I believe there have been a lot of articles on the memory alignment mechanism on the Internet. Here, I just want to use a small example to illustrate the memory allocation phenomenon.
There is a piece of code like this:
//: Memory alignment _ 2 # include
As for why the address is incremental, I will not explain it much (the sequence in which the compiler is pushed into the stack). I will debug it in VC 6.0 to understand. m1,. m2,. m3 alignment in m
be converted using the formula. We still need to look up the table.
Obviously, only 50400 code bits are used in the 39420 code bits, and the remaining code bits are retained. For fun, let's calculate the position of the last non-reserved code bit (0 xFFFF). The calculation process is as follows:
M1 = (39420-1)/12600 = 3
N1 = (39420-1) % 12600 = 1619
M2 = N1/1260 = 1619/1260 = 1
N2 = N1 % 1260 = 1619% 1260 = 359
M3 = n2/10 = 359/10 = 35
N3 = N2
1. Problem description:
There are four modules in system s: M1, M2, M3, and M4. Each module is a Web application. Sessions in one module cannot be read from other modules.
2. cause:
A Web application is equivalent to a site, and the session cannot be shared between the application and the application.
3. solution:
1) include four web applications in the same solution
(Note: Adjust the. webinfo file to make the solution work properly)
2) create
Problem descriptionThe solution S is established using Asp.net. There are four modules in S: M1, M2, M3, and M4. Each module is a Web application. Sessions in one module cannot be read from other modules.
CauseA Web application is equivalent to a site, and the session cannot be shared between the application and the application.
Solution1) include four web applications in the same solution ,:The actual directory storage structure is as follows:(No
any time and 8 bytes aligned at the invocation entry.In this convention, the 4-byte alignment of the stack does not have to be adhered to at any time, and it is difficult to do so, because the last two bits of the SP are kept 0 on the hardware. For 8-byte alignment, this requires code farmers and compilers to work together. One point to note is that 8-byte alignment even if you do not follow, in some cases also no problem, as long as the keynote and the use of the two-way side of the stack used
is-d,d,d to calculate the M2 point coordinates:Solution: =The upper distance value is d,-d,d to calculate the M3 point coordinates:Solution: =The upper distance value D,d,-d calculates the M4 point coordinates:Solution: =From the above solution can be seen through the above method can be obtained four coordinate points of the rotating platform, in the absence of other constraints, we can rotate the rotating platform three times and record the corresp
squaresInt[][] result = new Int[a.length][a.length];if (a.length = = 2)//If A and B are all 2-step, the recursive end conditionresult = Strassmul (A, b);else//otherwise (i.e., A and B are 4,8,16 ...){Four sub-matrices of aint[][] A00 = Copyarrays (a,1);int[][] A01 = Copyarrays (a,2);int[][] A10 = Copyarrays (a,3);int[][] A11 = Copyarrays (a,4);Four sub-matrices of bint[][] B00 = Copyarrays (b,1);int[][] B01 = Copyarrays (b,2);int[][] B10 = Copyarrays (b,3);int[][] B11 = Copyarrays (b,4); Recurs
Derived2 object, you can refer to it with any variable of the DERIVED2 type. As shown in 1, Derived, base, and Itype are all base classes of Derived2. Therefore, a reference to the base class is useful. Figure 3 depicts the conceptual perspective of the following statement.Base base = Derived2;Figure 3:base Class reference attached to Derived2 objectAlthough the reference to the base class does not have to access M3 () and M4 (), it does not change a
of the Derived2 object maps the appropriate code, as described in the above Code. For example, the Derived2 object maps the m1 () method defined in Derived. The m1 () method of the Base class is also overloaded. The referenced variable of a Derived2 does not have access to the overloaded m1 () method in the Base class. However, this does not mean that this method cannot be called using the super. m1 () method. This code is not suitable for variables referenced by derived2. Other operation Mappi
[Thinking in Java] modifier public, protected, default, private, thinkingprotected
When using Java, four modifiers, public, protected, default (no modifier), and private, are often encountered. The differences between them are written here.
Public: any access outside the package
Protected: any access in the package, only sub-class access outside the package
Default: any access in the package
Private: class-based access only
Use code to explain
1 package p1; 2 import static java.lang.System.*; 3
. setColor (Color. BLACK); // set the paint color to paint. setTextScaleX (15); // set the text size canvas. drawBitmap (bitmap, 10, 10, paint); // draw the image canvas at 10x10. save (); // save the canvas State Matrix m1 = new Matrix (); // Matrix m1.setTranslate (500, 10); // translate X500 Y10 Matrix m2 = new Matrix (); m2.setRotate (15); // rotate 15 ° Matrix m3 = new Matrix (); m3.setConcat (m1, m2);
corresponds to 49, 50, 51, 52The encryption process is: 49 ^ Key ^ Salt Value-M1The encryption process is: 50 ^ key ^ M1-m2The encryption process is: 51 ^ key ^ m2-m3The encryption process is: 52 ^ Key ^ m3-M4After the above operation, ciphertext becomes M1, M2, M3, M4.Decrypt:Decryption is the inverse of the above encryption: Known conditions are M1, M2, M3, M4
Hybrid prediction-The average of single-model predictions-is typically used to produce better point estimates than any contribution prediction model. I showed how to build a prediction interval for mixed predictions, where the coverage is more accurate than the most commonly used prediction interval (i.e. 80% of the actual observations are indeed within the 80% confidence interval), and the test contest data set is performed in the 3,003 M3 prediction
different ordinal number in the cell, enter "Please enter a number" in cell L3, and then determine the M3 cell as the notification Number option cell. At the same time, in order to be in front of the students ' scores, the data of each student automatically quoted, in the notice of the students ' record list "student name" below the A12 input formula "=offset" (Student score Details! $A $, $M $3*1-1,0) "", in the 1th course "language" The following
1, the problem description:
There are four M1,M2,M3,M4 modules in system S, each of which is a Web application. The session is not readable in another module after the session is set in one of the modules.
2, the problem reason:
A Web application is the equivalent of a site, and it is impossible to share sessions between applications and applications.
3, the solution:
1 include four Web applications in the same solution
(Note: Adjust the. webinf
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