Acm hdu 1170 balloon comes! (Complete water questions, plus, subtraction, multiplication, division)

Balloon comes!

Time Limit: 2000/1000 MS (Java/others) memory limit: 65536/32768 K (Java/Others)
Total submission (s): 10546 accepted submission (s): 3623

Problem descriptionthe contest starts now! How excited it is to see balloons floating around. you, one of the best programmers in HDU, can get a very beautiful balloon if only you have solved the very... easy problem.
Give you an operator (+,-, *,/-- denoting addition, subtraction, multiplication, division respectively) and two positive integers, your task is to output the result.
Is it very easy?
Come on, guy! Plmm will send you a beautiful balloon right now!
Good luck!

Inputinput contains multiple test cases. the first line of the input is a single integer T (0 <t <1000) which is the number of test cases. t test cases follow. each test case contains a char C (+,-, *,/) and two integers A and B (0 <a, B <10000 ). of course, we all know that A and B are operands and C is an operator.

Outputfor each case, print the operation result. The result shocould be rounded to 2 decimal places if and only if it is not an integer.

Sample input4 + 1 2-1 2*1 2/1 2

Sample output3-1 2 0.50

Authorlcy water question, note

The result shoshould be rounded to 2 decimal places if and only if it is not an integer. It is used for Division. If the division is to output an integer, because this WR has

 # Include  < Stdio. h  >  
# Include  <  Iostream  >  
  Using     Namespace  STD;
  Int  Main ()
{
  Int  T, A, B;
  Char  Ch;
Scanf ( "  % D  "  ,  &  T );
  While  (T  --  )
{
CIN  >  Ch  >  A  >  B;
  If (CH  =  '  +  '  ) Printf (  "  % D \ n  "  ,  +  B );
  Else     If  (CH  =  ' -  '  )
Printf (  "  % D \ n  "  ,  -  B );
  Else     If  (CH  =  '  *  ' )
Printf (  "  % D \ n  "  ,  *  B );
  Else   
{
  If  (  %  B  =  0  ) Printf (  " % D \ n  "  ,  /  B );  //  Note that you can see the meaning of the question  
    Else   
Printf (  "  %. 2f \ n  "  ,(  Float  ) /  B );
}
}
  Return     0  ;
}