A comparison between structure array and the application of malloc to structural body space

A comparison between structure array and the application of malloc to structural body space

　　The title of the article sounds very awkward, perhaps I describe the less clear, or to see the routine it:

I'll start with the first malloc I'll ever use:

　　

1#include <stdio.h>2#include <stdlib.h>3#include <string.h>4 5 structStudent6 {7     Char*name;8     intAge ;9 };Ten  One intMain () A { -     structStudent *p_student=NULL; -P_student= ((structStudent *)malloc(sizeof(struct( Student) )); the  -P_student->name="Tom"; -P_student->age= at; -  +printf"name:%s\n",p_student->name); -printf"age:%d\n",p_student->Age ); +  A      Free(p_student);
p_student=null;//Note that the malloc space is released, but the struct pointer still exists and still needs to point to NULL; -     return 0; -}

　　The above procedure is simple and clear, is to apply for a structure pointer, and then open up a memory space, ready to store "struct student" type of variable data, variables are initialized, print out, finally release malloc space.

Here's another structure array:

1#include <stdio.h>2#include <stdlib.h>3#include <string.h>4 5 structStudent6 {7     Char*name;8     intAge ;9 };Ten  One intMain () A { -     structStudent p_student[sizeof(structStudent)]={"Tom", at}; -  theprintf"name:%s\n",p_student->name); -printf"age:%d\n",p_student->Age ); -     return 0; -}

　　This is the structure of the array, that is: "struct student" type of array "P_student", the space size of "sizeof (struct student)", when initialized, directly behind the writing on the line.

　　From the above two examples, I found that the second structure of the array is useful.

A comparison between structure array and the application of malloc to structural body space