Array deduplication and record repetition (and four ways to traverse the map)

Private Static voidcheck (string[] array) {//what are the string arrays that contain non-repeating strings? The number of each repetitionmap<string,integer> Map = new hashmap<> (); for (int i=0;i<array.length;i++) {if (Map.get (array[i]) = null) {Map.put (Array[i], Map.get ( Array[i]) + 1);//value + 1} else {map.put (array[i],1); } } //① Traversal MapSystem.out.println ("Traverse key and Value by Map.keyset ():");  for(String key:map.keySet ()) {System.out.println ("The array is:" + key + "=" +Map.get (key)); }                //②mapset (). Iterator ()SYSTEM.OUT.PRINTLN ("Traversal of key and value through Map.entryset () iterator ()"); Iterator<entry<string, integer>> it =Map.entryset (). iterator ();  while(It.hasnext ()) {Entry<string, integer> entry =It.next (); System.out.println ("The array is:" + entry.getkey () + "=" +Entry.getvalue ()); }        //③mapset () recommended when capacity is largeSystem.out.println ("Traverse key and value through Map.entryset ()");  for(Entry<string, integer>Entry:map.entrySet ()) {System.out.println ("The array is:" + entry.getkey () + "=" +Entry.getvalue ()); }                //④System.out.println ("Traverse all value through Map.values (), but cannot traverse key");  for(Integer value:map.values ()) {System.out.println ("= " +value); }          }

Array deduplication and record repetition (and four ways to traverse the map)