A practical example of date operations in SQL Server 2000

Source: Internet
Author: User

1. display the first day of the month


       
        SELECT DATEADD(mm,DATEDIFF(mm,0,getdate()),0)            select convert(datetime,convert(varchar(8),getdate(),            120)+'01',120)
       

2. display the last day of the month


       
        select dateadd(day,-1,convert(datetime,convert            (varchar(8),dateadd(month,1,getdate()),120)+'01',120))            SELECT dateadd(ms,-3,DATEADD(mm,DATEDIFF(m,0,getdate())+1,0))
       

3. Last day of last month


       
        SELECT dateadd(ms,-3,DATEADD(mm,DATEDIFF(mm,0,getdate()),0))
       

4. the first Monday of this month


       
        select DATEADD(wk,DATEDIFF(wk,0, dateadd(dd,6-datepart(            day,getdate()),getdate())),0)
       

5. The first day of this year


       
        SELECT DATEADD(yy,DATEDIFF(yy,0,getdate()),0)
       

6. The last day of the year


       
        SELECT dateadd(ms,-3,DATEADD(yy,DATEDIFF(yy,0,getdate())+1,0))
       

7. Last day of last year


       
        SELECT dateadd(ms,-3,DATEADD(yy,DATEDIFF(yy,0,getdate()),0))
       

8. The first day of this quarter


       
        SELECT DATEADD(qq,DATEDIFF(qq,0,getdate()),0)
       

9. Monday of the week


       
        SELECT DATEADD(wk,DATEDIFF(wk,0,getdate()),0)
       

10. query records of this month


       
        select * from tableName where DATEPART(mm, theDate)            =DATEPART(mm, GETDATE()) and DATEPART(yy, theDate)            = DATEPART(yy, GETDATE())
       

11. query the records of this week


       
        select * from tableName where DATEPART(wk, theDate) = DATEPART            (wk, GETDATE()) and DATEPART(yy, theDate) = DATEPART(yy, GETDATE())
       

12. query this season's recordsNote: getdate () is a function used to obtain the system time.


       
        select * from tableName where DATEPART(qq, theDate) = DATEPART            (qq, GETDATE()) and DATEPART(yy, theDate) = DATEPART(yy, GETDATE())
       

13. Get the total number of days of the month:


       
        select DATEDIFF(dd,getdate(),DATEADD            (mm, 1, getdate()))            select datediff(day,            dateadd(mm, datediff(mm,'',getdate()), ''),            dateadd(mm, datediff(mm,'',getdate()), '1900-02-01'))
       

14. Obtain the current day of the week


       
        DATENAME(weekday, getdate())
       

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