Goffi and Median
Problem description
A median in a sequence with the length of
n
is an element which occupies position number
?n+12?
after we sort the elements in the non-decreasing order (the elements are numbered starting with 1). A median of an array (2, 6, 1, 2, 3) is the number 2, and a median of array (0, 96, 17, 23) — the number 17.
An average of a sequence is the sum of sequence divided the size of the sequence.
Goffi likes median very much and he hates average number. So if a sequence‘s average number is larger than or equal to the median of sequence, Goffi will hate the sequence. Otherwise, Goffi will like it.
Now, your are given a sequence. Please find whether Goffi will like it or hate it.
Input
Input contains multiple test cases (less than 100). For each test case, the first line contains an integer
n
(
1≤n≤1000
), indicating the size of the sequence. Then in the next line, there are
n
integers
a1,a2,…,an
(
1≤ai≤1000
), seperated by one space.
Output
For each case, if Goffi like the sequence, output "YES" in a line. Otherwise, output "NO".
Sample Input
51 2 3 4 541 5 6 6
Sample output
NOYES
Question:
Determine the maximum median and mean values of the number sequence.
Code:
#include <iostream>#include <stdio.h>#include <algorithm>#include <cmath>#include <iomanip>#include <queue>#include <stack>using namespace std;const int maxn=1010;int num[maxn];int n;int main(){ while(scanf("%d",&n)!=EOF) { double ave; double sum=0; for(int i=1;i<=n;i++) { scanf("%d",&num[i]); sum+=num[i]; } sort(num+1,num+1+n); int mid=(n+1)/2; ave=sum/n; if(ave>=num[mid]) printf("NO\n"); else printf("YES\n"); } return 0;}
[Bestcoder round #6] HDU 4981 goffi and median (water question)