tps l2

://s3.51cto.com/wyfs02/M00/73/39/wKioL1X4AaazlT6xAAEh5CIu3as754.jpg "height=" 348 "/>2, node Nodes and the level of (level)In OSPF, the node names are: DR, BDR, ABR, ASBR, and so on.In Is-is, the node name is as follows;Nodes:Level-1 Routers (L1 router )--- non-backbone zone routersFor the Level1 router, it is located inside the common area.█L1 routers only form adjacency with Level1 routers within the region (or L1/L2 with L1 functionality).The █L1 r

The main idea is that two pieces of wood to form a slot, ask how much rain tank can be installed, pay attention to the vertical fall of rain, thinking is very simple, is the classification of the discussion is a bit bad.1. If the two segments do not intersect or are parallel, install 0;2. There is a parallel x-axis, installed 0;3. If the top cover below, install 0;4. Other, cross-product to find area.Directly on the code:#include #include #include Using namespaceSTD;Const Double eps=1e-8;struct

Label:from:http://jackyrong.iteye.com/blog/19826781. Number of system MySQL processesPs-ef | grep "MySQL" | Grep-v "grep" | Wc–l2.slave_runningMySQL > Show status like ' slave_running ';If the system has a slave replication server, this value indicates the health of the server from the3.threads_connectedMySQL > Show status like ' threads_connected ';The number of connections currently being made by the client. This value will be less than the preset v

Tags: mysql database1. Number of system MySQL processesPs-ef | grep "MySQL" | Grep-v "grep" | Wc–l2.slave_runningMySQL > Show status like ' slave_running ';If the system has a slave replication server, this value indicates the health of the server from the3.threads_connectedMySQL > Show status like ' threads_connected ';The number of connections currently being made by the client. This value will be less than the preset value, but you can also monitor

The array pointer problem seems complicated to be simple. Please help me! Delphi/Windows SDK/API Http://www.delphi2007.net/DelphiDB/html/delphi_20061219113016224.html First, I made a DLL named "mydll" Library mydll; Uses Sharemem, Sysutils, Extctrls, Stdctrls; Type TPS = record Sno: integer; // serial number Fjcode: String [200]; // code End; TP = array of TPS; PTP = ^ TP; {$ R *. Res} Function select

21. Merge Two Sorted Lists, mergesorted The question comes from leetcode. The requirement is to splice two sorted linked lists into an ordered linked list. The linked list structure is as follows: public class ListNode{ int val; ListNode next; ListNode(int x){ val=x; } } As follows, a rectangle becomes a node, and a linked list has at least one node. Method 1: first create a new linked list L, compare the Val of the current L1 and

1. Number of system mysql processesPs-ef | grep "MySQL" | Grep-v "grep" | Wc–l2.slave_runningMySQL > Show status like ' slave_running ';If the system has a slave replication server, this value indicates the health of the server from the3.threads_connectedMySQL > Show status like ' threads_connected ';The number of connections currently being made by the client. This value will be less than the preset value, but you can also monitor this value to be la

Tags: using IO strong data problem CTI time log1. Number of system mysql processesPs-ef | grep "MySQL" | Grep-v "grep" | Wc–l2.slave_runningMySQL > Show status like ' slave_running ';If the system has a slave replication server, this value indicates the health of the server from the3.threads_connectedMySQL > Show status like ' threads_connected ';The number of connections currently being made by the client. This value will be less than the preset valu

" #test case nameThreads=4 #numbers of thread of every client hostConnections=4 #numbers of connection of every client hostdurations=10 #time of test case runningthinktime=2000 #the time interval between requestsUrl= "http://10.41.150.52:8082/job/tcep/" #request URLDT = Datetime.datetime.now ()Res_file = "/home/test_result/%s_%s.txt"% (TEST_NAME,DT)Res_file = Res_file.replace ("", "_")If Os.path.exists ("/home/test_result"):With settings (hide (' warnings ', ' running ', ' stdout ', ' stderr '),

Video Demo:Https://pan.baidu.com/s/1qYRMp7QTool sysbench0.5 128 Concurrent 10 sheets 1 million rowsHardware configuration R720 64G RAID10 (15000 rpm)100 seconds for separate pressure measurementSysbench--test=/root/soft/sysbench-0.5/sysbench/tests/db/oltp.lua--mysql-table-engine=innodb--oltp-table-size= 1000000--max-requests=0--max-time=100--num-threads=128--oltp-tables-count=10--report-interval=10--mysql-host= 192.168.143.244--mysql-port=4000--mysql-user=admin--mysql-password=159753--mysql-db=t

