Binary Tree Maximum Path Sum

Source: Internet
Author: User

Binary Tree Maximum Path Sum

Given a binary tree, find the maximum path sum.

The path may start and end at any node in the tree.

Find the maximum path from one point of the tree to another, and use the recursive method. ans are generated at the maximum of left and right subtree, root + left and right.

/*** Definition for binary tree * struct TreeNode {* int val; * TreeNode * left; * TreeNode * right; * TreeNode (int x): val (x ), left (NULL), right (NULL) {}*}; */class Solution {public: int ans; int maxPathSum (TreeNode * root) {ans = INT_MIN; travel (root); return ans;} int travel (TreeNode * root) {if (root = NULL) return 0; int sum = root-> val; int leftsum = travel (root-> left); int rightsum = tra Vel (root-> right); if (leftsum> 0) sum + = leftsum; if (rightsum> 0) sum + = rightsum; ans = max (ans, sum ); sum = max (leftsum, rightsum); return root-> val + (sum> 0? Sum: 0 );}};



Related Article

Contact Us

The content source of this page is from Internet, which doesn't represent Alibaba Cloud's opinion; products and services mentioned on that page don't have any relationship with Alibaba Cloud. If the content of the page makes you feel confusing, please write us an email, we will handle the problem within 5 days after receiving your email.

If you find any instances of plagiarism from the community, please send an email to: info-contact@alibabacloud.com and provide relevant evidence. A staff member will contact you within 5 working days.

A Free Trial That Lets You Build Big!

Start building with 50+ products and up to 12 months usage for Elastic Compute Service

  • Sales Support

    1 on 1 presale consultation

  • After-Sales Support

    24/7 Technical Support 6 Free Tickets per Quarter Faster Response

  • Alibaba Cloud offers highly flexible support services tailored to meet your exact needs.