11.2---Array of strings, removing the verb

The problem is that you want to take advantage of the sort function that comes with the array.

Also, note that hash is used to determine if it appears.

   Public StaticArraylist<string> sortstrings (string[] str,intN) {//Write code herearraylist<string> res =NewArrayList (); //SortArrays.sort (str); HashSet<String> hash =NewHashSet ();  for(inti = 0; I <n; i++){              Char[] C =Str[i].tochararray ();                           Arrays.sort (c); String tmp=NewString (c); if(!hash.contains (TMP))                  {Hash.add (TMP);              Res.add (Str[i]); }                        }                    returnRes; }

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11.2---Array of strings, removing the verb