706-LCD-Display

Simple question simulation, design a good data structure to easily express the output mode of each number.

I am not the best. Later I saw the kaipeng Liu method, which is more convenient to write ;)

 

Returns the volume VII index.

Returns the total index.

 

Below is my code

 

//////////////////////////////////////// /// // <Br/> // 706-LCD-display <br/> // copyright (c) 2010 by Bo-Wen Feng <br/> // balonfan@gmail.com <br/> /////////////////////// //////////////////////////////////////// /// // </P> <p> # include <set> <br/> # include <map> <br/> # include <list> <br/> # include <queue> <br/> # include <stack> <br/> # include <vector> <br/> # include <string> <br/> # include <sstream> </P> <p> # include <cstdio> <br/> # include <cmath> <br/> # include <limits> <br/> # include <utility> </P> <p> # ifndef online_judge <br/> # include <fstream> <br/> STD:: ifstream CIN ("in.txt"); <br/> STD: ofstream cout ("out.txt"); <br/> // STD: ofstream cout (stdout ); <br/> # else <br/> # include <iostream> <br/> # endif </P> <p> typedef long llong; <br/> typedef unsigned long ullong; <br/> typedef long double ldouble; </P> <p> using namespace STD; </P> <p> # define max_digit 20 </P> <p> // 0 1 2 3 4 5 6 7 8 9 <br/> char Part1 [10] = {'-', '','-','-','','-','-','-','-','-'}; <br/> char Part2 [20] = {'|', '|', '', '|', ',' | ', '|', ',' | ', '|', '|'}; <br/> char Part3 [10] = {'','','-','-','-', '-', '-', '', '-', '-'}; <br/> char part4 [20] = {'|', '| ', '', '|', '|','', '', '|','', '|', '|', ',' | ',' | ', '|', '', '|', ',' | '}; <br/> char part5 [10] = {'-','','-','-','','-','-','', '-', '-'}; </P> <p> void printpart135 (char part [], int S, char * num, int ndigit) <br/>{< br/> char ch; <br/> int D; <br/> for (INT I = 0; I <ndigit; ++ I) <br/>{< br/> if (I> 0) <br/> cout <''; </P> <p> d = num [I]-'0'; </P> <p> cout <''; <br/> CH = part [d]; </P> <p> for (Int J = 0; j <s; ++ J) <br/>{< br/> cout <ch; <br/>}< br/> cout <''; <br/>}</P> <p> cout <'/N'; <br/>}</P> <p> void printpart24 (char part [], int S, char * num, int ndigit) <br/>{< br/> int D; <br/> for (int K = 0; k <s; ++ K) <br/>{< br/> for (INT I = 0; I <ndigit; ++ I) <br/>{< br/> if (I> 0) <br/> cout <''; </P> <p> d = (Num [I]-'0') <1); </P> <p> char parts = part [d]; <br/> char CH2 = part [d + 1]; </P> <p> cout <strong; </P> <p> for (Int J = 0; j <s; ++ J) <br/> cout <''; </P> <p> cout <CH2; <br/>}</P> <p> cout <'/N '; <br/>}</P> <p> int main (INT argc, char * argv []) <br/>{< br/> int s; <br/> char num [max_digit]; <br/> int ndigit; </P> <p> CIN> S> num; </P> <p> while (S> 0) <br/>{< br/> ndigit = strlen (Num); <br/> printpart135 (Part1, S, num, ndigit); <br/> printpart24 (Part2, s, num, ndigit); <br/> printpart135 (Part3, S, num, ndigit); <br/> printpart24 (part4, S, num, ndigit ); <br/> printpart135 (part5, S, num, ndigit); </P> <p> cout <'/N '; </P> <p> CIN> S> num; <br/>}</P> <p> return 0; <br/>}</P> <p>