About python3.6.3 and python2.7.14 when you encounter an in range (variable) error when using a For loop convenience

1. Number = input ("Enter a Numbers:")
2. Product = 1
3. For I in range (number):
4. Product = Product * (i + 1)
5. Print (product)

　　Error in python3.63 "TypeError: ' str ' object cannot is interpreted as an integer"
At this point, change the 3rd line to
For I in range (int (number)):
After executing the discovery again successfully the conjecture is input into the variable type of STR then proceed
Print (Type (nummber)) was found to be so displayed <class ' str ' >.
The original code was executed successfully using Python2.7.14, and the test type (number) was found as <type ' int ' >.
---from Beginner python cc

About python3.6.3 and python2.7.14 when you encounter an in range (variable) error when using a For loop convenience