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. CASE_INSENSITIVE); // after adding the attribute, Patter. CASE_INSENSITIVE indicates case-insensitive regardless of Matcher m4 = p4.matcher ("java_java_java_ilovejava fdasfas"); StringBuffer sb = new StringBuffer (); int I = 0; while (m4.find () {I ++; if (I % 2 = 0) {m4.appendReplacement (sb, "java");} else {m4.appendReplacement (sb, "JAVA");} m4.appendTail (sb ); // adding the tail to the buf is a combination of the following parameters: Word Group "); Pattern p5 = Pattern. compile ("(\ d {3

} years, {1} months, {2} days. ", year, month, day);}else if (day = = 29){if (year% 4 = = 0 year%!! = 0 | | year% 400 = = 0){Console.WriteLine ("You entered the date is:" + year + "years," + Month + "month," + Day + "days.) ");}Else{Console.WriteLine ("You entered the wrong date!");}}Else{Console.WriteLine ("You entered the wrong date!") ");}}}Else{Console.WriteLine ("You entered the wrong date!") ");}}Else{Console.WriteLine ("The Month you entered is incorrect!) ");}}Else{Console.WriteLine ("Y

}Example: What is the day of the year when judging a certain month? Assume that February of this year has 28 days. int m1 = to, M2 =, M3 = To, M4 =, M5 = To, M6 =, M7 =-M8 = =, M9 = +, M10 = +, M11 = +;Console.WriteLine ("Please enter the month:");int m = Int. Parse (Console.ReadLine ());Console.WriteLine ("Please enter the date:");int d = Int. Parse (Console.ReadLine ());switch (m) {Case 1:Console.WriteLine ("+d+", "Day");Break ;Case 2:Console.WriteL

Namespace ConsoleApplication11{Class Program{static void Main (string[] args){int m1 = to, M =-, M2 = to, M3 =, M4 = To, M5 = +, M6 =-, M7 = to, M8 = +, M9 =, M10 = 31, M11 = +;Console.Write ("Please enter the Year:");int n = Int. Parse (Console.ReadLine ());Console.Write ("Please enter the month:");int y = Int. Parse (Console.ReadLine ());Console.Write ("Please enter a few days:");int r = Int. Parse (Console.ReadLine ());if ((n >= 1759 n {Console.Wr

Morning sun teacher told how to judge the leap year;//judgment is not a leap year, the normal years, is a multiple of 4 but not a multiple of 100;//Century year is a multiple of 400//Enter a year to determine if it is leap years//console.write ("Please enter a year:");int year = Int. Parse (Console.ReadLine ());if (year>0year {if (year%4==0year%100!=0| | year%400==0) {Console.WriteLine ("The number of years you enter is a leap year! "); }Else {Console.WriteLine ("The Year you entered is comm

The switch case where you learned the choice statement today is a multi-select scenario that you can use.Case:Enter the month and the number of the output is how many days this yearThe 1,3,5,7,8,10,12 month is 31 days a year.This year's February is 28 days the other is 30 intM1 = to, M2 = -, M3 = to, M4 = -, M5 = to, M6 = -, M7 = to, M8 = to, M9 = -, M10 = to, M11 = -; ----don't need to define the volume for December, because Con

static void Main (string[] args){while (true){int m1 = 31; int m2 = 28; int m3 = 31; int m4 = 30; int M5 = 31; int M6 = 30; int M7 = 31; int m8 = 31; int M9 = 30; int m10 = 31; int M11 = 30;Console.Write ("Please enter the month");int m = Convert.ToInt32 (Console.ReadLine ());Console.Write ("Please enter the date");int d = Convert.ToInt32 (Console.ReadLine ());Switch (m)//If CASE1 is set up, simply jump out of the switch's curly brace and proceed dire

[Root @ localhost ~] # MongoMongoDB shell version: 1.8.1Connecting to: test> DbTest> Show collectionsData_testSystem. indexesSystem. users> Db. data_test.find (). skip (3). limit (4) // query by PAGE, starting from 4th records, 4 records per page.{"_ Id": ObjectId ("4dd7c914b2d5f68db79cdf57"), "userId": "10010174", "userName": "Bill Tu4", "gender": "m4 ", "interests": {"game": "game4", "ball": "ball4 ","Other": "nothing4 "}}{"_ Id": ObjectId ("4dd7c914b2d5f68db79cdf58"), "userId": "10010175", "u

Test instructions:, the coordinates of P, Q, r three points are given, AB, BC, ac are divided into m1:m2, M3:M4, and E by the points F, D, and C, and the values of M1~M6 are given, and the coordinates of the three vertices A, B and D of ABC are obtained.The puzzle: According to the Meneraus theorem, if there are two triangles that are composed of:Conclusion: (BD/DC) x (ce/ea) x (AF/FB) =1To prove the omission, the direct use of the conclusion, the tri

