tia 232

1#include 2 3 intFlag =0;4UnsignedintSend_data,recv_data;5 6 voidMain ()7 {8SCON =0X50;//MODE 29Tmod =0x20;//MODE 2Ten OneTH1 =0XFD; ATL1 =0XFD; - -TR1 =1; theES =1;//Open Serial Interrupt -EA =1; - - while(1) + { - if(Flag = =1) + { ASbuf =Send_data; at while(TI = =0); -TI =0; -Flag =0; - } - } - } in - voidSer_int () Interrupt4 //3 Timer 1 interrupt number 1 Timer 0 interrupt number 0 External interrupt 1 2 external interrup

; $ } $ if(s[i][j]=='*') flag=0, acr[cnt1].ans[tmp]=' /'; - if(flag) - { theacr[cnt1].ans[tmp++]=S[i][j]; - if(j==c-1) flag=0, acr[cnt1].ans[tmp]=' /';Wuyi } the } - } Wuflag=0; - for(intj=0; j) About { $ for(intI=0; i) - { - if((i==0|| s[i-1][j]=='*') s[i][j]!='*') - { Adown[++cnt2].num=Fl[i][j]; +tmp=0, flag=1; the } - if(s[i][j]=='*

Implement Queue using StacksImplement the following operations of a queue using stacks. Push (x)--push element x to the back of the queue. Pop ()--Removes the element from in front of the queue. Peek ()--Get the front element. Empty ()--Return whether the queue is empty. Notes: you must Useonly standard operations of a stack--which means onlypeek/pop from top , size , Andis empty operations is valid. Depending on your language, stack may is not supported native

is directly to pop up, this data will not enter S2.When the above operation is completed, the data of the S2 is transferred to S, and the data that has just been reversed is restored to the original order.In the process of testing the code, but also write the size of the queue, in fact, just a line, that is, the size of S.If you have finished reading this question, you can continue with the following question: Leetcode 225 Implement Stack using Queues (using queue to implement stack) (*)Ok, thi

() >1) {Stk2.push (Stk1.top ()); Stk1.pop (); }if(stk1.size () = =1) Stk1.pop (); while(!stk2.empty ()) Stk1.push (Stk2.top ()), Stk2.pop (); }//Get the front element. intPeekvoid) {intRe while(Stk1.size () >1) {Stk2.push (Stk1.top ()); Stk1.pop (); }if(stk1.size () = =1) Re = Stk1.top (); while(!stk2.empty ()) Stk1.push (Stk2.top ()), Stk2.pop ();returnRe }//Return whether the queue is empty. BOOLEmptyvoid) {returnStk1.empty (); }};2.231 Power of Two2.1 problem descriptionD

Click to open linkThis is a string simulation, test instructions is probably given a m*n grid, Haig with ' * ', the white lattice has a letter, if a white lattice left or above the black lattice, it is called a starting lattice.Then find all the horizontal and vertical words, note that the place of the horizontal word refers to start from a beginning to the right or down, until the black lattice or out of bounds, and each letter in the search for horizontal or vertical words can only use aTimes,

My idea is that all around the grid is set to ' * ', setting the sign array record starting grid#include #includeChara[ -][ -];intsign[ -][ -];intn =1;intMain () {intR, C, CNT, yes, first =1; while(SCANF ("%d", r) = =1) {memset (sign,0,sizeof(sign)); CNT=1; Yes=0; if(r = =0) Break; scanf ("%d",B); GetChar (); for(inti =1; I ) { for(intj =1; J ) {scanf ("%c",a[i][j]);} GetChar (); } for(inti =0; I 1; i + +) a[i][0] = a[i][c+1] ='*'; for(intj

PrivateStackOutputstack;7 8 Publicmyqueue ()9 {TenInputstack =NewStack(); OneOutputstack =NewStack(); A } - - Public voidPushintx) the { - while(!outputstack.isempty ()) - Inputstack.push (Outputstack.pop ()); - Inputstack.push (x); + while(!inputstack.isempty ()) - Outputstack.push (Inputstack.pop ()); + } A at Public voidpop () - {Outputstack.pop ();} - - Public intPeek () -{returnOutputstack.peek ();} - in Public Booleanempty

