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= CephxFilestore_xattr_use_omap = TrueOsd_pool_default_size = 2Osd_pool_default_min_size = 1Osd_pool_default_pg_num = 128Osd_pool_default_pgp_num = 128Filestore_fd_cache_size = 204800Filestore_omap_header_cache_size = 204800Filestore_fiemap = TrueFilestore_wbthrottle_xfs_bytes_start_flusher = 500000000Filestore_wbthrottle_xfs_indoes_start_flusher = 500Filestore_wbthrottle_xfs_indoes_hard_limit = 500000Filestore_wbthrottle_xfs_ios_start_flusher = 50000Filestore_wbthrottle_xfs_bytes_hard_limit =

1, first you need to know what is git2, then the history of its git have some knowledge (bragging B when it is useful, if you do not know the Linux off socks Linus Torvalds o (︶^︶) o)Git Common data Query site,Official website (download): http://git-scm.com/download/Official website (document Center): Http://git-scm.com/docGit Pinterest (the most basic command introduction, English version, not difficult to understand): http://ndpsoftware.com/git-cheatsheet.html or (Chinese) http://www.jianshu.c

The result is that the make tool is not compatible with some old rules for the makefile of the lower version of the kernel, we just need to modify the corresponding makefile.Change 1:Original:approx. 1503 lines/%/: Prepare scripts Force$ (Q) $ (make) kbuild_modules=$ (if $ (config_modules), 1)$ (build) =$ (Build-dir)After modification:/: Prepare scripts Force$ (Q) $ (make) kbuild_modules=$ (if $ (config_modules), 1)$ (build) =$ (Build-dir)%/: Prepare scripts Force$ (Q) $ (make) kbuild_modules=$

--) { intn,m; Hav.clear (); scanf ("%d%d",n,m); for(intI=0; i) {scanf ("%d%d", px+i,py+i); } intflag=0; for(intI=0; i1; i++) { for(intj=i+1; j) { intDis=abs (Px[j]-px[i]) +abs (py[j]-Py[i]); if(Hav.count (dis)) {flag=1; Break; } Else{hav.insert (dis); } } if(flag) { Break; } } if(flag) printf ("yes\n"); Elseprintf"no\n"); } return 0;}View Codeconsider a kind of violence,

Title: Portal.Test instructions: A large number of N, up to 5 times the root of the root, ask several square root can get 1, if 5 times can not get 1 on the output tat.Problem solving:x1=1,x2= (x1+1) * (x1+1)-1, etc. X5 is not more than a long long , the output can be judged.#include #include#include#includeusing namespaceStd;typedefLong Longll;Charc[1005];intMain () { while(cin>>c) {intlen=strlen (c); if(len>= the) {printf ("tat\n"); } Else{ll n=c[0]-'0'; LL Maxx=4294967295; for(intI=1;

When at both ends: a total of n * (n-1) combinations, satisfying the condition of having, the calculation is available, counter = n * (n-1)/2.Other locations: A total of n * (n-1) * (n-2) combinations, to meet the conditions, the use of squares and formulas can be obtained counter = n * (n-1) * (n-2)/3.#include using namespacestd;intMain () {intN; while(~SCANF ("%d",N)) {DoubleAns =0.0, C; for(intI=1; i) {scanf ("%LF", c); if(i = =1|| i = = N) ans + = c/2.0; ElseAns + = c/3.0; } printf ("%lf\n

; j) A { theX=abs (a[i].x-a[j].x) +abs (a[i].y-a[j].y); + if(U[x]) - { $Puts"YES"); $ return; - } -u[x]=1; the } - }WuyiPuts"NO"); the } - intMain () Wu { - #ifndef Online_judge About //freopen ("1.txt", "R", stdin); $ //freopen ("2.txt", "w", stdout); - #endif - inti,j,x; - for(SCANF ("%d", cas); cas;cas--) A //for (scanf ("%d", cas), cass=1;cass + //while (~scanf ("%s", s)) the //while (~scanf ("%d", n)) -

namespacestd; -typedefLong LongLL; - intCas,cass; in intN,m,lll,ans; - intV1,v2; to intMain () + { - #ifndef Online_judge the //freopen ("1.txt", "R", stdin); * //freopen ("2.txt", "w", stdout); $ #endifPanax Notoginseng inti,j; - //for (scanf ("%d", cas); cas;cas--) the //for (scanf ("%d", cas), cass=1;cass + //while (~scanf ("%s", s)) A while(~SCANF ("%d",N)) the { +scanf"%d%d",v1,v2); - if(n==0) puts ("0.000000"); $ Else if(V1"Infinity"); $ Elseprintf

[j][i], a[i][i]); intX1 = D/a[j][i], x2 = d/A[i][i]; for(intK = i; K ) A[j][k]= ((a[j][k] * x1-a[i][k] * x2)%3+3) %3; } } } intAns =0; for(inti = cnt-1; i >0; I--) {X[i]=a[i][cnt]; for(intj = i +1; J ) X[i]= ((X[i]-a[i][j] * x[j])%3+3)%3; X[i]= a[i][i] * X[i]%3; Ans+=X[i]; } printf ("%d\n", ans); for(inti =1; I ){ while(X[i]) {printf ("%d%d\n", (I-1)/M +1, (I-1)%m +1); X[i]--; } }}intMain () {intT; scanf ("%d",T); while(T--) {CNT=1; scanf ("%d%d",n,m); for(inti =1;

