About the C language declaration void (*signal (int sig, Void (*FUNC) (int))) (int) is understood

I just started seeing this, it hurts.

Or do you understand it slowly?

First of all

void (*FUNC) (int) is a pointer to a function with a return value of void parameter int

is a function pointer

Specific Understanding Http://zhidao.baidu.com/link?url=5GpEN7wPUhDlk_m-3drRHV9bGxv53tj818vtd1GIsyaVfyY1mdsFZfP6_2M_DNAfTQrh0qxMo _wxhk1cjiepjk

And see if the perimeter function declaration is a little bit like inside.

The inside function of the pair is abbreviated void (*signal (XXX)) (int)
The same as the function declaration inside is a no return value there is an int parameter that returns a function pointer to the type of the function shown above

Reference

Middle part:
Signal (int sig, Void (*FUNC) (int))
The signal function has 2 parameters, the first is int, the second is no return value, and a function pointer with an int argument

Peripheral:
void (*signal (XXX)) (int)
The signal function returns a function pointer with no return value and an int parameter

Simplified:
typedef void Sigfunc (int)
Sigfunc represents a return value is a function that has no return value and has an int parameter.

And that's how it ends.
Sigfunc *signal (int, sigfunc*)

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About the C language declaration void (*signal (int sig, Void (*FUNC) (int))) (int) is understood