terabyte to megabyte

string section of hbufc.2. Because the heap string is a newly allocated object, you must manually delete it immediately after use. I use Delete heapbuf; to delete it, but I think it would be better if I could use the cleanupstack library provided in the Symbian system to delete it. I have no research on this aspect, so I dare not give an example here.3. The size of the heap is still worth noting. I allocated two heap strings with a length of 0 x in my program. There is no big problem. When I wa

the concurrent garbage collection (CMS) for the old generation starts when the old generation reaches 90%, and 10% of the remaining space is 5500 * 10% = 550 MB, therefore, even if all objects in the xmn (that is, the young generation has a total of 500 mb) are moved to the old generation, the space of 550 MB is sufficient, so as long as the above formula is met, there will be no promotion failed during garbage collection; Softreflrupolicymspermb is a bit useful. The official explanation is so

showing the results for in memory parsing of a 14 megabyte XML document. note that the parsing time is in seconds and the y-axis isLogarithmic. Yes, hpricot took over a minute, and rexml took over two minutes, while nokogiri and libxml-Ruby came in at a few seconds each: Want all the actual numbers? Want to see the actual tests? Want to run them for yourself? Head over to Aaron's project here. Have fun! I'll putting on my flame-retardant jacket in

. Be redirected to an app store. Download the app. Wait while a multi-megabyte file downloads over your temperamental, expensive 3G connection. Open the app up. Familiarise yourself with an interface that has cryptic, weird touch affordances that aren't actually revealed to the user and behave ever so slightly differently from every other similar app. Struggle as the badly-implemented statefulness gives you a spinning loading wheel (on iOS

full GC is executed. Cmsinitiatingoccupancyfraction = 70 indicates that CMS is executed when the old generation accounts for about 70% of the total, so that full GC will not occur. Softreflrupolicymspermb is also useful in my opinion. The official explanation is softly.Reachable objects will remain alive for some amount of time after the last time they were referenced. the default value is one second of lifetime per free megabyte in the heap. I don't

[Question] You are given the ages (in years) of all people of a country with at least 1 year of age. you know that no individual in that country lives for 100 or more years. now, you are given a very simple task of sorting all the ages in ascending order.Input There are multiple test cases in the input file. Each case starts with an integerN(0 NNIntegers indicating the ages. Input is terminated with a case whereN= 0. This case shocould not be processed.Output For each case, print a lineNSpace se

(DBMS_RESOURCE_MANAGER.CALIBRATE_IO (2, 10, iops, mbps, lat );DBMS_OUTPUT.PUT_LINE ('max _ iops = '| iops );DBMS_OUTPUT.PUT_LINE ('latency = '| lat );DBMS_OUTPUT.PUT_LINE ('max _ mbps = '| mbps );End;/The parameters are described as follows: Parameter DescriptionNum_physical_disksApproximate number of physical disks in the database storage (number of physical disks input)Max_latencyMaximum tolerable latency in milliseconds for database-block-sized IO requests (Maximum number of milliseconds for

undo tablespace is not available, today we can complete all the work and steal joy. Prepare the data file as follows: # Lslv lv_undo_tmp01 Logical volume: lv_undo_tmp01 volume group: cxdatavg Lv identifier: 00f65ad200004c000000012e3d0271ff. 104 PERMISSION: read/write Vg state: active/complete lv state: closed/syncd TYPE: jfs2 write verify: off MAX LPs: 512 pp size: 512 megabyte (s) COPIES: 1 sched policy: striped LPs: 80 PPs: 80 STALE PPs: 0 bb poli

Bit (BIT) (binary digits): stores a bit of binary, that is, 0 or 1, the smallest storage unit. Byte: eight binary bits are one byte (B), the most common unit. Generally, the computer storage unit is represented by B, kb, MB, GB, TB, Pb, EB, ZB, Yb, and BB. The relationship between them is: 1kb (kilobyte kilobytes) = 1024b, 1 MB (megabyte MB for short) = 1024kb, 1 GB (gigabyte, also known as "Gigabit") = 1024 MB, 1 Tb (trillionbyte trillion byt

both 2, which indicates that the image operation is performed on two physical disks. 1. view the rootvg size. # Lsvg rootvgVolume group: rootvg IDENTIFIER: 00f9150300004c0000000145634ba48dVg state: active pp size: 1024 megabyte (s)Vg permission: read/write TOTAL PPs: 1116 (1142784 megabytes)MAX LVs: 256 FREE PPs: 199 (203776 megabytes)LVs: 13 USED PPs: 917 (939008 megabytes)OPEN LVs: 12 QUORUM: 1 (Disabled)TOTAL PVs: 2 vg descriptors: 3STALE PVs: 0

