The football tournament is a team in a season to face the league in addition to their own team in the game, for which we can use a loop algorithm to achieve, then take a look at the Python Design Football League schedule program and simple implementation of the idea of the example:
Every year the Serie A Bundesliga tournament is a must-see for the fans, remembering the code that was written to build the sc
G-footballTime limit:1000MS Memory Limit:65536KB 64bit IO Format:%i64d %i64 U SubmitStatusDescriptionConsider a single-elimination football tournament involving 2n teams, denoted 1, 2, ..., 2n. In each round of the tournament, all teams still in the tournament is placed in a list in order of increasing index. Then, the first team in the list plays the second team, the third team plays the fourth team, etc. The winners of these matches advance to th
covered by this title. And a coach in the club can stand for more than 3-5 years, the road opponents still elusive his troops way, so that the team's success, enough to show that the coach diversification, troops array changes in endless, resulting in a long time, the opponent in a very difficult to break. According to this idea, it is obvious that Sir Alex, Arsene Wenger, the Magic Bird, Guardiola, Lippi, and so on, are the best candidates for such superior coaches.To revitalize Chinese
[TOJ 3955] nku acm football match (weighted sum query set), tojnku
Description
Nku acm is about to hold a football match recently. As the event owner, Lee wants to team up registrants. The team should follow the following principles:
One person cannot join multiple teams;People you don't know can't be in the same team;If a and B know each other and B and c know each other, a and c also know each other;Each
The flame here is not the flame material, the need to draw the overall shape of the flame according to their own needs, and then render the middle of the high light, and then slowly refine the edge of the flame can be.
Final effect
1, a new 1000 * 750 pixels, resolution of 72 of the canvas, background filled with black.
Create a new group, named "Football", open the football
Python: Train of Thought and simple implementation example for designing the Football League Schedule Program.
Each year, the schedules of major league matches in the Premier League of Serie A are a must-have for fans. It is so comfortable to write this kind of things in Python when I think of the code that I have previously written to generate a competition schedule.This algorithm is called the snake ring algorithm.That is to say, all teams are arran
Data Analysis of football game forums-simple and crude K-means clustering and mean-means clustering
After trying to tag in
The classification of Forum posts is not as simple as PC/PS/XBOX
Even the author's own labels have the possibility of hanging the goat's head.
Since it is impossible to classify posts, try the clustering algorithm to see if any of the following information is found:
# All texts with good words have been saved into one file wi
, "': {'"), "' ': {'"), "'}, ' 0", "'}, '"), "'}, ' 0", "'}, '") for i = 1 to $ j = 0 to Cells (i + 1, j + 1) = Ms.eval ("a.racelist[" I "]." am P BT (j)) Next J Next I. Open "GET", "http://www.aicai.com/static/no_cache/jc/zcnew/data/hist/" S "Zcrefer.js", False. Send Ms. Addcode "A=" . ResponseText for i = 1 to $ j = 0 to (i + 1, j + 36) = Ms.eval ("a[" Cells (i + 1, 1) "]." at (J)) Next J Next i End WithEnd Sub Copyright NOTICE: This article for Bo Master original article, withou
Question address: http://poj.org/problem? Id = 3071
Question: give you 2 ^ n football teams, and the probability that each team will defeat another team, and find the team with the highest probability of victory.
Question: DP [I] [J] indicates the probability of victory for the J team in the I game.
