where find itin number

InputNumber of digits nMinimum starting at 4, output n ascending numbersOutputs the sum of the number of mass numbers between any two numbers34612Out6Do not know where is wrong, solve:#include #include #include #include using namespace Std;BOOL Yes (int i){int a=0;for (a=2; a{if (i%a==0){return false;}}return true;}int Xunzhao (int a,int b){int counts=0;for (int c=a; c{if (yes (c)){counts++;}}return counts;}int Zhishu (int *arr,int num,int z){int left

Search for the number of objects closest to the array [java]/*** to find the number closest to the target value, and returns * @ param array * @ param targetNum * @ return */public static Integer binarysearchKey (Object [] array, int targetNum) {Arrays. sort (array); int targetindex = 0; int left = 0, right = 0; for (right = array. length-1; left! = Right;) {int

#include This article is only in the learning process of their own ideas, can only achieve simple functions, may not consider the optimization of the program, and the code written by the great God there is a certain gap, if the great God found the problem, please enlighten me, if you have a better way, may wish to share, thank you!This article is from the "Sharing Progress" blog, be sure to keep this source http://xmwen1.blog.51cto.com/10730069/1706070Only one

Why do I always make these stupid mistakes, or my logic is not rigorous enough. Try ing ...1#include 2#include 3#include 4#include 5 using namespacestd;6typedefLong LongLL;7LL x;intN;8 intMain ()9 {Ten One while(~SCANF ("%d",N)) { A intsum=0; LL ans; - for(intI=1; i) { -scanf ("%lld",x); the if(sum==0) { -ans=x; -sum++;//easy wrong I was too stupid ... - } + Else { - if(X==ans) sum++; + Elsesum--; A

Package Com.lianxi; /** * Find the index and value of the first number larger than the left, smaller than the right number * * @author Administrator * */public class found {/** * @param args * * * public static void Main (string[] args) {//TODO auto-generated method Stub int[] A = {1, 6, 4, 5, 6,6, 9, km}; GetIndex (a);} public stat IC void GetIndex (int[] a) {fo

/* This is a free program, you can modify or redistribute it under the terms of GNU * Description: Find the largest number of data in a large amount of data * language: c ++ * Development Environment: vc6.0 * Author: wangzhicheng * E-mail: 2363702560@qq.com * Date: 2012/10/31 * // ** use the quick sort method for search, first, put the entire data to be searched into the vector in STL, then, Recursively sea

Topics N Numbers (0,1,..., n-1) Form a circle, starting with the number 0, each time the number of m digits is removed from the Circle (the first is the current number itself, the second is the next number of the current number). When a

On the topic of water King--find the number of occurrences greater than/equal to half the length of the array1. Title DescriptionAn array of length n, in which some numbers appear more frequently. Please find the number of occurrences greater than half the length of the array. (Water King 1)an array of length n, in whi

Find the Duplicate number Topic Connection: Find the Duplicate number descript Given an array nums containing n + 1 integers where each integer is between 1 and N (inclusive), prove that at least one D Uplicate number must exist. Assume that there are only one duplicate

There is a series of integers, the number of numbers is indefinite, a total of N, to find out the number of the most frequent (the original question is to find the number of occurrences greater than the N/2) What is the general algorithm for this problem? General algorithm

The BFPRT algorithm is a classical algorithm for finding the smallest number of K or the smallest number of k in linear time. For example, we want to know that sales are the first few goods or the most visited the first few sites, we do not need to sort, with the BFPRT algorithm can be completed. BFPRT algorithm is also called fast selection algorithm, its idea is to use the division of Fast sorting to dete

The following: Define a Niconico-number, if X is Niconico-number, then all integers less than x and x coprime are a arithmetic progression, initially giving an array of n numbers, three operations: 1 L r Q How many niconico-number numbers are there in [L,r] 2 L R v for all numbers in [l,r] to V 3 k x Changes the number