= + + operator Difference Simple introduction _java

We know:

int i = 5;

Long j = 7;

i = i + j cannot compile, but i = j can compile and run, result i = 12.

This is because:

i = = J equals to i = (int) (I+J);

The summary is that for a compound assignment expression, the E1 op= E2 (such as I = J, I-J, and so on) is actually equivalent to E1 = (t) (E1) op (E2), where T is the type of E1 element.

This question, in fact, has been answered in the official document. Official document Address §15.26.2 compound assignment Operators

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