System.Data.SqlClient.SqlCommand.InternalExecuteNonQuery (TaskCompletionSource ' 1 completion, String MethodName, Boolean sendtopipe, Int32 timeout, Boolean asyncwrite)In System.Data.SqlClient.SqlCommand.ExecuteNonQuery ()In System.Data.Mapping.Update.Internal.DynamicUpdateCommand.Execute (updatetranslator translator, EntityConnection Connection, Dictionary ' 2 identifiervalues, List ' 1 generatedvalues)In System.Data.Mapping.Update.Internal.UpdateTranslator.Update (Ientitystatemanager Stateman

With the study in depth, Java also has a general understanding.This week, I learned the basic syntax of Java: if,while,do/while,forThere are arrays, methods, and so on.For this part of the study, the focus is to master the basic form of grammar, understanding the meaning of grammatical essence. All things, existence is rational, so understand each grammar, each keyword appears the meaning of their usage is basically mastered.The key of program design is to divide the big problem and target. Divi

.prototype);// Undefined, because it is an instance, there is no prototype property Console.log (New Object () __proto__.__proto__);//null, why is null,//take prototype object proto = object.prototype;//enumerates the object members and counts var num = 0;for (var n in Proto) {num++}//display count: 0console.log (num);/** * The following method of invocation is incorrect. Be sure to note */function Myfunca () {alert ("AA");} Myfunca.prototype = {show:function () {alert ("Show");}} Myfunca.show

[] passwords, string[] names, int[] numbers, int[] grades,String[] problems) {System.out.println ("Enter the username that requires a password reset:");Scanner S1 = new Scanner (system.in);String user = S1.nextline ();for (int i = 0; i if (users[i]! = null user.equals (Users[i])) {SYSTEM.OUT.PRINTLN ("New password:");Scanner s2 = new Scanner (system.in);String password = s2.nextline ();Passwords[i] = password;SYSTEM.OUT.PRINTLN ("Password has been reset! ");NEWPSD (Users, passwords, names, numb

-s_3167458311.png "title=" write the title. png "alt=" wkiom1ey5k6jgav3aadsdrhgsn8317.png-wh_50 "/> You can insert a paragraph reference650) this.width=650; "Src=" Http://s5.51cto.com/wyfs02/M01/86/08/wKiom1ey5mjT9HNNAAG_-m0xJxc054.png-wh_500x0-wm_3 -wmp_4-s_161657961.png "title=" paragraph references. png "alt=" wkiom1ey5mjt9hnnaag_-m0xjxc054.png-wh_50 "/> Can be added to the buying style650) this.width=650; "Src=" Http://s5.51cto.com/wyfs02/M01/86/08/wKioL1ey5n2Sb8hXAAJ5Fgjt7N0151.png-wh_5

EndurerOriginal1Version A web friend's computer has a QQ tail, and automatically sends a file to upload my recent photo to 11.zip ". Unzip my close photo 11.zip contains a file:----------------My photo is 11.jpg exe---------------- There are a large number of spaces between the extension name.exeand the pseudo extension name.jpg. The size of the file is 25,331 bytes, Which is compressed by UPX. The size of the file after shelling is 80,896 bytes. Kaspersky reportsTrojan-Downloader.Win32.VB.khThe

mastered C ++. They have to pay a huge price, including time, money, and even become difficult to get along with people (and of course not a general rule ). One thing is certain, that is, you are willing to invest (the time spent by others !) If you learn all relevant theories (such as hardware and architecture, compilation theory, low-level language, and discrete mathematics), you will naturally become excellent. Of course, in today's college students, they are willing to invest any additional

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has 100 attributes.But we just show 10 fields on the interface,The client uses the Web service to get the data, and there is no need to pass the entire PO object to the client.At this point we can pass the result to the client with a DTO with only these 10 attributes, and this will not expose the service-side table structure. After the client is reached, if the interface is displayed with this object, then its identity will be converted to VO.O/R Mapper object/relationship MappingAfter all the

here"Find:var Idselector=document.getelementbyid ("#selector");var tagselector=document.getelementsbytagname ("div");var tagselector=idselector.getelementsbytagname ("div"); "Select only Idselector div"H5 element Selectorvar classselector=document.getelementsbyclassname (". Selector") "Support ie9+"var query=document.queryselector ("#selector") "support all selectors in CS" "Support ie8+" "returns the first matching element"var queryall=document.queryselectorall (". Selector") "support all sele

Learning Linux also has more than two years, the beginning of the bumps, the east piece of the west, no systematic study. Wasted a lot of time and energy. Early this year participated in a Linux architect training course (here do not advertise, there is a window I want to know), systematic learning is really more than a multiplier ! Because of the use of spare time to learn, it is inevitable that homework is not good enough. Recently, there are not so many things in the work, after the leisure t