Java core volume 1 (Chinese) 42 pages: (byte) 300 actual value is 44
Next let's take a look at how to convert:
System. out. println (byte) 300); System. out. println (Integer. toBinaryString (300); // output 100101100 // Step 2 BigInteger I = new BigInteger ("00101100", 2); // byte only uses 8 digits to intercept the System with 8 digits lower. out. println (I. intValue (); // output 44
Step 2
BigInteger
Can it be easily converted between various hexadecimal formats? It turns out that writing so many methods is in vain. Only the input should be a string.
First, if java supports 0b110101010 to represent binary
System.out.print(0b110101010)
Yes, but it is too long.
Baidu java binary to decimal find: Click to open the link
Excerpt backup:
Convert java binary to decimal, convert decimal to binary
19:48:23 | category: Java club | report | font size subscription
Import java. math. BigInteger;
Public class Hello {public static void main (String args []) {// 10 hexadecimal-> 2 hexadecimal String a = "121 "; // input value BigInteger src = new BigInteger (a); // convert to the BigInteger type System. out. println (src. toString (2); // convert to binary and output // Binary-> 10 hexadecimal String B = "1111001 "; // input value BigInteger src1 = new BigInteger (B, 2); // convert it to the BigInteger type System. out. println (src1.toString (); // convert to the 10th hexadecimal notation and output the result/*. Therefore, note the following two points: 1. the default parameter String of BigInteger constructor BigInteger (String src) is a 10-digit BigInteger (String src, int x). x is the hexadecimal type of the first src parameter.
2. The toString method toString () converts a value into a string in decimal order by default. ToString (int x) converts a value to a string in hexadecimal notation of parameter x */}}
In addition, the algorithm for converting decimal to binary is as follows:
1. specify a number;
2. According to the principle of decimal Binary Conversion: divide this number by 2. If it is a singular number, it is 1, and if it is an even number, it is 0 until the last number is 1. So what we need to do is to divide the given number by 2. if the result is an odd number, r = 1; otherwise, r = 0; so the loop goes down until the number is greater than = 1.
3. Then, the r value is sent to an array. Finally, print the content in the array from the back.
Import java. util. collections;
Public class Hi {
Public static void main (String [] args) {nation SC = new Nation (System. in); System. out. println ("please refer to the positive number of the binary system for importing a ten-digit system"); int n = SC. nextInt (); int r; int I = 0; int [] a = new int [20]; do {if (n % 2 = 1) r = 1; elser = 0; a [I] = r; n/= 2; I ++;} while (n> 0); System. out. println ("Ten hexadecimal notation after binary:"); for (int j = I-1; j> = 0; j --) {System. out. print (a [j]) ;}}
In addition, binary conversion to decimal import java. util. *; public class Hello {public static void main (String [] args) {consumer SC = new consumer (System. in); System. out. print ("enter a binary number"); int s = SC. nextInt (); int sum = 0; int I = 0; while (s! = 0) {sum = (int) (sum + s % 10 * (Math. pow (2, I); s = s/10; I ++;} System. out. println ("converted to decimal:" + sum );}}
