14th Week Item three electronic dictionary

/**copyright (c) 2014, College of Computer and Control engineering, Yantai University *all rights reserved.* file name: d.cpp* Author: Zhang Wanhua * Completion Date: June 3, 2015 * version number: v1.0*//* Project 3-oop Edition Electronic Dictionary "make a simple electronic dictionary." In the document Dictionary.txt, the preservation is a English-Chinese control dictionary, the vocabulary quantity nearly 8,000, English, the Chinese explanation and the part of speech uses ' \ t ' separates. (1) Programming, the user input English words, show the part of speech and Chinese interpretation. Tip 1: If you want to use OOP to complete this dictionary (which can also be implemented using the Oo method), you can define a word class that represents an entry with the data member string 中文版; denotes English word, string Chinese; Indicates the Chinese meaning, string word_class; A dictionary class that represents the dictionary, where word words[8000] members represent terms in the dictionary, int wordsnum; Represents the number of entries in a dictionary, reads entries from a file in a constructor, and adds a member function to look up a word. Tip 2: The words in the file are sorted, so when searching, use the binary search method to improve the efficiency. Tip 3: Such projects, preferably organized in multi-file format * * #include <fstream> #include <iostream> #include <string> #include <    Cstdlib>using namespace Std;class word{public:void Set (string e, String C, string wc);  int compare (string);    The English part compares with the given string, which equals return, greater than return, less than 1 string Getchinese ();    String Getword_class ();p rivate:string Chinese;    String 中文版; string Word_class;};    void Word::set (String e, String C, string wc) {english=e;    Chinese=c; WORD_CLASS=WC;} int Word::compare (string p)//English part with given wordstring comparison, equal to return, greater than return, less than return -1{if (english>p) return 1;    if (english==p) {return 0; } return-1;} String Word::getchinese () {return chinese;} String Word::getword_class () {return word_class;}    Class Dictionary{public:dictionary ();    void Searchword (string k);p rivate:int binseareh (int low, int. High, String k);    int wordsnum; Word words[8000];    Used to save the thesaurus};D ictionary::D ictionary () {string E,C,WC;    wordsnum=0;    Ifstream infile ("Dictionary.txt", ios::in);        if (!infile) {cerr<< "Open error" <<endl;    Exit (1);        } while (!infile.eof ()) {infile>>e>>c>>wc;        Words[wordsnum].set (E, C, WC);    ++wordsnum; } infile.close ();}    void Dictionary::searchword (string key) {int low=0,high=wordsnum-1;    int Index=binseareh (Low, high, key); if (index>=0) cout<<key<< "--->" <<words[index].getword_class () + "\ T" <<words[index].    Getchinese (); Else Cout<< "Do not find this word"; Cout<<endl<<endl;}    int Dictionary::binseareh (int low, int. High, string key) {int mid;        while (Low<=high) {mid= (low + high)/2;            if (Words[mid].compare (key) ==0) {return mid;//find successful return} if (Words[mid].compare (key) >0) High=mid-1; Continue in W[low. Find else low=mid+1 in mid-1]; Continue to find} return-1 in W[mid+1..high];    When Low>high indicates that the lookup interval is empty, the lookup fails}int main () {Dictionary dict;    String key;        Do {cout<< "Please enter the keywords to be queried (English), 0000 end:" <<endl;        cin>>key;        if (key!= "0000") {Dict.searchword (key);    }} while (key!= "0000"); cout<< "Welcome to use again!"    "<<endl<<endl; return 0;}

14th Week Item three electronic dictionary