This article mainly introduces Python's examples of merging and sorting two ordered lists. The final code is constantly optimized and the small Editor is very satisfied, for more information about how to merge two lists with high efficiency and keep them in order, the sorting is positive by default. The idea is relatively simple. It is nothing more than comparing the first element in l1 and l2 headers in sequence, placing the smaller one in a new lis

Suppose there are 2 sequential tables L1, L2, how efficient the 2 lists are merged and maintained in an orderly state, where the default ordering is the positive order. The idea is relatively simple, which is to compare the first element of L1 and L2 head in turn, will be smaller than a new list, and so on, until all the elements are placed in the new list. Consider 2 lists L1 = [2],

ADD NumbersYou have both numbers represented by a linked list, where each node contains a single digit. reversethe digits is stored in order, such the 1 's digit is at the head of the list. Write a function that adds the numbers and returns the sum as a linked list.ExampleGiven 7->1->6 + 5->9->2 . That's, 617 + 295 .Return 2->1->9 . That's 912 .Given 3->1->5 5->9->2 and, return 8->0->8 .Solution:It is simple to add, to see a linkedlist again, and then to consider the carry, a carry count, the nu

Assuming that there are 2 sequential table L1, L2, how to efficiently combine 2 lists and maintain an orderly state, where the default sort is positive sequence. The idea is relatively simple, but is to compare L1 and L2 The first element of the head, will be smaller than a new list, and so on, until all the elements are placed in the new list. Consider the 2 list L1 = [2],

This article is in the study summary, welcome reprint but please specify Source:http://blog.csdn.net/pistolove/article/details/41750865Merge sorted linked lists and return it as a new list. The new list should is made by splicing together the nodes of the first of the lists.For example,Given1->2->3,4->5->6 ,return1->2->3->4->5->6.Given1->3->5,2->4->4,return1->2->3->4->5->6.Ideas:(1) Test instructions to synthesize an ordered list of two ordered linked lists.(2) First, the list header node is emp

Tags: style blog Io ar use the for strong SP File Continue with yesterday's topic. I mentioned yesterday that I/O: the indirect impact of format on data sharing. I am afraid it is more likely to become a "pitfall" in the following two cases. Well, I happened to have encountered it; If the test code is as follows, what will happen? Guess! s2()-> L=[1,2,3,4,5,6], L2=[L,L,L,L],erlang:display( {{erts_debug:size(L),erts_debug:flat_size(L)},{erts_debug:s

General Equation Method: The general equation of a straight line is f (x) = AX + by + c = 0. Now that we know the two points of a straight line, assuming (x0, y0), (x1, Y1), we can get a = y0-Y1, B = x1-x0,C = x0y1-x1y0. Therefore, we can represent the two straight lines F0 (x) = A0 * x + B0 * Y + C0 = 0, F1 (x) = A1 * x + B1 * Y + C1 = 0 The intersection of the two straight lines should meet A0 * x + B0 * Y + C0 = A1 * x + B1 * Y + C1 This can be introduced X = (B0 * C1-B1 * C0)/d Y = (A1 * C0

) {} * }; */class Solution {public:listnode* mergetwolists (ListNode *l1, ListNode *l2) {if(L1 = =NULL L2 = =NULL){return NULL; }Else if(L1 = =NULL L2! =NULL){returnL2; }Else if(L1! =NULL L2 = =NULL){returnL1; } ListNode *new_head =NULL;if(L1->val Next; }Else{new_head = L2;

Leetcode 2_add, NumbersTitle Description:You are given, linked lists representing, and non-negative numbers. The digits is stored in reverse order and all of their nodes contain a single digit. ADD the numbers and return it as a linked list.Input: (2, 4, 3) + (5, 6, 4)Output: 7, 0, 8the topic is very clear (although I watched for a long while), nothing more than the list added! Attention:1, the list length is not said to be as long.2, consider the last node may carry, at this time need to create

When designing a system, the architect wants to build a high-performance system, and the throughput (TPS) is an important indicator of the performance of the system. When doing performance testing, testers need to understand the number of concurrent users of the system, system throughput, and response time, and so on, according to the relationship between the following simple collation as follows.1. Response Time: The time required to respond to the r