1 dollars a bottle of water, 4 cover for a bottle of water, 150 can drink how much water

First to analyze:

First time: 150
Second time: 150/4 = 37 2
Third time: (37+2)/4 = 9 3
Fourth time: (9 + 3)/4 = 3

3 < 4 so stop

Initial value 150 bottle of water, which is 150 caps

1. Take all the lids to change the water, record the remainder and sum

2. (last remainder + last change of water to drink)/4, record remainder and sum1

......

Infinite loops, until the number of lids <4,

Binding code:

 Public classDemo3 { Public Static voidMain (string[] args) {intn = 150; intsum = 150;  while(N >= 4) {
　　　　　　　int temp = n% 4;  N= (int) (N/4);sum+=N; N= n +temp;    } System.out.println (sum); }}

1 dollars a bottle of water, 4 cover for a bottle of water, 150 can drink how much water