A program written in weskercn. Question (2) Answer: Convert the hexadecimal numbers of 16,10 and 8th of the keyboard input into binary output.

// Because the system cannot reply, the system always prompts an incorrect verification code.

# Include "stdafx. H"

# Include <iostream>

# Include <string>

# Include <cstdlib>

# Include <bitset>

# Include <iomanip>

# Include <cassert>

# Include <limits>

Using namespace STD;

Typedef Enum _ transmode

{

Hex_mode = 1,

Dec_mode,

Oct_mode

} Transmode;

Int main ()

{

String instr; // This is the input, string type

Long outlong; // converts the value to a long integer in the hexadecimal format.

Int n_numformat;

Cout <"Please chose the input number format (1-Hex, 2-dec, 3-oct)" <Endl;

Cin> n_numformat;

Cout <"Please input the number to be transformed :";

Cin> instr;

Switch (n_numformat) // your style is better than mine

{

Case hex_mode:

N_numformat = 16;

Break;

Case dec_mode:

N_numformat = 10;

Break;

Case oct_mode:

N_numformat = 8;

Break;

Default:

Cout <"error input number, exit" <Endl;

Exit (1 );

}

Outlong = strtol (instr. c_str (), null, n_numformat );

Assert (outlong! = 0); // If the conversion fails and the assertions are incorrect, this is the best part of your method.

Bitset <numeric_limits <long>: digits> abit (outlong );

Cout <"the binary number is" <abit <Endl; // No pipe format

Return 0;

}