tps l2

Title: http://oj.leetcode.com/problems/add-two-numbers/ You are given two linked lists representing two non-negative. The digits are stored in reverse order and all of their nodes a single contain. Add the two numbers and return it as a linked list. Input: (2-> 4-> 3) + (5-> 6-> 4)Output:7-> 0-> 8 Title translation: A given two lists represent two non-negative numbers. The numbers are stored in reverse order, and each node contains a single number. Calculates the two-digit number and returns it

Coding:1,is = == = the value is compared.is memory address.for int STR: There is a concept of a small data pool.Why is there a small data pool? Save memory.INT-5 ~ 256STR all letters, numbers and a single letter want to multiply the number by no more than 20.Other data types: No concept of small data pools,L1 = [1] L2 = [1]Big environment: Python3:PYTHON3: encoded Unicode in STR memoryWhat if I want to store, or transfer strings (files) directly to ST

1L1 = [1, 2, 3]2L2 =L13L1.append ('a')4 Print(L1, L2)#Deep Cpoy5 6L1 = [1, 2, 3]7L2 = L1.copy ()#Shallow Copy8L2.append ('a')9 Print(L1, L2)View Code1. Other Codes1 #Assignment Operations2 #L1 = [A]3 #L2 = L14 #l1.append (' a ')5 #print (L1,L2)6 7 #Copy8 #L1 = [A]9 #L2 = l1.

Copy is a copy, what is the depth of the word?In Python, there is a difference between the assignment of an object and the copy (deep/shallow copy), which can produce unexpected results if used without notice.Actually, this is the result of shared memory.Copy: The principle is to separate the data, copy its data, and later modify the non-impact.Let's look at a non-copy example.= Assignment: Data is fully shared (= assignment is pointing to the same object in memory, if it is a variable (mutable)

Merge Sorted ListsMerge sorted linked lists and return it as a new list. The new list should is made by splicing together the nodes of the first of the lists.Idea: Merge two sorted single-linked lists. The algorithm is relatively simple, similar to the merge sort. Just the data structure on the previous learning, now forget more, write the first time more laborious. and want to repeat the code to write the method, but the method can not change the value of parameters synchronously, there is no w

Merge sorted linked lists and return it as a new list. The new list should is made by splicing together the nodes of the first of the lists.Test instructions: Merging two sorted listsThe problem is not difficult, but there are a lot of details that need attention, direct sticker code1 /**2 * Definition for singly-linked list.3 * struct ListNode {4 * int val;5 * struct ListNode *next;6 * };7 */8 structlistnode* mergetwolists (structlistnode* L1,structlistnode*

Isis? Word ISO routing area tag Level-1 is-is level-1 routes only Level-1-2 is-is level-1 and level-2 routes Level-2 is-is level-2 routes only Metric metric for redistributed routes Route-map route map reference R1 (config-router) # redistribute ISIS level-1 metric 2 Check R5 route table R5 # Show IP Route .... 34.0.0.0/24 is subnetted, 1 subnets I L2 34.0.0.0 [115/20] via 45.0.0.4, fastethernet0/1 16.0.0.0/24 is subnetted, 1 subnets I

1. A list loop with duplicate data# The result is incorrect when you cycle through the data in the list for inch L: if i%2! =0: l.remove (i)print(l)The output is:[1, 2, 4, 6, 8]Why is not correct, because: the loop subscript 0 element is 1, the number of the deletion of the list at this time to [1,2,3,4,5,6,8], this time to cycle subscript 1, when the subscript is 0 or 1, subscript 1 is 2, so the subscript 0 has been circulating, so it was missing out.2. Memory address as memory addr

This article will not explain the details of each of the network technology, and will not explain the implementation of neutron network details, but a high degree of summary of the technical nature of these basic network technology, trying to help you in these network technology and neutron between the establishment of a higher level of contact, so that everyone juchongruoqing, the global system to So before you read this article, understanding the following knowledge will help you understand th

suffering from this disease only with these 5 factors, the doctor is much better analysis. But if 1000 wi is not 0, doctors face these 1000 kinds of factors, tired sleep do not love.2, L2 norm In addition to the L1 norm, there is a more popular rule-norm that is the L2 norm: | | w| | 2. It is also inferior to the L1 norm, it has two laudatory name, in the return inside, some people have its return called

# # [0, 0, 0, 0, 0, 0, 0, 0, 0], #3 # [0, 0, 0, 0, 0, 0, 0, 0, 0], #4 # [0, 0, 0, 0, 0, 0, 0, 0, 0], #5 # # [0, 0, 0, 0, 0, 0, 0, 0, 0], #6 # [0, 0, 0, 0, 0, 0, 0, 0, 0], #7 # [0, 0, 0, 0, 0, 0, 0, 0, 0], #8 # # 0, 1, 2, 3,|4, 5, 6,|7, 8 #] Exists_d = Dict (((H_idx, Y_idx), V) for H_idx, Y-Enumerate (a) for Y_idx, V in enumerate (y) if v) h_exist = defaultdict (dict) v_exist = Defaultdict (di CT) for k, v. in Exists_d. Items (): h_exist[k[0]][k[1]] = v v_exist[k[1]][k[0]] = v AA = List (Itertoo