122345 arrange randomly to find the number that satisfies the condition

Title Requirements:

1. Must contain 122345 of these six numbers

2. The third digit in the number (hundred) cannot be 4

3. Output 6 digits of all the above two conditions

The code is as follows:

    StaticString[] Numberstrings = {"1", "2", "3", "4", "5"};  Public Static voidMain (string[] args) { for(inti=122345;i<999999;i++) {Onetof (i+""); }            }     Public Static voidOnetof (FinalString number) {         for(String n:numberstrings) {if(Number.indexof (n) <0)                return; }        if(Number.indexof ("4") ==3)            return; if(Number.lastindexof ("2") ==number.indexof ("2")))            return; if("Number.indexof") >0 | | number.indexof ("(") > 0)            return;    SYSTEM.OUT.PRINTLN (number); }

So, the question is, if it's not a 6-digit number, but a 7-bit, or a lot of other bits, you need to change it:

if (Number.indexof ("4") = = Number.length ()-3            ) return;

That's it.

But this method feel inefficient, if there is an idea, welcome message ....

122345 arrange randomly to find the number that satisfies the condition