I started reading programming on Saturday and finished reading the first article. But now I write my notes. The first question is actually very simple. But it is impossible for someone who has learned data structures and sorting algorithms to come up with such a method, on the contrary, it is more likely to be thought of by a person who has never learned sorting. The problem is as follows: Input: a file containing at most n positive integers, each less than n, where n = 107. it is a fatal error

Write a file in WindowsProgramA process fork generates about 2000 threads and then exits abnormally. Why? This problem occurs because in Windows 32-bit system, a process can use a maximum of 2 GB of virtual memory, and the default thread stack stacksize of a thread is 1024 K (1 m ), in this way, when the number of threads approaches 2000, 2000*1024 K = 2G (approximately), memory resources are equivalent to depletion. Msdn Original: "The number of threads a process can create is limited

Iostat command ExplanationThe iostat is used to output CPU and disk input and output, partition, Network File system NFS-related statistics. The Iostat command monitors the input/output status of system devices and generates reports to modify the system configuration for better performance based on statistical reporting.Command format:Iostat [-c] [-d] [-n] [-n] [-h] [-K |-m] [-t] [-v] [-X] [-z] [device [...] | ALL] [-p [device [,...] | all] [interval [count]]Iostat can produce three types of rep

Linux boot Start program detailedWe assume that you are already familiar with the boot process of other operating systems, and understand the self-test boot steps of the hardware, starting with the boot loader for the Linux operating system (usually lilo for personal computers) and introducing the Linux boot steps.Load KernelAfter Lilo starts, if you choose Linux as the boot-ready operating system, the first thing to be loaded is the kernel. Keep in mind that there are no operating systems in th

is a game or high-definition are very necessary. For the current mainstream, whether it is telecommunications or netcom broadband, the general 4M speed can be achieved how much? The formula for calculating 4M broadband is: 4*1024/8 = 512k/s, that is, the theory of the 4M broadband speed download speeds can reach the highest 512k/s, But in reality because the environmental impact is not possible to achieve this speed, then how to judge it? The most common and easiest to judge is to use some of

that the eth0 outlet has 100mbit/s bandwidth, assigned to WWW, e-mail and Telnet three data traffic, which is allocated to the WWW bandwidth of 40mbit/s, the bandwidth allocated to the email is 40mbit/s, the bandwidth allocated to Telnet is 20Mbit SIt is important to note that the following abbreviations are used in the TC to indicate the appropriate bandwidth:Kbps kiiobytes per second, or "kilobytes per second;Mbps megabytes per second, or "megabyte

Linux boot Start program detailedWe assume that you are already familiar with the boot process of other operating systems, and understand the self-test boot steps of the hardware, starting with the boot loader for the Linux operating system (usually lilo for personal computers) and introducing the Linux boot steps.Load KernelAfter Lilo starts, if you choose Linux as the boot-ready operating system, the first thing to be loaded is the kernel. Keep in mind that there are no operating systems in th

of the system's maximum pathname (defined in the/usr/include/sys/limits.h file).If you do not specify an input file or if you specify-(minus) The file name, the split command reads the file from the standard input.SignNote: the-B and-L flags are mutually exclusive.-a suffixlength Specifies the number of letters used to form the suffix portion of the output name file. Number of letters determines the number of possible combinations of output file names. The default is two letters.-B divides the

doubled because the code page and shared library are single. The free and PS commands are useful for estimating memory requirements. The first step of the estimate plus some security amount. Because estimating the size of a program is probably wrong because you may have forgotten some of the programs you want to run and make sure you have some extra space. There should be a few MB. (Allocating too much space is better than allocating too little, but not excessive, because not using the swap s

is cumbersome, and the global variable Local_school is a Threadlocal object, each threadIt can read and write student properties, but it does not affect each other. You can think of Local_school as a global variable, and each property, such as Local_school.student, is a lineProcess local variables, can read and write without interfering with each other, do not need to manage the lock problem, threadlocal internal processing.The most common place for threadlocal is to bind a database connection,