Non-terminating decimal expansion; no exact representable decimal result-Lopper column-blog channel-csdn. Net http://blog.csdn.net/lopper/article/details/5314686
Because it is necessary to process floating-point numbers with relatively high precision, double type should be discarded, and bigdecimal type should be used for numerical processing.
There is no problem in addition, subtraction, multiplication, b
We want to modify the display format of a page's data, which requires two steps:1. In JS through $ ('. Class1. Class2 Li:eq (2) Span.value '). Text (). Trim (); A similar statement gets the contents of the data.2. Modify the data to the desired format. (eg:data=10 ==> 9+1)If we get the data value is an integer, then no problem, things will go well, as expected results.But if you take a decimal, the problem comes.What is this for?A: This is related to
The output retains the floating point with 12 decimal digits and the 12 decimal digits.
Total time limit: Ms memory limit: 65536kB
Description
Read a double-precision floating point number, retain 12 decimal places, and output this floating point number.
Input
There is only one row, one double-precision floating point number.
45: decimal to octal, 45 decimal45: decimal to octal
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Submit
Statistics
Question
Total time limit:
1000 ms
Memory limit:
65536kB
Description
Converts a decimal positive integer to octal.
Input
A row containing only one decimal integer a (0
Output
Title DescriptionThe 1234 output of the decimalOutputs the octal 1234 corresponding to its decimal numberOutputs the hexadecimal 1234 corresponding to its decimal numberInputNoOutput1234d=1234d1234o=668d1234h=4660dSample output1234d=1234d1234o=668d1234h=4660dTipsOutput the second line of "1234o=668d", 1234 is the capital letter O, not the number 0The code is as follows:#include Operation Result:OJ "
Convert a string of the double type into a pure numeric string and a c ++ code with the decimal point. double decimal point
In today's work, I encountered a string that is not double type converted into a pure word string and a number of int types that indicate the decimal point of this numeric string.
For example, "23.123" --- "23123" + 3 is relatively simple. I
Php_ keep two decimal places and round _ Keep two decimal places and do not round
php reserved Two decimal places and rounded
$num = 123213.666666;echo sprintf ("%.2f", $num);
PHP retains two decimal places and does not round
$num = 123213.666666;echo sprintf ("%.2f", substr (sprintf ("%.3f", $num), 0,-2));
ph
Note that if the result is an infinite number of decimal places, you will get an error if you do not specifyImport Java.util.scanner;import Java.math.bigdecimal;public class Main {public static void main (String args[]) {Scanner in = new Scanner (system.in); BigDecimal a = In.nextbigdecimal (); BigDecimal B = in.nextbigdecimal (); System.out.println ("Add" + a.add (b)); System.out.println ("Sub" + a.subtract (b)); System.out.println ("Mul" + a.multipl
# The user is given a decimal data, and the binary n, completes the n-ary conversion, outputs the result to the user (do not use the existing function)# User input datadecdata = Int (Input ("Enter a Decimal data:"))# binary N for user inputHex = Int (Input ("Enter a binary N:"))# Custom Data Conversion functionsdef decconversion (dec,n): # Store output Data initialization result = ' # Determine if
Method 1: Use Math.Round to calculate the number format that is returned here.float price=89.89;int itemNum=3;float totalPrice=price*itemNum;float num=(float)(Math.round(totalPrice*100)/100);//如果要求精确4位就*10000然后/10000Method 2: Return with DecimalFormat in string format. The class is fully encapsulated in decimal. Like the% number, thousand bits, decimal precision. Scientific calculation.float price=1.2;Decim
C # decimal retains the specified decimal places,
When decimal retains the specified decimal digits, the. NET method is rounding.
If the project encounters a apportioned amount, the amount in the last line = total amount-sum of the apportioned amount.
This may result in a negative number when the last part is apportion
Java float retains two decimal places or decimal placesMethod 1: Use Math.Round to calculate the number format that is returned here.float price=89.89;int itemnum=3;float Totalprice=price*itemnum;float num= (float) (Math.Round (totalprice*100)/100); If the exact 4-bit is required *10000 then/10000Method 2: Return with DecimalFormat in string format. The class is fully encapsulated in
Turn from:Java float retains two decimal places or decimal placesMethod 1: Use Math.Round to calculate the number format that is returned here.float price=89.89;int itemnum=3;float totalprice=price*itemnum;float num= (float) (Math.Round (totalprice*100)/100); /If the exact 4-bit is required *10000 then/10000Method 2: Return with DecimalFormat in string format. The class is fully encapsulated in
Today, when using two BigDecimal-type numbers for the division operation, a following exception message appears:1 java.lang.arithmeticexception:non-terminating decimal expansion; No exact representable decimal resultOn the internet to check this anomaly, found the reason: when the division by BigDecimal divide method when not evenly divisible, an infinite loop of decimals, will throw an exception: Java.lan
There's a problem.
First enter the integer part and then the whole part of the deletion, in disguise let the decimal point to the first place
In the case of a two-bit decimal, you cannot change a two-bit number if selected
Netizen Ymwcwee has corrected please refer to his code
Http://blog.csdn.net/jzz870519/archive/2010/08/08/5796876.aspx, because I always failed to reply to the code, so I opened it mys
Reference: http://database.51cto.com/art/201005/201651.htmHttp://www.lai18.com/content/1693593.htmlDirectly on the example, the following is the processing of the field cost divided by 1000, leaving two decimal placesCast (SUM (a.costs)/1000 as Decimal (32,2))The cast () function is a conversion function, which is an expression that includes the source value and the target data type separated by the AS keyw
. Net decimal retains the specified decimal places (not rounded),. netdecimal
Preface
If the project encounters a apportioned amount, the amount in the last line = total amount-sum of the apportioned amount.
This may result in a negative number when the last part is apportioned. Therefore, I wrote a method to retain the decimal digits of the specified number.
The
JQuery allows only numbers and decimal places. jquery decimal places
This example describes how jQuery allows only numbers and decimal places. We will share this with you for your reference. The details are as follows:
Convert decimal to binary:The result is 1 after 2 rounds.Write the remainder and the last 1 in descending order as the result.For example, 302302/2 = 151 + 0151/2 = 75 + 175/2 = 37 + 137/2 = 18 + 118/2 = 9 + 09/2 = 4 + 14/2 = 2 + 02/2 = 1 + 0The binary value is 100101110.
Convert binary to decimalStart from the last digit and column it as 0th, 1, 2...The number (0 or 1) of the nth digit multiplied by the Npower of 2The result is the answer.Example: 0
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