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Test instructions is Chinese, I don't say it;Here to use the species and check set, respectively, with 1-n; N-2N,2N-3N represents city, service, person;Then pay attention to these points:1: Do not use rank array, because even the edge to control their own.2: In the Unite function, the comparison of X and Y, control the large connection to the top of the small, so after ruminate, find () will find the smallest (city), and then if greater than n, it mea

into K-tribes in total! That's a good news. Cong hopes to dig out the details of all the tribes from this information. He was experimenting with an algorithm that could find the distance between two tribes for any one tribe division, and Cong hoped to find a way to divide the tribe so that the nearest two tribes could be kept as far away as possible. For example, the diagram on the left shows a good division, while the right is not. Please program to help Cong solve this problem.The first line

=-1; C=GetChar ();} while(c>='0'c'9') {a=a*Ten+c-'0'; C=GetChar ();} returnA *F;}intFindintx) {returnx==f[x]?x:f[x]=find (F[x]);} InlinevoidUnintXinty) { if(xy) Swap (x, y); F[y]=x; V[y]=1;}intMain () {n=read (); for(intI=1; i1; i++) f[i]=i; memset (V,0,sizeof(v)); for(intI=1; i) { intX=read (), y=read (); intP=find (x), q=find (y); if(p!=q) UN (P,Q);Elsev[p]=1; } for(intI=1; i1; i++) if(!v[i]) {printf ("%d", I-1); Break;} return 0;}[SCOI2010] [BZOJ1854] games | bina

} voidQueryintOintLcintRcintk) { if(lc==RC) {printf ("%d\n", LC); return; } intMC = lc+ (RC-LC)/2; if(k2|1]) query (o*2|1, mc+1, rc,k); ElseQuery (o*2, lc,mc,k-sum[o*2|1]); } voidinit () {memset (sum,0,sizeof(sum)); This->n =N; };} Solver;intMain () { while(cin>>n>>m) {init (); Solver.init (); Solver.build (1,1, N); for(intI=0; i){ intSG; scanf ("%d",SG); if(!SG) { intu,v; scanf ("%d%d",u,v); U=Find (U); V=Find (v); if(U==V)Contin

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the input file contains two integers, n (1 The next M-line, each line consists of two integers x, y, where (0The next line is an integer k, representing the number of planets the empire plans to hit.The next K-line is an integer X for each line, satisfying 0Output format:The first line of the output file is the number of connected blocks at the beginning of the planet.The next K-line, an integer per line, indicates the number of connected blocks of the existing planet after the strike.Input Sam

() >1)//Keep running even if you find the information incomplete, because if the information is incomplete and the conflict is conflict theFlag =1; - intpos =S.front (); WuS.pop (), sum--;//number of times the record was run - for(inti =0; I) About { $ inch[map[pos][i]]--; - if(inch[Map[pos][i]] = =0) - S.push (Map[pos][i]); - } A } + if(sum>0) printf ("conflict\n");//conflict, that is, there are multiple degrees of zero and ances

To allow the Python interpreter to find the location of the Python package I installed, I added the location to the Pythonpath, and after a while, the interpreter in Pycharm failed to detect the existence of my bag, The command interaction mode that opens Python at the end can get the path I set in Pythonpath. (I was so angry that I sprayed my old blood, and if any of the great gods knew what the situation was, please inform me meow.) Thank you, Yo ^_

} - voidUniteintT1,intT2) { - intf1=find_father (t1); - intF2=Find_father (T2); - if(f1==F2) { - return ; in } - if(depth[f1]Depth[f2]) { topar[f1]=F2; +}Else{ -par[f2]=F1; the if(depth[f1]==Depth[f2]) { *depth[f1]++; $ //Record DepthPanax Notoginseng } - } the } + A BOOLSame (intXinty) { the returnFind_father (x) = =Find_father (y); + } - $ intMain () $ { - intn,k; - intd,x,y; the intans=0; -scanf"%d%d",n,k);WuyiInit (n3); the

This requires implementing a function that finds and returns the K-element of the linked table. function Interface Definition:ElementType findkth (List L, int K); Where the list structure is defined as follows: typedef struct Lnode *ptrtolnode;struct lnode { ElementType Data; Ptrtolnode Next;}; typedef ptrtolnode List; L is given a single linked list, the function findkth to return the K element of the linked table. If the element does not exist, an error is returned. Example of a referee

intfather[1001],n,k; One A DoubleDis (intXinty) - { - return(sqrt (a[x].x-a[y].x) * (a[x].x-a[y].x) + (A[X].Y-A[Y].Y) * (a[x].y-( a[y].y) )); the } - - intFind (intx) - { + if(X==father[x])returnFather[x]; -father[x]=Find (father[x]); + returnFather[x]; A } at - voidMerge (intXinty) - { - intfx=Find (x); - intfy=Find (y); -father[fx]=fy; in } - to BOOLCheckDoublelen) + { - for(intI=1; ii) thefather[i]=i; * for(intI=1; i1;++i) $ for(intj=i+1; jj)Panax N

Using recursive memory search to enumerate n parentheses Class Solution (object): dp=[] def generateparenthesis (self, N): "" : Type n:int : rtype:list[ STR] "" While (N>=len (SELF.DP)): Self.dp.append ( -1) if Self.dp[n]!=-1:return self.dp[n] if n==0 : self.dp[0]=[] Return [] if n==1: self.dp[1]=["()"] Return ["()]] ans=

, the output "OK". Otherwise, you can determine the cause of the error because the information is incomplete (output "uncertain"), or because the information contains a conflict (output "CONFLICT").Note that if the information contains both conflicting and incomplete information, the output is "CONFLICT".Input This topic contains multiple sets of tests, please handle to the end of the file.The first row of each group of tests contains two integers n,m (0Next there are m lines, which represent th