ASCII-to-character conversion issues in Swift

We're dealing with characters in C + +, which is usually the case

char a = ‘A‘ // A = 65printf("‘%c‘ = %d", a + 1, a + 1) // ‘B‘ = 66

This does not work in Swift, which is known to absorb all the advantages of C + +, because
Character and INT cannot be computed and will be error-

var c:Character = "A"c + 1 // 这里是错误的Xcode 会告诉你 Binary operator ‘+‘ cannot be applied to operands of type ‘Character‘ and ‘Int‘

So what's not in the textbook is a problem.

There's no internet.

But the textbook says an example has an String.unicodeScalars array of ASCII (or Unicode) values that can return a string.

So UnicodeScalar

This class was found.

The character "A" can be expressed in this way

let A = Character(UnicodeScalar(65))

It's worth 65 to be able to do so

let A_ASCII = UnicodeScalar("A") // 65

ASCII-to-character conversion issues in Swift