LeetCode 232 Implement Queue using Stacks (Queue using Stack )(*)Translation Stack is used to perform the following operations on the queue. Push (x) -- write element x to the end of the queue pop () -- remove the element peek () from the queue header -- return the queue Header element empty () -- whether the returned queue is empty. Note: you must use a stack with only standard operations. That is to say, only push/pop/size/empty and other operations

Easy Stack, 155 take the smallest element, with two stacks, the second stack saves the smallest element of the current stack, and then pops up when the element pops up according to the situation: Class Minstack {public : /** Initialize your data structure here. * /Minstack () { } void push (int x) { s1.push_back (x); if (S2.empty () | | X 255 with Deque, two-way queues: Class Mystack {public : /** Initialize your data structure here. *

about 350mV can meet the requirements of near-distance transmission. Assuming that the load resistance is 100 kohm, when using LVDS transmission data, if the twisted pair length is 10m, the transmission rate can reach 400Mbps, when the cable length increases to 20m, the rate will be 100Mbps, and when the cable length is 100m, the rate can only reach 10Mbps around4. Transfer rateOne-to-one connector caseRS232 can achieve two-way transmission, full-duplex communication maximum transmission rate o

Usually the RS-232 interface appears in 9-pin (DB-9) or 25-pin (DB-25) Type Generally, there are two groups of RS-232 interfaces on the PC, called COM1 and com2 RS-232C interface signal RS-232C Gauge Standard Interface has 25 lines, 4 lines, 11 control lines, 3 timing lines, 7 standby and undefined lines, commonly used only 9, they are 1. The data set ready-DSR status indicates that the modem is in usable s

TopicImplement the following operations of a queue using stacks.Push (x) –push element x to the back of the queue.Pop () –removes the element from in front of the queue.Peek () –get the front element.Empty () –return whether the queue is empty.Notes:You must use only standard operations of a stack–which means only push to top, peek/pop from top, size, and is empty ope Rations is valid.Depending on your language, stack may is not supported natively. You could simulate a stack by using a list or d

Tags: Post get nbsp path pre character false input git commandWhen adding a file to be submitted using git Add, if the file name is in Chinese, it will display garbled characters such as 274\232\350\256\256\346\200\273\347\273\223.Solution: At the bash prompt, enter:FalseIf the Core.quotepath is set to False, the characters above 0x80 will not be quote. Chinese display is normal.Reference:http://blog.csdn.net/tyro_java/article/details/53439537Linux gi

Title Description:Implement the following operations of a queue using stacks. Push (x)--push element x to the back of the queue. Pop ()--Removes the element from in front of the queue. Peek ()--Get the front element. Empty ()--Return whether the queue is empty. Notes: You must use only standard operations of a stack--which means only push to top , peek/pop from top , size , and is empty operations AR E valid. Depending on your language, stack may is

Question link: Click the open link #include Sgu 232 infinite fraction hash

Leetcode 232: Implement Queue using Stacks, leetcodeimplementImplement Queue using StacksTotal Accepted:93Total Submissions:256 Implement the following operations of a queue using stacks. Push (x) -- Push element x to the back of queue. Pop () -- Removes the element from in front of queue. Peek () -- Get the front element. Empty () -- Return whether the queue is empty. Notes: You must useOnlyStandard operations of a stack -- which means only

The code is messy, and the time is too tight to sort out and the idea is not good ~ But AC ...... You can leave a message if you cannot see it clearly, or join QQ to discuss it. # Include Ultraviolet A 232-crossword answers

stack, which means that only the push to top (stack), the Peek/pop from top (take the top of the stack/top of the stack),//And empty (judgment is empty) is allowed, depending on your language, the stack may not be built-in support. You can use list (list) or deque (double-ended queue) to simulate,//to ensure that only the standard operation of the stack, you can assume that all operations are valid (for example, do not perform a pop or peek operation on an empty queue)//solution: With two stack

classMyqueue {//Push element x to the back of the queue. Public voidPushintx) {stin.push (x); } //Removes the element from in front of the queue. Public voidpop () {if(Stout.isempty ()) { while(!Stin.isempty ()) {Stout.push (Stin.pop ()); }} stout.pop (); } //Get the front element. Public intPeek () {if(Stout.isempty ()) { while(!Stin.isempty ()) {Stout.push (Stin.pop ()); } } returnStout.peek (); } //Return Whether the queue is empty.