ACCode:
# Include
Test instructionsThere are 2*n only team to participate in the knockout of n theory, give any two teams to engage in the respective winning rate, the last remaining the highest probability of the team.Analysis:Probability dp,dp[i][j] Indicates the probability that the team J is still on the field after the end of the first round, Dp[i][j]=dp[i-1][j]*sum (Dp[i-1][k]p[j][k]) (1Code: Copyright NOTICE: This article for Bo Master original article, without Bo Master permission not reproduced. POJ 307
[Cpp]// ZOJ 3464 Rugby Football// Question# Include # Include # Define N 10005Int a [N];Int n, t, l;Int cmp (const void * a, const void * B ){Return * (int *) B-* (int *);}Int main (){Int T;Int I;Scanf ("% d", T );While (T --){Scanf ("% d", n, t, l );For (I = 1; I Scanf ("% d", a [I]);Qsort (a + 1, n, sizeof (a [0]), cmp );Double ans = 0;For (I = 1; I If (l> = a [I] * t ){L-= a [I] * t;Ans + = t;}Else {Ans + = l * 1.0/a [I];L = 0;Break;}}If (l =
Football
Link: http://blog.csdn.net/xuechelingxiao/article/details/38520105
2 ^ n teams in a single knockout match, each of which has the highest probability of winning the championship.
Idea: the simple probability DP problem is mainly about how to deal with the problem of which two teams are playing.
The DP equation is DP [I] [J] = Σ (DP [I-1] [J] * DP [I-1] [k] * P [J] [k]); // DP [I] [J] indicates the probability that the J team will win in the
Poj 3071 Football probability dp, poj3071
Question:
There are 2 * n teams participating in the n-theory knockout competition, giving the winning percentage of any two teams involved, and finding the team with the highest probability left.
Analysis:
Probability dp, dp [I] [j] indicates the probability that the team j is still on the field after the end of the I round, dp [I] [j] = dp [I-1] [j] * sum (dp [I-1] [k] p [j] [k]) (1
Code:
//poj 3071//sep9#
The Chinese women's softball team defeated the north with a 0-1 score in the 11th softball Championship and the Japanese team held at Beijing Fengtai Gymnasium on September 3. It really hurts me. I can't lose to anyone. Why should I lose to Japan. Then I lost my bid to the Australian team at on the evening of September 4.World Championship medals.The Chinese women's youth football team lost to the "stay at home" Korean team with an incredible score in
Football Link: http://blog.csdn.net/xuechelingxiao/article/details/38520105 2 ^ n teams in a single knockout match, each of which has the highest probability of winning the championship. Idea: the simple probability DP problem is mainly about how to deal with the problem of which two teams are playing. The DP equation isDP [I] [J] = Σ (DP [I-1] [J] * DP [I-1] [k] * P [J] [k]); // DP [I] [J] indicates the probability that the J team will win i
Question connection: BNU 34986 football on table
The table size is l, W, followed by the starting position of the ball Sx, Sy, and the moving vector dx, Dy. Then N is given, indicating that there are n rods, for each pole, first give the position X, and the number of people C on the pole, the width of the person, and then the distance between the person C. Now I want to talk about the probability that the ball can be represented by everyone.
Solution
// Football (aka soccer) // PC/Ultraviolet IDs: 110408/10194, popularity: B, success rate: average level: 1 // verdict: accepted // submission date: 2011-05-27 // UV Run Time: 0.020 S // copyright (c) 2011, Qiu. Metaphysis # Yeah dot net // it is complicated to read data. Others are the sorting and comparison functions. It is relatively easy, but error-prone. # Include
= Imread (' crayfish. jpg ') # parse the picture # parameter Configuration WC = Wordcloud (background_color= ' White ', # background color max_words=300, # Maximum number of words Mask=back_color, # with this parameter value plotted to draw the word cloud, when this parameter is not empty, width and height will be ignored max_font_size=100, # Displays the maximum value of the font font_path= "c:/windows/fonts/ Simhei.ttf ", # Solve the display font garbled problem, you can enter the c:/windows/
First look at the final effect:
Decomposition production steps:
The first step: Open Photoshop software, create a new file, fill the background color, not required here.
Step two: Select "Polygon Tool" here we need a 6-side shape, a new layer, such as drawing a graph, and then we continue to draw, (here to draw a graphic to create a new layer, in order to facilitate the modification!) get the picture effect
Step three: Here we have more layers, the layers
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