1010.a+b

Title Description:

Read in two positive integers a and B less than 100, calculate a+b.
It is important to note that each digit of A and b is given by the corresponding English word.

Input:

The

test input contains several test cases, one row for each test case, the format "A + B =", and two adjacent strings with a space interval. When both A and B are at the end of 0 o'clock input, the corresponding result is not output.

Output:

Output 1 rows for each test case, which is the value of a+b.

Sample input:

One + =three four + five six =zero seven + eight nine =zero + zero =

Sample output:

39096

#include <iostream>#include<cstring>using namespacestd;intChangestringstr) {    if(str=="Zero")return 0; Else if(str==" One")return 1; Else if(str==" Both")return 2; Else if(str=="three")return 3; Else if(str==" Four")return 4; Else if(str=="Five")return 5; Else if(str=="Six")return 6; Else if(str=="Seven")return 7; Else if(str=="Eight")return 8; Else if(str=="Nine")return 9;}intMain () {strings; intb;  while(cin>>R) {        if(s!="+"&& s!="=") A=change (s) +Ten*A; Else if(s=="+") {b=A; A=0; }        Else {            if(a==0&& b==0)return 0; Elsecout<<a+b<<Endl; A=b=0; }    }    return 0;}

1010.a+b