weather by latitude and longitude

Recently I used the formula for calculating the distance between two points on the earth's surface based on latitude and longitude, and then implemented it using JS. Based on the fact that the earth is a smooth sphere and not a real sphere, there are two ways to expand the sphere. If you are interested, you can use JavaScript to calculate the distance between two points on the earth based on the

monitoringLocationmanager.requestlocationupdates (Locationmanager.gps_provider, Watts, new Locationlistener () { public void onstatuschanged (String provider, int status, Bundle extras) { } public void onproviderenabled (String provider) { } public void onproviderdisabled ( String provider) { } public void onlocationchanged (Location Location) { Updatetonewlocation (location); } }); } private void Updatetonewlocation (Location Location) { TextView TV1;TV1 = (TextView) This.fi

In the use of Baidu API to query the latitude and longitude of multiple addresses, because the Baidu API provides latitude and longitude Query method is a callback function, and subsequent operations must be achieved by latitude to complete to proceed, the problem exists in

1/** 2 * use Baidu to convert the longitude and latitude information to address information. 3*4 * @ Param longpolling longitude 5 * @ Param latitude Latitude 6 * @ Param coordtype coordinate system: Running result: 1 public static void main (string [] argv) {2 dbobject OBJ

This article describes the Java implementation of the Geohash into the corresponding latitude and longitude of the coordinates of the detailed code, to share with you for your reference, the specific content as follows Package Com.lulei.geo; Import java.util.ArrayList; Import Java.util.Arrays; Import Java.util.HashMap; Import java.util.List; Import Com.lulei.geo.bean.LocationBean; Import Co

: = Z * cos (T) + 0.0065;EXCEPTIONWhen OTHERS ThenNULL;END;Test code:DeclareVal varchar2 (1024);Lat number;LNG number;BeginLat: = 25.123456;LNG: = 120.987654;Google2baidu (LAT,LNG);Val: = To_char (lat) | | ', ' | | To_char (LNG);Dbms_output.put_line (Val);Baidu2google (LAT,LNG);Val: = To_char (lat) | | ', ' | | To_char (LNG);Dbms_output.put_line (Val);EndOutput Result:25.12950357111129114394070387150607218949, 120.9941596847708026959269928710265389825.12345611379500842252418931941721965068, 120.

= 3.1415926;x = x/1000000.0;y = y-500000.0;BF = 9.04353692458*x-0.00001007623*pow (x,2.0) -0.00074438304*pow (x,3.0) -0.00000463064*pow (x,4.0) +0.00000505846* Pow (x,5.0) -0.00000016754*pow (x,6.0);HBF = BF * pi/180.0;SA = 6378245.0;SB = 6356863.019;SE2 = 0.006693421623;SEP2 = 0.006738525415;W1 = sin (HBF);W2 = 1.0-se2 * POW (W1, (double) 2);W = sqrt (w2);MF = sa* (1.0-SE2)/pow (W, (double) 3);W3 = cos (HBF);W4 = POW (SA, (double) 2) *pow (W3, (double) 2) + POW (SB, (double) 2) *pow (W1, (doub

Recently used in accordance with the latitude and longitude calculation of the Earth's surface two distance between the formula, and then use JS to achieve a bit. There are probably two ways to calculate the distance between two points on the Earth's surface. The first is the default Earth is a smooth spherical surface, and then calculate the distance between any two points, this distance is called the Grea

Java known two locations latitude and longitude distance (very accurate) Package com.lbnet.lzx.util; public class GoogleMap {Private static final Double Earth_radius = 6378.137;private static Double rad (double D){return d * math.pi/180.0;}/*** ????}????????????? /γ???* @param LAT1* @param lng1* @param lat2* @param lng2* @return*/public static double Getdistance (double lat1, double lng1, double lat2, dou

Baidu Map, to achieve vehicle trajectory mapping Implementation ideas: 1. Vehicle trajectory mapping according to latitude and longitude 2. Using the Baidu Map API two overlay implementation, Polyline (polyline) Draw track, Marker (icon) to draw the car icon 3. Connect each of the two coordinates to form a coherent trajectory line 4. After the next icon is generated, delete the last drawn icon to create a c

data from the program9876543 9876543.12 9876540mysql> INSERT into T1 values (1.21, 1.12,1.21);1. In Toad for MySQL, the display isC1 C2 C31.21 1.12 1.212. The display in MySQL Query browser isC1 C2 C31.21 1.12 1.213. Remove data from the program1.21 1.12 1.21mysql> INSERT into T1 values (1.2, 1.2,1.2);1. In Toad for MySQL, the display isC1 C2 C31.2 1.20 1.22. The display in MySQL Query browser isC1 C2 C31.20 1.20 1.23. Remove data from the program1.2 1.20 1.2mysql> INSERT INTO T1 values (987654

