to introduce zookeeper, large changes to existing code)
4.redis+sentinel (Redis self-monitoring middleware) (small code changes, less configuration, and can meet the needs of dual-machine hot standby)
Based on our current situation and requirements, after a brief comparison, our team decided to choose a fourth option Redis+sentinel to achieve dual-machine hot standby. preparatory work 1. Install redis-001 (main)
$ wget http://download.redis.io/releases/redis-3.2.3.tar.gz
$ tar xzf redis-3.2.3.t
50 commonly used test and interview SQL statements Postedon50 commonly used test and interview SQL statements 2009-12-1715: 05 Student (S #, Sname, Sage, Ssex) student table Course (C #, Cname, T #) Course list SC (S #, C #, score) Instructor table question: 1. query all students whose 001 course scores are higher than 002.
50 commonly used test and interview SQL statements Posted on 50 commonly used test, interview SQL statement Student (S #, Sname,
50 commonly used SQL statements Student (S #, Sname, Sage, Ssex) Student table Course (C #, Cname, T #) curriculum SC (S #, C #, score) exam table Teacher (T #, Tname) Instructor table questions: 1. query the student ID of all the students whose scores are higher than those of the 002 course; selecta. S # from (selects #, scorefromSCwhereC #001)
50 commonly used SQL statements Student (S #, Sname, Sage, Ssex) Student table Course (C #, Cname, T #) cur
all students whose score is higher than that of the "002" course;
select a.S# from (select s#,score from SC where C#='001') a,(select s#,score from SC where C#='002') b where a.score>b.score and a.s#=b.s#;2. query the student ID and average score of students whose average score is greater than 60;
select S#,avg(score) from sc group by S# having avg(score) >60;3. query the st
SQL database Interview Questions and answers
(22:52:54)
ReprintedBytes
Summary of course number of three c courses by Ye Ping
Category: Program World
Student (S #, Sname, Sage, Ssex) Student table S #: Student ID; Sname: Student name; Sage: Student age; Ssex: Student genderCourse (C #, Cname, T #) curriculum C #, Course No.; Cname: Course name; T #: Instructor No.SC (S #, C #, score) Student table S #: Student ID; C #, course number; score: scoreTeacher (T #, Tname) Instructor table T #: Instruc
Basic Database Operations, databasesI. Data Table Student (S #, Sname, Sage, Ssex) Student table S #: Student ID; Sname: Student name; Sage: Student age; Ssex: Student genderCourse (C #, Cname, T #) curriculum C #, Course No.; Cname: Course name; T #: Instructor No.SC (S #, C #, score) Student table S #: Student ID; C #, course number; score: scoreTeacher (T #, Tname) Instructor table T #: Instructor ID; Tname: Instructor name
Ii. Basic operations:1. query the student ID of all students whose sc
Windbg DEBUG command 7 (! Runaway ,~)
1.! Runaway
! RunawayCommand to display the consumption time of each thread
Bit 0 (0x1) enables the debugger to display the user time consumed by each thread. The default value 0x1 is not added.
Bit 1 (0x2) shows the Kernel Time consumed by each thread ).
Bit 2 (0x4) shows how long each thread has elapsed since its creation.
Is the combination of the three: 1 2 3 4 5 6 7
0: 002>! Run
This text has been reprinted online, and some SQL statements are suitable for use in application systems. Some "reports" have a heavier feeling, mainly to review the former.
This text has been reprinted online, and some SQL statements are suitable for use in application systems. Some "reports" are more likely to be used, mainly to review the former.
50 common SQL statements
Student (S #, Sname, Sage, Ssex) Student table
Course (C #, Cname, T #) Curriculum
SC (S #, C #, score) Orders table
Teac
50 SQL statements involved in one question
Student (s #, sname, sage, ssex) Student tableCourse (C #, cname, T #) CurriculumSC (s #, C #, score) Orders tableTeacher (T #, tname) Instructor table
Problem:1. query the student ID of all students whose score is higher than that of the "002" course;Select a. s # From (select s #, score from SC where C # = '001') A, (select s #, scoreFrom SC where C # = '002
50 Common SQL statements
Student (s#,sname,sage,ssex) Student table
Course (c#,cname,t#) timetable
SC (s#,c#,score) score sheet
Teacher (t#,tname) Teacher's Table
Problem:
1, Query the "001" Course than "002" course scores of all students of the school number;
Select a.s# from (select S#,score from SC where c#= ' 001 ') A, (select S#,score
From SC where c#= ' 002 ') b
where A.score>b.score and a.s#=b.s#;
"Hello!"(integer) 0
127.0.0.1:6379> hget myhash Field"Hello"
③hmset method
Set multiple field of hash at the same time
Cases
Copy Code code as follows:
127.0.0.1:6379> hmset user:002 name Dee specialty PHP
Ok
127.0.0.1:6379> hget user:002 Name"Dee."
127.0.0.1:6379> Hget user:002 Specialty"PHP"
④hget method
Gets the spe
Student (s#,sname,sage,ssex) Student tableCourse (c#,cname,t#) timetableSC (s#,c#,score) score tableTeacher (t#,tname) Teacher tableProblem:1, the inquiry "001" course is higher than "002" of all students of the school number;Select a.s# from (select S#,score from SC where c#= ' 001 ') A, (select S#,scoreFrom SC where c#= ' 002 ') bwhere A.score>b.score and a.s#=b.s#;2, the query average score is more than
50 common SQL statementsStudent (S #, Sname, Sage, Ssex) Student tableCourse (C #, Cname, T #) CurriculumSC (S #, C #, score) Orders tableTeacher (T #, Tname) Instructor tableProblem:1. query the student ID of all students whose score is higher than that of the "002" course;Select a. S # from (select s #, score from SC where C # = '001') a, (select s #, scoreFrom SC where C # = '002') BWhere a. score> B. sc
50 SQL Query Techniques, query statement examples, 50 SQL statements
Student (S #, Sname, Sage, Ssex) Student tableCourse (C #, Cname, T #) CurriculumSC (S #, C #, score) Orders tableTeacher (T #, Tname) Instructor tableProblem:1. query the student ID of all students whose score is higher than that of the "002" course;Copy codeThe Code is as follows:Select a. S # from (select s #, score from SC where C # = '001') a, (select s #, scoreFrom SC where C #
50 common SQL statements
Student (S #, Sname, Sage, Ssex) Student tableCourse (C #, Cname, T #) CurriculumSC (S #, C #, score) Orders tableTeacher (T #, Tname) Instructor table
Problem:1. query the student ID of all students whose score is higher than that of the "002" course;Select a. S # from (select s #, score from SC where C # = '001') a, (select s #, scoreFrom SC where C # = '002') BWhere a. score> B.
Student (s #, sname, sage, ssex) Student tableCourse (C #, cname, T #) CurriculumSC (s #, C #, score) Orders tableTeacher (T #, tname) Instructor table
Problem:1. query the student ID of all students whose score is higher than that of the "002" course;Select a. s # From (select s #, score from SC where C # = '001') A, (select s #, scoreFrom SC where C # = '002') BWhere a. score> B. score and a. s # = B. S #
Student (s#,sname,sage,ssex) Student tableCourse (c#,cname,t#) timetableSC (s#,c#,score) score sheetTeacher (t#,tname) Teacher's TableProblem:1, Query the "001" Course than "002" course scores of all students of the school number;
Copy Code code as follows:
Select a.s# from (select S#,score from SC where c#= ' 001 ') A, (select S#,score
From SC where c#= ' 002 ') b
where A.score>b.score a
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