1-6-05: Age and disease

Describe

A hospital would like to check whether the availability of a disease is related to age, the previous diagnostic records need to be collated, according to 0-18, 19-35, 36-60, 61 (including 61) four age groups accounted for the proportion of the total number of people affected.

Input

Total 2 lines, first act the number of past patients N (0 < n <= 100), the second act of each patient's age at the time of illness.

Output

according to the output of 0-18, 19-35, 36-60, 61 (including 61) Four age groups, the proportion of the total number of people affected by the disease is as a percentage of the output, accurate to two digits after the decimal point. Each age group occupies a row, a total of four rows.

Sample input

101 11 21 31 41 51 61 71 81 91

Sample output

20.00%20.00%20.00%40.00%

1#include <stdio.h>2 intMain ()3 {4     inta[5]={0};5     intn,y;6scanf"%d",&n);7      for(intI=1; i<=n;i++)8     {9scanf"%d",&y);Ten         if(y<= -) {a[1]++;Continue;} One         if(y<= *) {a[2]++;Continue;} A         if(y<= -) {a[3]++;Continue;} -a[4]++; -     } theprintf"%.2f%%\n%.2f%%\n%.2f%%\n%.2f%%\n",(float) a[1]/n* -,(float) a[2]/n* -,(float) a[3]/n* -,(float) a[4]/n* -); -     return 0; -}

1-6-05: Age and disease