=-Thank you very much for your guidance ~ Solution

-Thank you very much for your guidance ~ & Lt ;? Phpecho & nbsp; Name :. $ _ POST [name]. & lt; br & gt; & nbsp; echo & nbsp; $ _ POST [price]. & lt; br & gt; & nbsp; echo & nbsp; $ _ POST [type]. & lt; br & gt; & nbsp; e =-thank you very much for your guidance ~

 
Echo "name:". $ _ POST ['name']."
";
// Echo $ _ POST ['price']."
";
// Echo $ _ POST ['type']."
";
// Echo $ _ POST ['name']."
";
Echo "tel:". $ _ POST ['Tel ']."
";
Echo "email:". $ _ POST ['email ']."
";
Echo "QQ:". $ _ POST ['QQ']."
";
Echo "address:". $ _ POST ['addr ']."
";
Echo "gender:". $ _ POST ['sex']."
";
Echo "product name:". $ _ POST ['brandname']."
";
Echo "brand:". $ _ POST ['commoditybrand']."
";
Echo "product No.:". $ _ POST ['produd d']."
";
Echo "product No.:". $ _ POST ['ordername']."
";
Echo "shop name:". $ _ POST ['shopname']."
";
Echo "shop address:". $ _ POST ['shopadd']."
";
Echo "Invoice No.:". $ _ POST ['invoicenumber']."
";
Echo "purchase date:". $ _ POST ['purchasingdate']."
";


$ Dingdanhao = date ("Y-m-dH-I-s ");
$ Dingdanhao = str_replace ("-", "", $ dingdanhao );
$ Dingdanhao. = rand (1000,2000 );

Echo "warranty No.:". $ dingdanhao;

 
$ Name = $ _ POST ['name'];
$ Tel = $ _ POST ['tel'];
$ Email = $ _ POST ['email '];
$ QQ =$ _ POST ['QQ'];
$ Sex = $ _ POST ['Sex '];
$ Brandname = $ _ POST ['brandname'];
$ Commoditybrand =$ _ POST ['commoditybrand'];
$ ProductID = $ _ POST ['produd d'];
$ Ordername = $ _ POST ['ordername'];
$ Shopname = $ _ POST ['shopname'];
$ Shopaddr = $ _ POST ['shoppaddr '];
$ Invoicenumber = $ _ POST ['invoicenumber'];
$ Purchasingdate = $ _ POST ['purchasingdate'];


Require_once ("conn. php ");
If (mysql_query ("insert into name set

Name = '$ name', tel =' $ Tel', email = '$ email', QQ = '$ QQ', sex =' $ sex ', brandname = '$ brandname', commodity

Brand = '$ commoditybrand', productID =' $ productID ', ordername =' $ ordername', shopname = '$ shopname ',

Shopaddr = '$ shopaddr', invoicenumber = '$ invoicenumber', purchasingdate = '$ purchasingdate '",

$ Conn )){
Echo "added successfully! View database ";
}
Else {
Echo 'failed to add! ';
}

Mysql_close ($ con );
?>

The error report is as follows:
Notice: Undefined variable: con in D: \ wamp \ www \ WWW \ post. php on line 55
Call Stack


(! ) Warning: mysql_close () expects parameter 1 to be resource, null given in D: \ wamp \ www \ post. php on line 55

=-Help
------ Solution ----------------------
Mysql_close ($ con); change to mysql_close ($ conn );
------ Solution ----------------------
$ Con is wrong. it should be $ conn.

You have written the program above.
Mysql_query ("insert into name set

Name = '$ name', tel =' $ Tel', email = '$ email', QQ = '$ QQ', sex =' $ sex ', brandname = '$ brandname', commodity

Brand = '$ commoditybrand', productID =' $ productID ', ordername =' $ ordername', shopname = '$ shopname ',

Shopaddr = '$ shopaddr', invoicenumber = '$ invoicenumber', purchasingdate = '$ purchasingdate '",

$ Conn ))