximum digital versiondef fib (max): x, y = 0,1while y 　　# 2 Control Iteration count version def fib (count): X,y,n = 0,1,1while N 　　"The beauty of simplicity" Fibonacci that tangent series generator python

1. Installing KINGAOP in NuGet2. Log Demo Public classTest:idynamicmetaobjectprovider {[Logaspec] Public voidTestMethod () {Console.WriteLine ("output text come on!"); Throw NewArgumentNullException ("user name could not being null"); } Publicdynamicmetaobject getmetaobject (System.Linq.Expressions.Expression parameter) {//need for AOP weaving return NewAspectweaver (parameter, This); } } Public classLogaspec:onmethodboundaryaspect { Public Override voidonentry (Met

Usering");}}Userservice.javaPackage Ml.orlion.service;import Ml.orlion.dao.userdao;import Ml.orlion.dao.impl.userdaoimpl;import Ml.orlion.model.user;public class UserService {private Userdao Userdao = new Userdaoimpl ();p ublic Userdao GetUserDao () {R Eturn Userdao;} public void Setuserdao (Userdao userdao) {This.userdao = Userdao;} public void Saveuser (user user) {this.userDAO.saveUser (user);}}Loginterceptor.javaPackage Ml.orlion.aop;public class Loginterceptor {public void before () {Syste

Userinfoservice { get; set;}//This completes the decoupling of the web layer and the BLL layer public ActionResult Index () { return View ();}} 4.controllers.xml File Configuration content:"1.0"Encoding="Utf-8"? >"Http://www.springframework.net"> Object type= "webapp.controllers.userinfocontroller,webapp "Singleton=" false " Userinfoservice "ref= "userinfoservice"/> userinfocontroller userinfoservice--> OBJECT> 5. Modify the Web. config file in the website to add the following nodes

can not use JDK the self-brought dynamic proxy, need to use to cglib do With regard to the context, here I am doing, due to the encounter of two contexts, that is generally said Rootcontext and webcontext .... In the case of returning JSON, you need to shutdownresponse, turn off the response, or you may output the JSON here and then output some content again. The rest of the content to follow up, now there are too many projects on hand, there are too many things to tidy up ~ Use a

"xsi:schemalocation= "Http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd" > BeanID= "CustomerService"class= "Com.shiyanlou.spring.aop.advice.CustomerService"> Propertyname= "Name"value= "Shiyanlou" /> Propertyname= "url"value= "Shiyanlou.com" /> Bean> BeanID= "Hijackaroundmethodbean"class= "Com.shiyanlou.spring.aop.advice.HijackAroundMethod" /> BeanID= "Customerserviceproxy"class= "Org.springframework.aop.framework

inspection without having to modify the other code.• Log-in checks wherever needed, even if new methods or classes are added. This can eliminate human error. Also know that all login check codes have been removed, and that nothing will be overlooked when we remove aspects from the build configuration.• There is a reusable aspect that can be applied and upgraded.7. Conclusion Aspect-oriented programming is a new technology that excites software developers, and it is used to look for novel modu

not the best solution. So give up module this detour.Second attempt:Custom inherits the ashx from IHttpHandler. Original: Index:ihttphandler, optimized after: Index:logincheckhandler,logincheckhandler:ihttphandler. Learn the above method of inserting into an inheritance tree in ASP. But the debug result is not to take the index of the ProcessRequest (), directly after the Logincheckhandler.processrequest () returned, the client is a blank piece. The reason: The general process of implementing I

Uibezierpath * Bezierpath = [Uibezierpath bezierPathWithRoundedRect:skinSource.bounds byroundingcorners: Uirectcornerbottomright | Uirectcornertopright Cornerradii:cgsizemake (14, 14)];Cashapelayer *masklayer = [Cashapelayer layer];Masklayer.frame = Skinsource.bounds;Masklayer.path = Bezierpath.cgpath;SkinSource.layer.mask = Masklayer; typedef ns_options (Nsuinteger, Uirectcorner) {Uirectcornertopleft = 1 Uirectcornertopright = 1 Uirectcornerbottomleft = 1 Uirectcornerbottomright = 1 Uirectcorne

:0.0];nsnumber *stoptwo = [nsnumbernumberwithfloat:1.0];nsarray *locations = [nsarrayarraywithobjects: Stopone, Stoptwo, Nil]; cagradientlayer *headerlayer = [cagradientlayerlayer];Headerlayer. colors = colors;Headerlayer. Locations = locations; cgfloat width = self viewgradualalpha Bounds Size Width + screen_width - self cellimgvtop Bounds Size Width cgfloat height=self. Viewgradualalpha . Bounds. Size. Height;Headerlayer. frame =cgrectmake(0,0, width, height);[Self. Viewgradualal

ArticleDirectory Java anti-trigonometric function arc tangent function original code precision to 0.03 seconds Original Java arctangent Function Code Precision to 0.03 seconds Http://blog.163.com/luckyjackyt@126/blog/static/1404476132010284149643/ 16:01:49 | classification: Technical article |Font SizeSubscription I recently encountered one of the biggest problems when I used the Java Road lofting software on my mobil

1. Recursive display of Fibonacci sequencesfunctionRecursion ($num) {Determine if it is less than 0if ($num return-1;}if ($num ==1) {return 0;}if ($num ==2 | | $num ==3) {return 1;}Returnrecursion ($num-1) +recursion ($num-2);}Loop displayfor ($i =1; $i $str. = ', ', recursion ($i);}$str = substr ($str, 1);Echo $str;?>2. Iterate to show Fibonacci sequencefunction Diedai ($num) {if ($num return-1;}Default first two bits is 1$arr [0] = 0;$arr [1] = 1;for ($i =2; $i $arr [$i] = $arr [$i -1]+ $arr [

Step one makes three segments (each of which acts as a radius of three circles). Open the geometry artboard and use the line segment tool to draw three lines of unequal lengths in the blank area of the artboard, labeled A, B, and C; Make three segments A, B, and C in a geometry artboard example Step two measures the length of 3 line segments. Select Line A, B, and C to perform the metric-length command, which measures the length of the 3 segments, as shown in the following figure;

Sample Example: http://www.zhaojz.com.cn/demo/draw9.html Copy Code code as follows: Draw Tangent Point round outside the dot Dot Center R radius function drawcircletangent (point, Dot, R) { Draw Auxiliary Line-start var color = ' darkred '; The color of the tangent var color2 = "#ccc"; Color of other guides DrawLine (dot, [dot[0]+9*r,dot[1]], {color:color2}); Extend the horizontal line

Currently, many tools can directly generate normalmap. Algorithm Different algorithms make the calculation of tangent and binormal a little different. Currently, most artists use 3 DSMAX most often. Using Max to generate normalmap is also a common and convenient method. However, at present, there seems to be little information about how to calculate the tangent vector when exporting normalmap from Max. The