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("Please select: \ n"); Student class3[ to]; return 0;}11.1#include voidAddint*p){ intI,add=0; for(i=0;i5; i++){Add=add+* (P+i);} printf ("%d", add);}intMain () {intA[]={22,33,44,0, One}; int*p=A; Add (p);return 0;}11.2#include #includestring.h>intMain () {Chara[5]; Char*p; P=A; inti,j,t; printf ("Please enter a string:"); for(i=0;i5; i++) scanf ("%c",P[i]); for(i=0;

; Auto Boxingi + = 1; Automatic unpacking and Automatic packingThe second question:See how the program writes results　1 public classIntegerdemo {2 public Static voidmain (string[] Args) {3Integer I1 =NewInteger (127);4Integer i2 =NewInteger (127);5System.out.println (i1 = =i2);6 System.out.println (i1.equals (i2));7System.out.println ("-----------");8 9Integer i3 =NewInteger (128);TenInteger I4 =NewInteger (128); oneSystem.out.println (i3 = =i4); a System.out.println (i3.equals (i4)); -System.

Go versions: Go version go1.4.2 linux/amd64 Test environment: [[emailprotected]mpro]#more/proc/cpuinfo|grep "Modelname" model name:intel (R) core (TM) i5-4590CPU@ 3.30ghzmodelname:intel (R) core (TM) i5-4590CPU @3.30ghzmodelname:intel (R) Core (TM) I5-4590cpu@3.30ghzmodelname:intel (R) Core (TM) i5-4590CPU@3.30GHz[[e

This question To[i][j] for the first person to send J this gift probability we use 13 to compress this left the number of gifts, so we will dp[i][k] expressed as the first person to put the gift after the state is K, then through the memory of the search we get the state probability that we want to Dp[i][k]+={dp[i+1][k-aj]*to[i][aj]}, well now if I go get the first gift I right probability, we can first know good friend put first probability forAssuming S is the state of the original giftPop=dp[

1. There are 5 students, each of whom has a test score of 3 courses in Chinese, maths and foreign languages. Programming statistics The total score and average scores of each student and the average score of all students in each section. Requires that the results be initialized in the program, and the result is output in tabular form. #include intSumintscore[5][3],Doubleave[]);intMain () {intscore[5][3]={{Ten, -, -},{Ten, -, -},{Ten, -, -},{Ten, -, -},{Ten, -, -}}; inti,j,sum1,sum2,

1. How arrays are accessed(1) Accessing The elements in the array as subscripts: a[i];(2) To access elements in the array as pointers : * (a+i)2. subscript form VS pointer form(1) When moving in an array with fixed increments in the form of pointers, the efficiency is higher than the subscript form(2) Higher efficiency when the pointer increment is 1 and the hardware has a hardware increment model(3) The conversion of subscript form and pointer form:a[n]==* (a+n) ==* (n+a) ==n[a];▲ Note:① Moder

1.#include voidSumint*P)//sum all elements and output the result{ inti,sum=0; for(i=0;i5; i++) Sum=sum+*p++; printf ("sum result is%d", sum);}intMain () {inta[]={1,3,5,7,9}; int*p=A; SUM (p);return 0;}2.#include #includestring.h>intMain ()//output 5 strings in order from small to large{ Chara[5]; Char*p; P=A; inti,j,t; printf ("Please enter a string (up to 5 characters):"); for(i=0;i5; i++) scanf ("

1. compatibility of string classes(1) The String class maximizes the compatibility of C strings(2) You can use a string object in the same way that you use C strings , such asstring " ABCEDEFG " ; char c = s[i];The "Programming Experiment" uses the string class in C mode#include #includestring>using namespacestd;intMain () {strings ="a1b2c3d4e"; intn =0; for(intI=0; I) { if(IsDigit (S[i]))//use a String object (that is, an array) in C-strings{n++; }} cout//4 return 0;}2. How object

external functions (the purpose is to make the caller more aware of the detailed meanings of each number of workers) // computercpu, withcomputerharddisk, withcomputermemory, withcomputermonitor is an external worker. // func setcomputerconfig must be included in the call. (computercpu: String, withcomputerharddisk HD: String, withcomputermemory mem: String, withcomputermonitor Mon: string) {Self. CPU = CPU self. harddisk = HD self. memory = mem self. monitor = mon} // use # To promote the vari

