2 ways to get a domain name in a URL in PHP

Method 1:

Custom function, the benefit is can be rewritten at any time, insufficient is some domain name may not parse out

function Get_domain ($url) {$pattern = "/[/w-]+/. Com|net|org|gov|biz|com.tw|com.hk|com.ru|net.tw|net.hk|net.ru|info|cn|com.cn|net.cn|org.cn|gov.cn|mobi|name|sh |ac|la|travel|tm|us|cc|tv|jobs|asia|hn|lc|hk|bz|com.hk|ws|tel|io|tw|ac.cn|bj.cn|sh.cn|tj.cn|cq.cn|he.cn|sx.cn| nm.cn|ln.cn|jl.cn|hl.cn|js.cn|zj.cn|ah.cn|fj.cn|jx.cn|sd.cn|ha.cn|hb.cn|hn.cn|gd.cn|gx.cn|hi.cn|sc.cn|gz.cn| yn.cn|xz.cn|sn.cn|gs.cn|qh.cn|nx.cn|xj.cn|tw.cn|hk.cn|mo.cn|org.hk|is|edu|mil|au|jp|int|kr|de|vc|ag|in|me| EDU.CN|CO.KR|GD|VG|CO.UK|BE|SG|IT|RO|COM.MO) (/. ( CN|HK) */";p Reg_match ($pattern, $url, $matches); if (count ($matches) > 0) {return $matches [0];} else{$rs = Parse_url ($url), $main _url = $rs ["Host"];if (!STRCMP (Long2ip (sprintf ("%u", Ip2long ($main _url)), $main _url) {return $main _url;} else{$arr = Explode (".", $main _url), $count =count ($arr), $ENDARR = Array ("com", "net", "org"),//com.cn net.cn, etc. if (in_ Array ($arr [$count-2], $ENDARR)) {$domain = $arr [$count-3]. ".". $arr [$count-2]. ".". $arr [$count-1];} else{$domain = $arr [$count-2]. ".". $arr [$count-1];} return $domain;}}}

Method 2:

With its own function, the advantage is that it's easy to use, and that's what I'm using now.

If you don't want www, you can replace it with Str_replace.

$URL = ' http://www.scutephp.com/index.html '; $tempu =parse_url ($Url) $message = $tempu [' Host '];echo $message;//Output is Www.scutephp.com

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