Another way PHP face questions

Another PHP face question

The subject comes from the Brothers Lianyun classroom.
Write the result of the operation:

function MyFunc ($argument) {

echo $argunment + 10;

}

$variable = 10;

echo "MyFunc ($variable) =". MyFunc ($variable);










Answer: 1, echo "MyFunc ($variable) =". MyFunc ($variable); How will this sentence be executed??

The MyFunc ($variable) is executed first, and then ECHO is executed, so the answer is at least myfunc ($variable) = . 20 is myfunc ($variable); Execution results.

2, echo "MyFunc ($variable) =". How will it be resolved? The variables in the double quotes are executed, and the function is not executed. So equals:myfunc (10) =.

So, the answer is at least 20myfunc (10) =.

But look closely, function MyFunc ($argument) {

echo $argunment + 10;

}

The function passed in the variable is $argument, below is $argunment, this is very confusing people. Therefore, $argunment in this function will not be printed.

The local final correct answer is:10myfunc (Ten) =

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