1-4-17: Judging leap years

Description Determines whether a year is a leap years. Input input is only one row, contains an integer a (0 < a < 3000) output line, if year A.D. is a leap years output y, otherwise output n sample input

2006

Sample output

N

It is suggested that the Gregorian calendar method, which can be divisible by 4 is mostly leap years, but can be divisible by 100 and not divisible by 400 is not a leap year, can be divisible by 3200 is not a leap, such as 1900 is common year, 2000 is leap year, 3200 is not a leap year.

1#include <stdio.h>2 intMain ()3 {4     intA;5scanf"%d",&a);6     if(a%4!=0)7printf"n\n");8     Else9         if(a% -!=0)Tenprintf"y\n"); One         Else A             if(a% -==0) -printf"y\n"); -             Else theprintf"n\n"); -     return 0; -}

1-4-17: Judging leap years