Article Title: X-Window graphics card configuration common solution. Linux is a technology channel of the IT lab in China. Includes basic categories such as desktop applications, Linux system management, kernel research, embedded systems, and open source. Many new graphics cards cannot be supported by XFree86 at the moment, and XWindow configuration is always a problem. However, the frame buffer device of Linux 2.2.x can use the Super VGA feature of the video card through the

Article Title: general solution for LinuxX-window graphics card configuration. Linux is a technology channel of the IT lab in China. Includes basic categories such as desktop applications, Linux system management, kernel research, embedded systems, and open source. Many new graphics cards cannot be supported by XFree86 at the moment, and XWindow configuration is always a problem. However, the frame buffer device of Linux 2.2.x can use the Super VGA feature of the video card through the

Many new graphics cards cannot be supported by XFree86 at the moment, and XWindow configuration is always a problem. However, the frame buffer device of Linux 2.2.x can use the Super VGA feature of the video card through the vesa vbe 2.0 standard, and then use the XFree86 frame buffer Server (XF86_FBDev) you can use high resolution and high/true color for your XWindow. Currently, most new video cards on the market support the

replace them with indexes sorted by memory columns ." Not over yet, Ellison next introduced Oracle's latest M6-32 "Large Memory Machine", and said it is the world's fastest memory device. The number of M6 cores to be listed is twice that of M5, with 32 tb dram Memory configured. "It can quickly move data and process data in memory ." Ellison said the M6 system b

Extended display identification data (coming from http://en.wikipedia.org) Extended display identification data(Edid) Is a data structure provided by a computer display to describe its capabilities to a graphics card. it is what enables a modern personal computer to know what kind of monitor is connected. edid is defined by a standard published by the Video Electronics Standards Association (VESA ). the edid provided des manufacturer name, product

, MJ, S, Ti) indicates a = B + (a + (G (B, c, d) + MJ + Ti) HH (a, B, c, d, MJ, S, Ti) indicates a = B + (a + (H (B, c, d) + MJ + Ti) II (a, B, c, d, MJ, S, Ti) indicates a = B + (a + (I (B, C, D) + MJ + Ti) The four rounds (64 steps) are: First round Ff (a, B, c, d, M0, 7, 0xd76aa478) Ff (D, a, B, c, M1, 12, 0xe8c7b756) Ff (c, d, A, B, M2, 17, 0x242070db) Ff (B, c, d, A, M3, 22, 0xc1bdceee) Ff (a, B, c, d, M4, 7, 0xf57c0faf) Ff (D, a, B, c, M5, 12, 0x4787c62a) Ff (c, d, A, B,

Labwindows Literacy + skills stickers, CVI learning is essential Http://www.vihome.com.cn/bbs/viewthread.php? Tid = 4675Labwindows Literacy + skills stickers, CVI learning is essential1. What are the applicable users of CVI?(R2 p. g h $ T %? 8 Z # wcvi is a fast development environment based on ansi c and is suitable for C and C ++. Engineers who use VB, Vc, and BC controls to organize user interfaces. % S # E6 P; {8 x* W3 x $ E; {p m-Y8 P5 y l2. How many versions of CVI are available ?, T5 C *

, and the corresponding storage file is deleted after the collection or index is deleted. Of course, because the storage method is different, the lower version of the database cannot be directly upgraded to the Wiredtiger storage engine, and can only be implemented by exporting the imported data. MongoDB 2.4.12 Version [Mongodb@mongo-data-emergency-001.m6.momo.com mongodb_2_4_12]$ LLDrwxrwxr-x 3 MongoDB mongodb 4096 February 19:03 Local-rwxrwxr-x 1

find that the X component that affects v is the X-component and the X-components of the rotation of the z-axis, and for the Y of V the same is true for the z component. 2 row main sequence, column main sequence OpenGL It is recommended to use a one-dimensional array to represent this transformation matrix: typedef glfloat MATRIX16[16]; In order to quickly access the x-axis, y-axis, and z-axis, the array is represented by the column main sequence: [M0, M4, M8, M12] [M1, M5, M9, M13] [m2,

. Therefore, for applications, if you wantTo program graphics on framebuffer, you also need to do a lot of other work by yourself. II. Implementation and Mechanism of framebuffer in LinuxThe source file of framebuffer is in the Linux/Drivers/Video/directory. The total abstract device file is fbcon. C, which contains the source files related to various graphics/card drivers.// Take a good look at this file (1) Analysis of framebuffer Device DriversThe old VES