Topic Links:http://acm.hdu.edu.cn/showproblem.php?pid=1892Main topic:The main topic: There are many squares, each grid corresponds to the coordinates (I,J), at the beginning of each lattice there are 1 books, and then let you count a region how many books, can also increase the book and reduce, mobile books.Problem Solving Ideas:Direct two-dimensional array array simulationAttention:Each subscript +1, starting from (1, 1)X1 Y1 and X2 y2 are not standa
1) Original Code representationThe original code notation is a simple representation of the number of machines. The sign bit with 0 for a positive sign, with: to denote a minus, the value is generally expressed in binary form. With a number of x, the original code is denoted as [x] original.For example, x1= +1010110X2= 11,001,010The original code is written as:[X1] Original =[+1010110] Original =01010110[X2
The use of simple functions of the R language:"C () is a connection function, the middle of the data representation of the vector, the connection between the middle of the data representation vector, X1 Mean () is the mean function, and mean (X1) represents the standard deviation of the computer array X1.SD () is the standard deviation function, and SD (
Import Java.math.BigInteger;1. Create a new objectScanner in = new Scanner (system.in);BigInteger x1 = new BigInteger ("11"); Create a new objectBigInteger x2 = In.nextbiginteger ();//Keyboard inputBigInteger y = x1.abs (); Take absolute valueBigInteger y2 = x1.add (y); X+yint x3 = Y.compareto (x1); X and y Comparison
bottom up (that is, starting from the node with the array sequence number zero), the upward layer is judged
* The left side of the parent node, the code is 0, if on the right side, the code is 1. The last output generated encoding.
*------------------------------------------------------------------------*/
#include
#define MAXBIT 100#define MAXVALUE 10000#define MAXLEAF 30#define Maxnode maxleaf*2-1
typedef struct { int bit[maxbit]; int start; } hcodetype;/* encoded struct */ typed
learning can be used to compress data, visualize, obtain effective distance matrix, etc.
Fig. 2 Manifold Learning
3. Several dimensionality reduction method Flow 3.1 principal component Analysis PCA
PCA, invented by Karl Pearson in 1901, is a linear dimensionality reduction method in which a point xi= (x1,x2,..., XD) of a high dimensional space (dimension D) is mapped to a point in a low dimensional space (dimension d,d
So the covariance matrix
integer, (int) (sqr + 0.9999999) will not carry, x = y. Not an integer.
If it is an integer, sqrt (delta) is first calculated.
(2) When sqrt (delta) is not an integer
Yes. Keep the root number!
Note: This small program was initially annoyed by the wide variety of pitfalls in solving mathematical problems. I want to finish my homework quickly ~~ So I wrote this article by the way after I finished my homework on that dark evening.
How to use C language to compile a program for solving the quad
It is the second time that you have encountered this problem:1#include 2 using namespacestd;3 4 5 Const intN the);6 7 intdp[n][2][n][2][n];8 intx1, x2, y1, y2;9 Ten intDfsintX1,intSintX2,intTinty) { One int now=Dp[x1][s][x2][t][y]; A if(~now)returnNow ; - intsum=0, cnt=0; - if(s==0){ theSum+=dfs (x1,1, x2, T, y1), cnt++; - if(t==0) -Sum+=dfs (x1, S, x2,1, Y1), cnt++; - El
MatrixTime Limit: 3000 MS Memory Limit: 65536 KTotal Submissions: 13137 Accepted: 4948DescriptionFor a given matrix (initially 0), maintain two operations:1. C x1 y1 x2 y2 (1 2. Q x y (1 Input www.2cto.comNumber of first behavior data groups X (X The first behavior of each group of data is N, T (2 The next T line is Q or C.OutputOutput all the question results.Press Enter next to each group of data.Sample Input12 10C 2 1 2 2Q 2 2C 2 1 2 1Q 1 1C 1 1 2
PostersProblem DescriptionThere are a lot of posters, each of which is subtracted from a rectangle (which may be totally subtracted). Now we have given the positions of no posters, asking for their area and.Ensure that the coordinates are between (0, 0) and (50000,500 00. No posters are hashed, and the side of the rectangle subtracted is parallel to the x and Y axes.InputThere is a lot of data.For each group of data, the first row has an integer N (0
The data ends with 0.
