weather by latitude and longitude

Scalar functions: View code Create Function DBO. fn_getdistance (@ lngbegin real, @ latbegin real, @ lngend real, @ latend real) returns float as begin declare @ distance real declare @ earth_radius real set @ earth_radius = 6378.137 -- The earth's radius is already divided by 1000, so the following calculated values are kilometers and kilometers declare @ radlatbegin real, @ radlatend real, @ radlatdiff real, @ radlngdiff real set @ radlatbegin. = @ Latbegin * Pi ()/ 180.0 Set @ radlate

Recent projects need to use the positioning function, and to obtain the latitude and longitude of the current location, consult the data to organize the following code: function Locationposition () {var geolocation = new Bmap.geolocation ();Geolocation.getcurrentposition (function (r) {var city_lat = r.latitude;var city_lng = r.longitude;Cookies.set ("Save_city_latitude", City_lat);Cookies.set ("Save_city_

For example: Longitude: 10.123456 Latitude: 20.654321Get to the actual location according to the above coordinates (do not use Baidu map or the API of the map of Gao de)The code is as follows:Put it in latitude and longitude. Publicstringgetaddress (doublelatitude,doublelongitude) { geocodergeocoder=newgeocoder (this,

Because the Baidu map api,2.0+ and 3.0+ changes relatively big, API basically was completely changed, some students may 2.0+ API use is very familiar with, but update to 3.0+, but will encounter some small trouble (because the API has changed, you need to re-learn its API, the code will be re-written , which is more painful than egg). So here are some small examples, I hope to upgrade to the 3.0+ of the students have some help.1. How does the Baidu map API map move to the specified

This example describes how PHP calculates the distance between two coordinates (longitude, latitude). Share to everyone for your reference. Specific as follows:Here we use PHP to calculate the distance between two coordinates (longitude, latitude) and return the result to meters or kilometers.function distance($lat1, $

At a very young age, the teacher told us that any place on earth could be determined by latitude and longitude. The warp and weft are also marked on the paper map. When you use the Baidu map, you will see the warp and weft? Will you pay attention to the coordinates of a place, latitude and longitude? This article tells

The formula is as follows, unit meters:1th latitude and Longitude: lng1 LAT12nd latitude and Longitude: lng2 lat2Round (6378.138*2*asin (sqrt (POW (LAT1*PI ()/180-lat2*pi ()/180)/2), 2) +cos (Lat1*pi ()/180) *cos (LAT2*PI ()/180) * Pow (Sin ((Lng1*pi ()/180-lng2*pi ()/180)/2), 2)) *1000)For example:SELECTSTORE_ID,LngLa

Tags: long search limit Data sel technology share structure latitude and longitude return database table Structure 2. The key is this SQLSELECT Address_, Longitude_, Latitude_, ROUND (6378.138 * 2 * ASIN (SQRT (POW () (? * PI ()/180-latitude_ * PI ()/180)/ 2), 2) + cos (? * PI ()/+) * cos (latitude_ * PI ()/+) * POW (SIN ((? * PI ()/180-longitude_ * PI ()/180)/2), 2)) ) * +) as Distance_um from xf_l

We often do projects when the use of mobile phone to obtain positioning, and then pass data to the background, which is iOS8 according to the latitude and longitude of the display name of the demo 1. Import Frame // Nearbyviewcontroller.m Neardemo // Created by Apple on 14/12/5. Copyright (c) 2014 Youdianshang. All rights reserved. // #import #import @interface Nearbyviewcontroller () { Nsuserd

Latitude algorithm $pi80 = m_pi/180; $lat 1=34.7465763; $lng 1=113.65778739999996; $lat 2=34.684795; $LNG 2=112.43594499999995; $lat 1 *= $pi; $LNG 1 *= $pi; $lat 2 *= $pi; $LNG 2 *= $pi; $r = 6372.797; Mean radius of Earth in miles $dlat = $lat 2-$lat 1; $DLNG = $lng 2-$LNG 1; $a = sin ($dlat/2) *sin ($dlat/2) +cos ($lat 1) *cos ($lat 2) *sin ($DLNG/2) *sin ($DLNG/2); $c = 2 * atan2 (sqrt ($a), sqrt (1-$a)); $km =round ($r * $c, 2);//return

By latitude, the database is compared stringbuffer SB = new StringBuffer () sb.append ("Select TimeKey,") Sb.append ("ROUND (6378.138*2*asin ( SQRT (POW (Sin (*pi ()/180-lat*pi ()/180)/2), 2), Sb.append (+cos (? *pi ()/180) *cos (Lat*pi ()/180) *pow (Sin ((? *pi ()/) ); Sb.append ("180-lng*pi ()/180)/2), 2)) *1000) as JL") Sb.append ("From T_news have JL Mysql takes a distance comparison between the specified lati