Hungarian match first said a simple situation, more is the same, such as A,b,c to find objects, a asked B there is no object, B said no, Ok,a told B after your object is me, if C also started in the surrounding (connected nodes) Find objects, if found B, found that B already has objects, Ask B is there anyone around you single, b find a single, tell a after you are the object of me, otherwise go to ask a around there is no one single, and so on and so on, once found like a such a single B must reluctantly admitted his object is C. Summed up is this, once a node to find the object, the node it visited is a long chain, the head is to find the object of the node, the tail is single person, if there is a middle node, the middle is already has the object of the person. After execution, this chain has no objects except the head, others have objects, that is, to find the object is to let others admit that his object is me, but I myself have no object.
ACM Learning-Hungary matches. CPP: The entry point that defines the console application.
//
#include "stdafx.h"
#include <iostream>
#include <vector>
using namespace Std;
const int v = 13;
int Edge[v][v] = {
A B C D E F G H I J K L M
{0, 1, 1, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0},//a
{1, 0, 1, 1, 0, 0, 0, 1, 0, 0, 0, 0, 1},//b
{1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0},//c
{0, 1, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0},//d
{0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0},//e
{1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0},//f
{0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 1, 0, 0},//g
{0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0},//h
{0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0},//i
{0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1},//j
{0, 0, 0, 0, 0, 0, 1, 1, 0, 0, 0, 0, 0},//k
{0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 1},//l
{0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0}//m
};
Char t[] = {' A ', ' B ', ' C ', ' D ', ' E ', ' F ', ' G ', ' H ', ' I ', ' J ', ' K ', ' L ', ' M '};
const int n = 100;
Vector<int> G[v];
int from[v], tot;
BOOL Use[v];
BOOL Match (int x) {
for (int i = 0; i < g[x].size (); i++) {
if (!use[g[x][i]])
{
Use[g[x][i]] = true;
if (from[g[x][i]] = = 1 | | match (from[g[x][i]))
{
if (from[g[x][i]] = =-1)
{
cout << T[g[x][i]] << "hubby is:" << t[x << Endl;
}
else{
cout << T[g[x][i]] << "old husband:" << T[from[g[x][i]] << Endl;
cout << T[g[x][i]] << "New husband is:" << t[x] << Endl;
}
From[g[x][i]] = x;
return true;
}
}
}
return false;
}
int Hungary () {
tot = 0;
memset (from,255,sizeof from);
for (int i = 0; i < V; i++) {
memset (use,0,sizeof use);
if (Match (i)) tot++;
}
return tot;
}
int _tmain (int argc, _tchar* argv[])
{
for (int i = 0; i < V; i++) {
for (int j = 0; J < V; j + +) {
if (Edge[i][j])
G[i].push_back (j);
}
}
for (int i = 0; i < V; i++) {
for (int j = 0; J < G[i].size (); j + +) {
cout << T[i] << ":" << T[g[i][j]] << ends<<ends;
}
cout << Endl;
}
cout << "tot=" << Hungary () << Endl;
for (int i = 0; i < V; i++)
{
if (from[i] = =-1) {
cout << T[i] << "First and" << from[i << Endl;
}
else{
cout << T[i] << "First and" << T[from[i] << Endl;
}
//
}
return 0;
}
Copyright NOTICE: This article for Bo Master original article, without Bo Master permission not reproduced.
ACM Learning-Hungary Matches