OutputOutput a row of
1743: Solution Equation descriptionA group of Ultraman defeated a group of small monsters, known all Ultraman have X1 head, y1 leg (mutation Ultraman), all the small monsters have x2 head, y2 leg. Battlefield on a total Q head, W leg, asked how many Ultraman, how many small monsters?InputThe input data has several groups each group contains 6 positive integers, respectively, x1,y1,x2,y2,q,w; (0OutputThe out
The main topic: the shortest distance from (0,5) to (10,5), between the starting point and the end point there are N wall, each wall has 2 doors.Topic idea: Judge whether there is a wall between two points (to determine whether the connection of two points with a wall of the line intersection), to establish a diagram, and then the shortest possible to find out on it.#include #include#include#include#include#include#include#include#defineINF 0x3f3f3f3f#defineMAX 1005DoubleMap[max][max],dist[max];
http://www.lydsy.com/JudgeOnline/problem.php?id=3122Test instructions: Give the p,a,b,x1,tKnown xn=a*xn-1+b%p, to find the smallest n order xn=tFirst, if x1=t, returns 1If a=0, then if B=t returns 2, no solutionIf a=1, then t=t-x1+p%p, you can list the equationB*x+p*y==t% PIf a>=2, then according to geometric series and availablexn=t=
DescriptionThere is a spherical space generator capable of producing a hard sphere in n-dimensional space. Now that you are trapped in this n-dimensional sphere, you only know the coordinates of the n+1 points on the sphere, and you need to determine the spherical coordinates of the n-dimensional sphere as quickly as you can to destroy the sphere space generator.Analysis
The distance from each point to the center of the circle is equal
The distance between points in n-dimension
Thinking: matrix and transformation, and the application of matrix in DirectX and OpenGL
1. Matrix and linear transformation: one-to-one correspondence
A matrix is a tool used to represent linear transformations. It corresponds to linear transformations one by one.Consider linear transformation:A11 * x1 + a12 * x2 +... + a1n * xn = x1'A21 * x1 + a22 * x2 +... +
following example shows that the result is very interesting:
This method is only exploratory and empirical. It may be wrong from a strict mathematical model. However, the results in actual use are good enough, and this method only requires the minimum amount of computing. The following code is used to draw the image of the lion above. These codes are not optimized and are only used for demonstration. Some variables are calculated twice. In the actual program, if the same variab
some practical skills in gradient descent calculation. The first is the feature scaling method.
If you have a machine learning problem that has multiple features. If you can ensure that these features are in a similar range (ensure that the values of different features are within a similar range), then the gradient descent method can converge faster.
Specifically, if you have a problem with two characteristics, X1 is the area of the house, and
Portal: http://acm.hust.edu.cn: 8080/judge/contest/view. Action? Cid = 12255 # OVERVIEW
When I started reading question a, I thought it was a simple deep search...
The K-question lightoj 1414 calculates the number of months in a given year, that is, the number of years in a leap. Based on the formula used to calculate the leap year, we can release it.
R/4-r/100 + R/400-(L/4-L/100 + L/400 ). Then judge the beginning and end.
if(strcmp(month2,"January")==0||(strcmp(month2,"February")==0)d
The backtracking method is also called the testing method. This method first gives up the limit on the size of the problem temporarily, and enumerates and tests the problem in a certain order. When it is found that the current explain solution cannot be a solution, select the next explain solution. If the current explain solution does not meet all other requirements except the problem scale requirements, continue to expand the scale of the current solution, and continue testing. If the current f
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