C-SPF
Time limit:1000 ms
Memory limit:10000kb
64bit Io format:% I64d % i64usubmit status
DescriptionConsider the two networks shown below. assuming that data moves around these networks only between directly connected nodes on a peer-to-peer basis, a failure of a single node, 3, in the network on the left wocould prevent some of the still available nodes from communicating with each other. nodes 1 and 2 cowould still communicate with each other as c
SPFTime Limit: 1000 MSMemory Limit: 10000 KTotal Submissions: 3790Accepted: 1727DescriptionConsider the two networks shown below. assuming that data moves around these networks only between directly connectednodes on a peer-to-peer basis, a failure of a single node, 3, in the network onthe left wowould prevent some of the still available nodes from communicatingwith each other. nodes 1 and 2 cocould still communicate with each other as couldnodes 4 and 5, but communication between any other pair
Reprint Please specify source: http://blog.csdn.net/vmurder/article/details/42671865In fact, I just feel that the original traffic is a bit more uncomfortable than unauthorized piracy 233 ...Test instructions: Ask what points are cut points, cut off after the picture can be divided into several pieces.Too much water does not want to be solved.Tarjan is good, do not understand the code.Code:#include "POJ1523" SPF Tarjan-two-connected Component Bare top
Previously thought is not set up, because in the self-service management system did not find the place.
Today to the million Network technology customer service call, just know, in fact, can be set. Login www.net.cn, in the left menu has a "domain DIY self-help management", click to enter the "domain name self-help resolution platform" (Http://diy.hichina.com/cgi-bin/login), Use domain name and domain name password (not million network account password OH) login, click on the left menu "DNS r
No SPF record is set to forge sender
0x01. Preface
SPF is called the Sender Policy Framework, that is, the Sender Policy Framework.
The current Email communication is still using the Simple Mail Transfer Protocol. SMTP is a very simple transmission protocol, and it does not have good security measures. According to SMTP rules, the sender's email address can be declared by the sender at will.
0x01. Preface
SPF is known as the sender Policy framework, the sender policy frame.
Current email communication, or is using the Simple Mail Transfer Protocol (Simplicity Mail Transfer Protocol) protocol. SMTP is a very simple transport protocol and has no good security in itself. According to the rules of SMTP, the sender's e-mail address can be declared arbitrarily by the originator. SPF is to prevent the
What is SPF?
Is the sender policy framework. SPF can prevent others from forging your email. It is a solution for anti-spoofing emails. After you define the SPF record of your domain name, the recipient determines whether the connected IP address is included in the SPF record based on your
http://golehuang.blog.51cto.com/7499/920865
When the link state routing algorithm constructs the LSDB, the next verse calls the SPF algorithm, processes the LSA in the LSDB, and calculates all the paths. The SPF algorithm is described in the OSPF section of the Routing TCP/IP volmun I.
The SPF algorithm is described briefly as follows (Lsdb has converged):
First,
An undirected graph is used to calculate a cut point. Is the use of tarjan.
[Cpp]# Include # Include # Include Using namespace std;Const int maxn = 1e3 + 9, N = 1e3;Bool e [maxn] [maxn];Int dfn [maxn], low [maxn], count, in [maxn];Void tarjan (int t, int from){Dfn [t] = low [t] = ++ count;Int ret = 0;For (int I = 1; I If (e [t] [I]){If (I = from) continue;If (dfn [I] =-1){Ret ++;Tarjan (I, t );Low [t] = min (low [t], low [I]);If (low [I]> = dfn [t])In [t] ++;}Else{Low [t] = min (low [t], dfn [I]
The main idea: give a picture, ask to cut points, the number of connected components is how manyProblem-solving ideas: cut points of water problems, set template can beHad to spit out the slot for input.#include #include #define MIN (a) #define N 1010#define M 2000010structedge{intTo, next;} E[M];intHead[n], Num[n], pre[n], lowlink[n];intTot, dfs_clock, root;BOOLIscut[n];voidDfsintUintFA) {Lowlink[u] = pre[u] = ++dfs_clock;intChild =0; for(inti = Head[u]; I! =-1; i = e[i].next) {intv = e[i].to;i
Title: http://poj.org/problem?id=1523Topic Analysis:Pay attention to the problem input input, prevent PE, the topic is to seek cutting points, and ask the cut point this connected graph into a few sub-graphs, is a template problem bar.#include #include#includestring.h>#include#include#includestring>#defineN 10010using namespacestd;structnode{intX,y,next;} eg[2*N];intTt,head[n],dfn[n],low[n],ti,f[n];voidinit () {memset (head,-1,sizeof(head)); TT=0; TI=1; memset (DFN,0,sizeof(DFN)); Memset (F,0,si
SPF -- standard parasitic formatDspf -- Detailed standard parasitic formatRSPF -- reduced standard parasitic formatSpef -- standard parasitic Exchange FormatSbpf -- Synopsys binary parasitic format Summary: SPF, dspf, and RSPF are in the Candence format and do not contain information about crosstalk C. They cannot be used in PT Si. Dspf has detailed RC information, which is relatively large in size and cl
Approximate test instructions: a connected undirected graph is given to find out which points are cut points, and for each cut point, the number of connected components after the point is removed. Output "No SPF nodes" if there is no cut point. Ideas:Seek cutting point with Tarjan can, and then ask to delete the number of connected components after cutting point, every time to find a cut point, and then from the point of cut Dfs, you can also directl
Meaning
Give a connected undirected graph, find all the cut points of this graph, and output each cut point and the connected edge is removed, will become several connected components
Ideas
Use Tarjan to find the basic problem of cutting point, the principle of Tarjan algorithm to really understand, this problem on the water.
Code
/**===================================================== * This are a solution for ACM/ICPC problem * * @source: poj-1523 S
The main idea of this problem is to find the cut point, and to find out if the cut point is removed, the whole picture is divided into several parts
Look at Beida that book, the solution of the point connectivity of undirected graphs.
And then they
/* Question address: http://poj.org/problem? Id = 1523 question: Give You A relational network, ask for the key node in it -- remove the connected part from the point and change it to two or more parts. The order of the midpoint of the question is
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