Bubble Sort algorithm

Source: Internet
Author: User
Tags for in range

Li = [33,2,1,10] for in range (Len (LI)-1)://Because range (4) is 0 1 2 3 (not including 4) when i= 3 o'clock Next_ Value does not        exist if li[i] >li[i + 1]        := li[i        ]= li[i + 1]        li[i +1] = tempprint (LI)//put the largest to the last

The first time the operation. After each operation put Len (LI)-1-1

Therefore, these operations can be replaced by a loop outside:

 for  in range (1, Len (LI)):    is in range (Len (LI)- j):         if li[ I] > li[i+1]:            = Li[i]            = li[i+1]            li[[i+1] = temp  Print (LI)

Bubble Sort algorithm

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