1 DROP FUNCTION IF EXISTS ' getdistance ';2 DELIMITER;;3 CREATE FUNCTION ' getdistance ' (4Lon1 Float (10,7) 5, Lat1 float (10,7)6, Lon2 float (10,7) 7, Lat2 float (10,7)8 ) RETURNS Double9 beginTen declare d double; One declare radius int; ASet radius = 6378140; -Set D = (2*atan2 (SQRT (SIN (LAT1-LAT2) *pi ()/180/2) -*sin ((LAT1-LAT2) *pi ()/180/2) + theCOS (Lat2*pi ()/180) *cos (LAT1*PI ()/180) -*sin ((Lon1-lon2) *pi ()/180/2) -*sin ((Lon1-lon2) *pi ()/180/2)), -SQRT (1-sin (LAT1-

drawingMmapview.onpause (); } @Overrideprotected voidonsaveinstancestate (Bundle outstate) {Super. Onsaveinstancestate (outstate); //mmapview.onsaveinstancestate (outstate) is executed when activity executes onsaveinstancestate, saving the current state of the mapmmapview.onsaveinstancestate (outstate); } @Override Public voidOnmapclick (latlng latlng) {amap.clear (); Latitude=Latlng.latitude; Longtitude=Latlng.longitude; Markeroptions markeroptions=

public class GetLocation {public static void main (string[] args) {//lat 39.97646//log 116.3039 String add = Getadd (" 116.3039 "," 39.97646 "); Jsonobject Jsonobject = Jsonobject.fromobject (add); Jsonarray Jsonarray = Jsonarray.fromobject (jsonobject.getstring ("addrlist")); Jsonobject j_2 = jsonobject.fromobject (jsonarray.get (0)); String Alladd = j_2.getstring ("Admname"); String arr[] = Alladd.split (","); System.out.println ("Province:" +arr[0]+ "\ n City:" +arr[1]+ "\ n area:" +arr[2]);}

This article describes how to use the Baidu map api to query the longitude and latitude Based on the address, attach an instance, and recommend it to friends who need it. The Code is as follows: Query longitude and latitude by address

　　[Self.locationmanager stopupdatinglocation];}@end#pragmaThe mark-delegate method is used to implement the update of the location-(void) Locationmanager: (Cllocationmanager *) Manager didupdatelocations: (Nsarray *) locations{//the current location of the deviceCllocation *currlocation =[Locations Lastobject]; NSString*latitude = [NSString stringWithFormat:@"Latitude:%3.5f", CurrLocation.coordinate.latitud

Mobile is the biggest feature of mobile phones and handheld devices. You can use the ddms view of eclipse to simulate device location changes, change the longitude and latitude, click send, and run the program. In the application, dynamically obtain the device location and display the current location information. There are three steps to obtain location information:1. Add system permissions to support acc

// Calculate AreaPublic static double calcarea (arraylist pointx, arraylist pointy, string mapunits){ Int COUNT = pointx. count;If (count> 2){Double mtotalarea = 0; If (mapunits = "Degrees") // spherical polygon under the coordinate of latitude and longitude{Double lowx = 0.0;Double Lowy = 0.0;Double middlex = 0.0;Double middley = 0.0;Double highx = 0.0;Double highy = 0.0; Double AM = 0.0;Double Bm = 0.0;Do

=-D11 * a * (1-E * E)/6;Fe = E11 * a * (1-E * E)/8;Fg =-F11 * a * (1-E * E)/10; C [0] = fa;C [1] =-(FB * 2 + FC * 4 + FD * 6 );C [2] = (FC * 8 + FD * 32 );C [3] =-FD * 32;/*************************************** *******54 coordinate system computation result have difference fromThe known value; but I don't find fault.Known: CO 6367558.49686C1 1, 32005.79642C2. 133.86115C3 1, 0.7031Compute:Co 1, 6367558.4968746C1 1, 32005.780305529C2. 133.9203503C3 1, 0.7041**************************************

successful");} else {system. out. println ("search failed");} public class mysearchlistener implements mksearchlistener {public void ongeta Ddrresult (mkaddrinfo arg0, int arg1) {/** returns the address information search result. Parameter: arg0-arg1-error no. In the search result, 0 indicates that the result is correct, and result indicates that the result is correct. 100 indicates that the result is correct and no relevant address information */string location = NULL; if (arg0 = NULL) {locati