being all crashed by a student in K times.
Inputthere'll be multiple input cases. Each test case begins with the integers n, K. N is the number of rows and columns of the balloons (1 Outputfor each test case, print in ascending order all the colors of which is impossible to being crashed by a student in K Times. If There is no choice, print "-1".Sample Input1 112 11 11 22 11 22 25 41 2 3 4 52 3 4 5 13 4 5 1 24 5 1 2 35 1 2 3 43 350 50 5050 50 5050 50 500 0Sample Output-1121 2 3 4 5-1Test
. $ Divclass= "Div2"> $ Divclass= "Div3" >1 - Div> - Div> the Div> - BR>BR>Wuyi Divclass= "Div1">Journey toBR/>BR/>"Journey to the Monkey" is a mythical novel, which is loved by Chinese people.BR/> theDescribes the story of Tang's monk leading three apprentices to the western heavens.BR/>Four of people through 9,981 difficult, eventually become a fruition. - Divclass= "Div2"> Wu Divclass= "Div3" >2 -
integer which is the max Imum number of kids the teacher can pick.Sample Input2 3 31 11 22 32 3 51 11 22 12 22 30 0 0Sample OutputCase 1:3case 2:4Test instructions: There are g girls, b boys, M inquiry, girls mutual understanding, boys to know each other, girls and boys have m relationship. The teacher wants to find the most people from the boys and girls to play games, these people ask to know each other.Idea: It is also a new way to build a map. Boys know each other, girls know each other, th
In Mysql, to determine whether a point falls within a polygon and about geospatial data, you often need to process the associations between the two spatial data. There are many ways to handle this by writing program algorithms or calling the corresponding functions in the database. In the mysql database, http://dev.mysql.com/doc/refman/5.1/en/functions-for-testing-spatial-relations-between-geometric-objects.html I have made a detailed introduction, but it does not take a specific engineering pra
Strategic GameTime limit:20000/10000 MS (java/others) Memory limit:65536/32768 K (java/others)Total submission (s): 5783 Accepted Submission (s): 2677Problem Descriptionbob enjoys playing computer games, especially strategic games, but sometimes he cannot find the Solutio n fast enough and then he is very sad. Now he has the following problem. He must defend a medieval city, the roads of which form a tree. He has to put the minimum number of soldiers in the nodes so, they can observe all the edg
......Sno_of_streets eno_of_streetsThe first line of all data set contains a positive integer no_of_intersections (greater than 0 and less or equal to 120), Which is the number of intersections in the town. The second line contains a positive integer no_of_streets, and which is the number of streets in the town. The next no_of_streets lines, one for each street in the town, is randomly ordered and represent the town ' s streets. The line corresponding to Street K (k There is no blank lines betwe
output shoshould be printed on the standard output. for each given input data set, print one integer number in a single line that gives the result (the minimum number of soldiers ). an example is given in the following table:
Sample Input
40:(1) 11:(2) 2 32:(0)3:(0)53:(3) 1 4 21:(1) 02:(0)0:(0)4:(0)
Sample output
12
The minimum vertex overwrite always times out. Later I realized that the graph is a sparse graph, and the matrix save graph times out
Solution report
Question:
I will give you a matrix of balloons in the Matrix. One to 50 colors are available for balloons. I will ask you if you can remove the existing colors within K times (K chances for each color ), colors that cannot be eliminated are output in ascending order.
Ideas:
I thought for a whole morning, and I understood the wrong question. In the past, each type had K chances of elimination, and thought it was a total of K chances of balloon elimination.
It's easy to understand,
To give a matrix, there are some balloons of different colors. Each time you can destroy one row or one color balloon in a column, ask if you are within K times, which of the following colors cannot be used to remove balloons.
The idea is to find the minimum point of coverage for each color balloon, and> K is the answer.
It is equivalent to the enhanced version of poj3041, because not every vertex in the matrix is equivalent.
# Include
This question is a little different from that of poj 3041. This is not a whole line of elimination, but a few consecutive grids are eliminated together. Therefore, pay attention to this when composing a diagram, from top to bottom, each row is consecutively marked from 1 as the left set, and each column is numbered from 1 from left to right as the right set, then the Hungary algorithm calculates the maximum matching number = the minimum vertex overwri
Question:
There are N points on the two-dimensional plane... if the distance between two points is not greater than R and there are no other points in the line segment .. you can connect an edge .. ask now .. how many spanning trees does this graph have?
Question:
I think this question is so embarrassing... some knowledge of computing + magic matrix + Gaussian elimination element (at the same time, the reverse element is required )...
Edge construction... according to the requirements of the que
For details, please refer to the secret of the Photoshop image dot algorithm.
Http://blogread.cn/it/article/6198
In the past, global vertex operations, such as histogram equalization, brightness and contrast adjustment, were performed on the image in PS. The secret of PS efficient operations is here. It only needs to adjust the values of the 256 palette items, without having to operate on each pixel to get the correct result. Of course, if we ch
The error "esri. config. defaults. io. proxyUrl has not been set" occurs when the element in the circle with a certain vertex radius is queried by ArcGIS API for Javascript. esriarcgis
When Query is used, the following configuration is used:
var queryTask = new esri.tasks.QueryTask(applicationModelOneSearchPOIURL); var query = new esri.tasks.Query(); query.geometry = geometry; query.outSpatialReference = map.spatialR
Nyoj17 monotonically incrementing longest vertex sequence (DP)
Question 17
Question Information
Running result
Rankings
Discussion area monotonically incrementing maximum eldest son sequence time limit: 3000 MS | memory limit: 65535 KB difficulty: 4
Description
Returns the length of the longest incrementing sub-sequence of a string.
For example, the longest incremental sub-sequence of dabdbf is abdf and the length i
This problem is to minimize vertex overwrite. Note that when a task can be implemented using mode 0, edge can be left blank because no restart is required! If you finish all the 0 tasks and then change the machine, it is equivalent to the task without 0. Therefore, ignore the tasks that Mode 0 can do.
Open door! Yes!
Code:
# Include
I. Attributes1. What is an attribute?The property is defined by objective-C 2.0 and provides the default Implementation of the setter and getter methods for instance variables.It can simplify the program to a certain extent and enhance the access security of instance variables.2. Attribute DefinitionIii. KVCKVC (key-value-coding) is a key-value encoding method that indirectly accesses instance variables.Key: indicates the instance variables.Value: The value corresponding to the instance variable
Vertex buffer: 0 1 2 3 4 5 6 7 8Index Buffer: 3 0 4 1 5 2 5 5 8 4 7 3 6D3d understands triangle strip as follows: (3 0 4) (0 1 4) (4 1 5) (1 2 5) (5 2 5) (2 5 5) (5 5 5 8) (5 4 8) (8 4 7) (4 3 7) (7 3 6)ItsMedium (5 2 5) (2 5 5) (5 5 5 8) is called a degraded triangle because they both have only two vertices. They enable traiangleThe role of the Strip sequence from the end of row 0th to the end of row 1st. Then, in the new row, the triangle vertices a
Http://acm.hdu.edu.cn/showproblem.php? PID = 1, 1498
I didn't understand Khan at the beginning ~~
Take the X coordinate as the Y coordinate of the X set to correspond to an edge for each color coordinate of the Y set, and find the minimum vertex (horizontal or vertical, that is, the number of times to be shot) to overwrite the number of corresponding edges,
Code:
/*************************************** * *********************************> F
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