ASP Date and Time Function example

Function syntax example
Now now () Get the current date and time of the system dim myvar = now
''Myvar contains the current date and time.
Date () gets the current system date dim mydate = Date
''Mydate contains the current system date.
Time () gets the current system time dim mytime = Time
''Returns the current system time.
Year Year (date) gets the year dim mydate, myyear of the given date
Mydate = # October 19,196 2 #
''Assign a date.
Myyear = year (mydate)
''Myyear contains 1962.
Month (date) gets the month dim myvar = month (now) of the given date)
''Myvar contains the number corresponding to the current month.
Day (date) returns the number of the given date dim myday = Day ("October 19,196 2 ")
''Myday contains 19.
Hour hour (time) gets the hour dim mytime, myhour
Mytime = now myhour = hour (mytime)
''Myhour contains the value representing the current time.
Minute (time) gets the number of minutes dim myvar
Myvar = minute (now)
Second second (time) is the number of seconds dim mysec
Mysec = second (now)
''Mysec contains the number representing the current second.
Weekday weekday (date) gets the integer of the given date in the day of the week, 1 indicates Sunday, 2 indicates Monday, and so on dim mydate, myweekday
Mydate = # October 19,196 2 #
''Dispatch date
Myweekday = weekday (mydate)
''Myweekday contains 6, and mydate represents Friday
Datediff ("Var", var1, var2)
VaR: date or interval factor, which has the following parameters:
Yyyy, M, D, WW, week, H, S, seconds

Var1: the first date or time
Var2: The second date or time, which is later than var1 to calculate the interval of two dates or times datediff ("D", date (), #1/1/2005 #)
''Returns the number of New Year's Day 2005
Datediff ("H", date (), #1/1/2005 #)
''How many hours are there before 2005 New Year's Day?
Datediff ("D", #1/1/2003 #, #1/1/2005 #)
''Returns the number of days between two dates.
Dateadd datediff ("Var", var1, var2)
VaR: date or interval factor:
Var1: date or interval multiple
Var2: Add two dates or times as the date or time benchmark. The following example adds January 31 to the previous month:

Newdate = dateadd ("M", 1, "31-Jan-95 ")
In this example, dateadd returns February 28, instead of February 31. If date is January 31, the return value is February 29, because 1996 is a leap year.

If the calculation date is before January 1, 100 AD, an error occurs.

Formatdatetime (date, vb1_date) to short date format fromatdatetime (date (), vblongdate)
"Displayed in long Date Format
Formatdatetime (date, vblongdate) to long Date Format
Formatdatetime (date, vb1_time) is converted to the short time format
Formatdatetime (date, vblongtime) is converted to a long time format