test cases for bubble sort

permutation, find the size of the maximum independent set of graph G, if we use such permutation as The premutation a in procedure bubblesortgraph.InputThe first line of the input contains an integer n (2≤ n ≤105). The next line contains n distinct integers a1, a2, ..., a n (1≤ ai ≤ n). OutputOutput a single integer-the answer to the problem.Sample Test (s) input33 1 2Output2NoteConsider the first example.

Bubble sort (Bubble sort) is a simpler sort algorithm in the field of computer science. It repeatedly visits the column of elements to sort, compares two adjacent elements in turn, and swaps them if their order (e.g., from larg

The original bubble sort is relatively time-consuming, even though an array has changed in order after several rounds of swapping, such as [2,1,3,4,5,6,7], which, after the first round, has become orderly, but the stubborn bubbling still has to go on without a 22 comparison of nutrients, thus sacrificing time. If you use a flag to determine whether the current array is in order, if you exit the loop orderly

The first is the header file: Objective-c code #import @interface Sort: NSObject { } //Bubble Sort -(void) bunbleSortWithArray: (NSArray *) aData; // Select sort -(void) selectSortWithArray: (NSArray *) aData; // Insert sort -(void) insertSortWithArray: (NSArray *) aDat

Directory (?) [+] Introduction to bubble sort algorithm The bubble sort is simpler than the insertion sort, pushing the largest element progressively to the highest bit (currently dealing with the highest bit of the child array). As I understand it,

thought in this assignment process will change the value, so small white immediately converted ideas, wrote down the following code　　The small white to own this method obtains the result to be very satisfied, then gives own code to the small Liu to lookXiao Liu first nodded, then shook his head again, then said with small white: "You this method is feasible, but you do not think this method has what insufficient?"Xiao Bai thought: there! Removing an element will break the order of the list, bec

Title Link: http://cpp.zjut.edu.cn/ShowProblem.aspx?ShowID=1373Surface:Easy as a+bTime limit:1000ms Memory limit:32768kDescription:these days, I am thinking on a question, how can I get a problem as easy as a+b? It is fairly difficulty to do such a thing. Of course, I got it after many waking nights. Give you some integers, your task was to sort these number ascending. Should know how easy the problem is now! Good luck!Input:input contains multiple

Yesterday to cool dog interview, in the written test that a pass, Youdao requires PHP to achieve bubble sorting programming problem, because it is too long used bubble sort, forget the principle of the algorithm, the result left blank, really no language. So today I'm going to record the bubbling

comparisons of bubble sort The method of J represents a bubble sort of 22 of the comparison, as for j Otherwise, the array is out of bounds.*/public void Bubblesort () {for (int i = 0; i for (int j = 0; j }} /** The method is mainly an array of variables and displays*/public void Di

Bubble sort algorithm This is an sorting algorithm which I learned when I began to study the C branch Ange. I never wrote it down even though it's such a simple algorithm. Implementation C ++: CS /* 1. Pick the last one as the seed 2. If smaller than the previous one, swap it 3. Else the previous becomes as the seed 4. This loop ends until to the 'top' We can make sure that the smallest o

Title DescriptionThe bubble sort of the previous day was too simple for RSW, so there was a bubble sort of 2, given the n,k,q, Q: How many different 1~n permutations, can make, bubble sort K-trip, get an almost correct sequence.An

5,5 is greater than 3, do not need to Exchange 3 5 2 6 to continue comparing 2 and 2,5 greater than 5, Exchange position 2 3 2 + 5 continue to compare 6 and 6,6 greater than 2, do not need to Exchange 5 5 3 2 5 Continue to compare 6 and 2,6 greater than 2, swap position 3 2 5 2 6 6 sink to the last, two 2 are all up (fore). Second round Compare 3 and 2, 3 is greater than 2, Exchange position 2 3 5 2 6 Compare 3 and 5, 5 is greater than 3, do not need to Exchange 2 3 5 2 6 compare

This is a creation in Article, where the information may have evolved or changed. Bubble sort (Bubble sort), is a Computer Science The more simple areas of Sorting Algorithms . Algorithm principle The bubbling sorting algorithm works as follows: Compares the adjacent elements. If the first one is bigger than the

This is a test checklist for web applications and desktop applications. Note: This articlearticleA bit long, my goal is to be able to share one of the comprehensive test lists that have been started but not yet completed. I will continue to update the list with many scenarios.　　If you don't have time to read now, feel free to share it with your friends and bookmark them for later reading.

The idea of bubble sorting is to compare the adjacent two elements once, and compare the positions if the elements are smaller than the previous elements.After a trip like this, the most important element falls on the last side, so the boundary of the inner Loop also comes out, that is, the last few elements that are not counted, namely n-i-1;And the position that the outer loop needs to compare is n-2, if it exceeds the boundary; (where n is the tota

#include #define SUM 3+4//macro definition is intact using used for test4#include #include void Test () {//array outputint a[5]={1,2,3,4,5};printf ("Array output,look,please...\n");int a[10];int i;//for (int i=0;iprintf ("a[10]={");for (i=0; iA[i]=i;printf ("%d,", a[i]);}printf ("}");}void Test1 () {//input arrayint a[5];printf ("\narray input (just the number in the brackets), look please...\n");scanf ("%d%d%d%d", a[0],a[1],a[2],a[3],a[4]);//can inpu

method only need to 2x=1024,x=10, only 10 times, 100 minutes(3) There are 1 to 100 of the number, randomly looking for 1 to 100 of the number, how to find in the shortest time?A: Divide 1 to 100 into two halves, the middle number and the random number comparison, if the random number is greater than the middle number, select greater than the half and then divided into two halves of the search, and the random number comparison, kept divided into two halves to take the intermediate comparison val

(outer loop)First 22 comparison 2 Pre-swap Status | 2 | 4 | 1 | 5 | 6 | 9 |Post-swap Status | 2 | 4 | 1 | 5 | 6 | 9 |Second 22 comparison, 4 > 1 swapPre-swap Status | 2 | 4 | 1 | 5 | 6 | 9 |Post-swap Status | 2 | 1 | 4 | 5 | 6 | 9 |Third 22 Comparisons, 4 Pre-swap Status | 2 | 1 | 4 | 5 | 6 | 9 |Post-swap Status | 2 | 1 | 4 | 5 | 6 | 9 |Fourth time 22 comparison, 5 Pre-swap Status | 2 | 1 | 4 | 5 | 6 | 9 |Post-swap Status | 2 | 1 | 4 | 5 | 6 | 9 |Third trip

Solve the number of exchanges, with bubbling justSort it time limits: +Ms | Memory Limit:65535KB Difficulty:2 Describe You want to processe a sequence of n distinct integers by swapping, adjacent sequence elements until the sequence is so RTed in ascending order. Then how many times it need.For example, 1 2 3 5 4, we only need one Operation:swap 5 and 4. Input The input consists of a number of

First, what is bubble sort: the bubbling sort is compared between two adjacent numbers, where the previous value is defined as before, and the following value is defined as after; when Before>after I, exchange their values, if beforeThe time complexity of bubble sort is indi