Device Name Old Model(CPU/yen price) New Model(CPU/yen price) YenLattice difference 13 inchMacBook Pro Core 2 Duo 2.26 GHz0.11 million 8800 bytes Core 2 Duo 2.4 GHz0.11 million 4800 bytes 4000 bytes Core 2 Duo 2.53 GHz0.14 million 8800 bytes Core 2 Duo 2.66 GHz0.13 million 8800 bytes 10 thousand bytes 15 inchMacBook Pro Core 2 Duo 2.53 GHz0.16 million 8800 bytes Core i5 2.4 GHz0.16 million 8800

Triangle operation(%i1) trigexpand(sin(10*x+y));(%o1) cos(10 x) sin(y) + sin(10 x) cos(y)(%i2) trigexpand(sin(2*x));(%o2) 2 cos(x) sin(x)(%i3) trigsimp(2*cos(x)^2+sin(x)^2); 2(%o3) cos (x) + 1(%i4) trigreduce(-sin(x)^2+3*cos(x)^2+x);cos(2 x)cos(2 x) 11(%o4) -------- + 3 (-------- + -) + x - - 2 2 22 Algebraic reasoning(%i1) assume(x>0,y(%o1)[x > 0, y (%i2) assume(a(%o2) [b > a, c > b](%i3) facts();(%o3) [x > 0, - 1 > y, z >= 0, b > a, c > b](%i4) is(a>c);(%o4)false(%

. out) A single row contains a list of the shortest moving orders that point all pointers to separated by spaces. If there are multiple solutions, output the one that makes it connect to the smallest number. (For example, 5 2 4 6 SAMPLE INPUT 9 9 126 6 66 3 6 SAMPLE OUTPUT 4 5 8 9 Analysis:Use 0, 1, 2, and 3 to indicate the clock status, indicating, respectively.Repeated results are generated after four operations, so 0 ~ 3,4 ^ 9 is also very limited,The status is small, and the impact of opera

following method is used, you canSet both the header and footer. Specifically, move the mouse to the worksheet name, right-click the worksheet, select the "select all worksheets" menu item in the pop-up menu, and then set the header and footerAll worksheets. 86. Determine the score level and count the number of people in each score segment In H5: h24, enter a number ranging from 50 to 100, click the I5 cell, and enter the formula = If (H5> = 85, "ex

expanded, my details are too small, and some have no focus. Will be updated and supplemented slowly. Comments and suggestions are welcome:-I Intel targeted I/O virtualization technology (VT Intel's targeted I/O virtualization technology (VT-d) is an extension of Intel's virtualization technology (VT), which provides assistance with virtualization solutions to hardware. Based on the existing virtualization support for IA-32 (VT-x) and anteng processor (VT-I), VT-d has also added support for I/O

. out. print ("String type is s1 = s2:"); System. out. println (s1 = s2); System. out. println ("-----"); String s3 = new String ("abc"); String s4 = new String ("abc "); // We can see that = compares whether the stack address is the same as the System address. out. print ("String type with new String () is s1 = s2:"); System. out. println (s3 = s4); System. out. println (s1 = s3); System. out. println ("-----"); Integer i1 = 1; Integer i2 = 1; System. out. print ("the packaging type is i1 = i2:

Package com. jzm. Data; Public class testbox {/*** @ Param ARGs*/Public static void main (string [] ARGs ){Integer I1 = 100;Integer I2 = 100;Int I5 = 100;Integer I3 = 200;Integer I4 = 200;Int I6 = 200;If (I1 = I2 ){System. Out. println ("I1 = I2 ");}Else {System. Out. println ("I1! = I2 ");}If (I1 = I5 ){System. Out. println ("I1 = I5 ");}Else {System. Out. print

from it.Source:The array length is 5.1#include 2 3 intMain ()4 5 {6 7 intarr[5];8 9 inti,j;Ten One intmax[5]; A -cout"input Array (five numbers):"Endl; - the for(i=0;i5; i++) - - { - +Cin>>Arr[i]; - + } A at for(i=0;i5; i++) - - { - -max[i]=Arr[i]; - in } - to for(j=0;j4; j + +) + - { the * for(i=j+1;